Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.PharmacologyMedium
Why is a progestogen added to oestrogen in hormone replacement therapy for a woman who still has her uterus?
ATo reduce hot flushes much more than oestrogen alone can
BTo protect against endometrial hyperplasia and cancer
CTo lower the risk of blood clots to zero
DTo prevent breast cancer completely
2.PharmacologyHard
A patient on digoxin and furosemide develops nausea, visual disturbances and an irregular pulse. Which electrolyte disturbance most likely made digoxin toxicity more likely?
AHyperkalaemia
BHypernatraemia
CHypocalcaemia
DHypokalaemia
3.Dosage calculationsMedium
A patient weighing 72 kg has a body surface area of 1.68 m². The prescription is 250 mg/m². Find the dose D in mg.
72 kgBSA = 1.68 m²250 mg/m²
D = mg
4.Dosage calculationsHard
An infusion contains 50000 units of a drug in 1000 mL. The prescription is 500 units per hour. At what rate R do you set the pump, in mL/h?
50000 units/1000 mL500 units/h
R = mL/h
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 7 mg/L at 1 h and 2.8 mg/L at 5 h. Assume first-order elimination. Find the half-life t½.
C1 = 7 mg/L (1 h)C2 = 2.8 mg/L (5 h)
t½ = h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 3 L/h. What dose D in mg gives an average steady-state level of 25 mg/L?
CL = 3 L/hτ = 12 hS = 1F = 1Css,avg = 25 mg/L
D = mg
3Solutions
1.Pharmacology
Answer: B · To protect against endometrial hyperplasia and cancer
Why this is the answer
Oestrogen alone causes endometrial proliferation and increases the risk of endometrial cancer. A progestogen protects the endometrium; women without a uterus can take oestrogen alone.
Answer
B · To protect against endometrial hyperplasia and cancer
2.Pharmacology
Answer: D · Hypokalaemia
Why this is the answer
Digoxin binds the Na⁺/K⁺-ATPase at the same site as potassium. Low potassium, often caused by loop or thiazide diuretics, increases digoxin binding and toxicity.
Answer
D · Hypokalaemia
3.Dosage calculations
Answer: D = 420 mg
Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).
Dose
D = 250·1.68 = 420 mg
Answer
D = 420 mg
4.Dosage calculations
Answer: R = 10 mL/h
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Concentration
50000/1000 = 50 units/mL
Pump rate
R = 500/50 = 10 mL/h
Answer
R = 10 mL/h
5.Clinical pharmacokinetics
Answer: t½ = 3.026 h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(7/2.8)/4 = 0.9163/4 = 0.2291 h⁻¹
Half-life
t½ = 0.693/0.2291 = 3.026 h
Answer
t½ = 3.026 h
6.Clinical pharmacokinetics
Answer: D = 900 mg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.