Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.PharmacologyMedium
Which assessments are most important during a magnesium sulfate infusion?
ABlood glucose, pupil size and pupil reaction to light
BTemperature and skin colour only
CBowel sounds and appetite
DDeep tendon reflexes, respiratory rate and urine output
2.PharmacologyHard
A patient taking sertraline starts St John's wort for low mood. What is the main concern?
AA hypertensive crisis from tyramine
BSerotonin syndrome from combined serotonergic effects
CBleeding from vitamin K deficiency
DSevere low blood pressure from blocked alpha receptors
3.Dosage calculationsMedium
A patient weighs 12 kg. The prescribed dose is 5 mg/kg per day, given in 3 equal doses. How many milligrams D are given per dose?
12 kg5 mg/kg/day3× per day
D = mg
4.Dosage calculationsHard
A child weighing 10 kg is prescribed 5 mg/kg per dose of an oral suspension that contains 40 mg in 1 mL. What volume V do you give? Round to one decimal place.
10 kg5 mg/kg40 mg/1 mL
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 10 mg/L at 1 h and 3.5 mg/L at 4 h. Assume first-order elimination. Find the elimination rate constant k.
C1 = 10 mg/L (1 h)C2 = 3.5 mg/L (4 h)
k = h⁻¹
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 48-year-old man weighs 62 kg and has a serum creatinine of 3.2 mg/dL (283 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual tobramycin regimen is 120 mg every 8 h for a creatinine clearance of 100 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.
Answer: D · Deep tendon reflexes, respiratory rate and urine output
Why this is the answer
Loss of reflexes is an early sign of magnesium toxicity, followed by respiratory depression and cardiac arrest. Low urine output allows magnesium to accumulate.
Answer
D · Deep tendon reflexes, respiratory rate and urine output
2.Pharmacology
Answer: B · Serotonin syndrome from combined serotonergic effects
Why this is the answer
St John's wort has serotonergic effects, so it can cause serotonin syndrome with SSRIs. It also induces liver enzymes and can reduce levels of drugs such as the combined pill, warfarin and ciclosporin.
Answer
B · Serotonin syndrome from combined serotonergic effects
3.Dosage calculations
Answer: D = 20 mg
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Total per day
5·12 = 60 mg
Per dose
D = 60/3 = 20 mg
Answer
D = 20 mg
4.Dosage calculations
Answer: V = 1.3 mL
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Dose from weight
5·10 = 50 mg
Volume
V = (50/40)·1 = 1.25 ≈ 1.3 mL
Answer
V = 1.3 mL
5.Clinical pharmacokinetics
Answer: k = 0.3499 h⁻¹
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(10/3.5)/3 = 1.05/3 = 0.3499 h⁻¹
Answer
k = 0.3499 h⁻¹
6.Clinical pharmacokinetics
Answer: τ = 32.3 h
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Creatinine clearance (Cockcroft–Gault)
CrCl = (140 − 48)·62/(72·3.2) = 24.76 mL/min
New interval
τ = 8·100/24.76 = 32.31 ≈ 32.3 h
Answer
τ = 32.3 h
In practice the interval is rounded to a convenient value such as 12, 24, 36 or 48 h.