Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.PharmacologyMedium
Which drug is the antidote for an opioid overdose?
AFlumazenil
BAcetylcysteine
CNaloxone
DAtropine
2.PharmacologyHard
A patient taking digoxin has nausea, yellow-green vision and a dangerous arrhythmia. Which specific treatment can bind the drug?
AProtamine sulfate
BFlumazenil
CIntravenous vitamin K (phytomenadione) given slowly
DDigoxin immune Fab (antibody fragments)
3.Dosage calculationsMedium
A vial contains 2 g of powder. The label says: add 9.2 mL of water for injection to give a total volume of 10 mL. The prescription is 240 mg. What volume V of the reconstituted solution do you give?
2 g+ 9.2 mL → 10 mL240 mg
V = mL
4.Dosage calculationsHard
A child weighing 24 kg is prescribed 5 mg/kg per dose of an oral suspension that contains 120 mg in 5 mL. What volume V do you give?
24 kg5 mg/kg120 mg/5 mL
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). A 96 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 20 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.
96 kgVd = 0.7 L/kgC = 20 mg/LS = 0.92
LD = mg
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 98 kg patient on regular tobramycin doses is at steady state. The target is a peak of 6 mg/L and a trough of 0.5 mg/L, and the volume of distribution is 0.25 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?
Naloxone reverses opioid-induced respiratory depression. Flumazenil reverses benzodiazepines, acetylcysteine treats paracetamol overdose and atropine treats bradycardia or organophosphate poisoning.
Answer
C · Naloxone
2.Pharmacology
Answer: D · Digoxin immune Fab (antibody fragments)
Why this is the answer
Digoxin immune Fab binds digoxin in the blood and makes it inactive. It is used for life-threatening toxicity, such as serious arrhythmias or severe hyperkalaemia.
Answer
D · Digoxin immune Fab (antibody fragments)
3.Dosage calculations
Answer: V = 1.2 mL
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Concentration after mixing
2000 mg/10 mL = 200 mg/mL
Volume
V = 240/200 = 1.2 mL
Answer
V = 1.2 mL
4.Dosage calculations
Answer: V = 5 mL
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Dose from weight
5·24 = 120 mg
Volume
V = (120/120)·5 = 5 mL
Answer
V = 5 mL
5.Clinical pharmacokinetics
Answer: LD = 1461 mg
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 0.7·96 = 67.2 L
Amount of active drug needed
Vd·C = 67.2·20 = 1344 mg
Loading dose
LD = 1344/(0.92·1) = 1461 mg
Answer
LD = 1461 mg
In practice the dose is rounded to a convenient amount.
6.Clinical pharmacokinetics
Answer: D = 134.8 mg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 0.25·98 = 24.5 L
Dose
D = 24.5·(6 − 0.5) = 134.8 mg
Answer
D = 134.8 mg
In practice the dose is rounded to a convenient amount.