Pharmacology: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.PharmacologyMedium

Which assessments are most important during a magnesium sulfate infusion?

  1. ABlood glucose, pupil size and pupil reaction to light
  2. BTemperature and skin colour only
  3. CBowel sounds and appetite
  4. DDeep tendon reflexes, respiratory rate and urine output
2.PharmacologyHard

A patient taking sertraline starts St John's wort for low mood. What is the main concern?

  1. AA hypertensive crisis from tyramine
  2. BSerotonin syndrome from combined serotonergic effects
  3. CBleeding from vitamin K deficiency
  4. DSevere low blood pressure from blocked alpha receptors
3.Dosage calculationsMedium
12 kg5 mg/kg/day3× per dayD = ? mg

A patient weighs 12 kg. The prescribed dose is 5 mg/kg per day, given in 3 equal doses. How many milligrams D are given per dose?

12 kg5 mg/kg/day3× per day
D = mg
4.Dosage calculationsHard
40 mg/1 mLV = ? mL

A child weighing 10 kg is prescribed 5 mg/kg per dose of an oral suspension that contains 40 mg in 1 mL. What volume V do you give? Round to one decimal place.

10 kg5 mg/kg40 mg/1 mL
V = mL
5.Clinical pharmacokineticsMedium
110100t (h)C (mg/L)1 h10 mg/L4 h3.5 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 10 mg/L at 1 h and 3.5 mg/L at 4 h. Assume first-order elimination. Find the elimination rate constant k.

C1 = 10 mg/L (1 h)C2 = 3.5 mg/L (4 h)
k = h⁻¹
6.Clinical pharmacokineticsHard
62 kg48 · manSCr 3.2 mg/dLCrCl → τ = ? h

Practice exercise (made-up values, not clinical guidance). A 48-year-old man weighs 62 kg and has a serum creatinine of 3.2 mg/dL (283 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual tobramycin regimen is 120 mg every 8 h for a creatinine clearance of 100 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.

48 years62 kgmanSCr = 3.2 mg/dL120 mg q8hCrCl normal 100 mL/min
τ = h

3Solutions

1.Pharmacology

Answer: D · Deep tendon reflexes, respiratory rate and urine output

Why this is the answer

Loss of reflexes is an early sign of magnesium toxicity, followed by respiratory depression and cardiac arrest. Low urine output allows magnesium to accumulate.

Answer

D · Deep tendon reflexes, respiratory rate and urine output
2.Pharmacology

Answer: B · Serotonin syndrome from combined serotonergic effects

Why this is the answer

St John's wort has serotonergic effects, so it can cause serotonin syndrome with SSRIs. It also induces liver enzymes and can reduce levels of drugs such as the combined pill, warfarin and ciclosporin.

Answer

B · Serotonin syndrome from combined serotonergic effects
3.Dosage calculations

Answer: D = 20 mg

Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.

Total per day

5·12 = 60 mg

Per dose

D = 60/3 = 20 mg

Answer

D = 20 mg
4.Dosage calculations

Answer: V = 1.3 mL

Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.

Dose from weight

5·10 = 50 mg

Volume

V = (50/40)·1 = 1.25 ≈ 1.3 mL

Answer

V = 1.3 mL
5.Clinical pharmacokinetics

Answer: k = 0.3499 h⁻¹

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Elimination rate constant

k = ln(10/3.5)/3 = 1.05/3 = 0.3499 h⁻¹

Answer

k = 0.3499 h⁻¹
6.Clinical pharmacokinetics

Answer: τ = 32.3 h

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Creatinine clearance (Cockcroft–Gault)

CrCl = (140 − 48)·62/(72·3.2) = 24.76 mL/min

New interval

τ = 8·100/24.76 = 32.31 ≈ 32.3 h

Answer

τ = 32.3 h

In practice the interval is rounded to a convenient value such as 12, 24, 36 or 48 h.

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