Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.PharmacologyMedium
Macrolides such as clarithromycin act by:
AInhibiting cell wall synthesis
BBlocking folic acid synthesis
CInhibiting DNA gyrase
DBinding the 50S ribosomal subunit to inhibit protein synthesis
2.PharmacologyHard
A patient with severe chronic hyponatraemia receives hypertonic saline. Why is the rate of correction strictly limited?
ARaising sodium too fast causes severe hypokalaemia and cardiac arrest
BFast correction causes immediate kidney failure
CRaising sodium too fast can cause osmotic demyelination in the brain
DHypertonic saline is toxic to the liver at high rates
3.Dosage calculationsMedium
A dose of 500 mg is needed from a 5% (w/v) solution. What volume V contains this dose?
500 mg5% w/v
V = mL
4.Dosage calculationsHard
The prescription is 4350 units of a drug that comes as 5000 units/mL. Draw up the dose in the 1 mL syringe: what volume V do you give?
4350 units5000 units/mL
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). A 70 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.
70 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 55-year-old woman weighs 91 kg and has a serum creatinine of 3.3 mg/dL (292 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual gentamicin regimen is 80 mg every 8 h for a creatinine clearance of 120 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.
Answer: D · Binding the 50S ribosomal subunit to inhibit protein synthesis
Why this is the answer
Macrolides bind the 50S subunit of the bacterial ribosome and block protein synthesis. Fluoroquinolones inhibit DNA gyrase and beta-lactams the cell wall.
Answer
D · Binding the 50S ribosomal subunit to inhibit protein synthesis
2.Pharmacology
Answer: C · Raising sodium too fast can cause osmotic demyelination in the brain
Why this is the answer
In chronic hyponatraemia the brain adapts to low osmolality. Correcting sodium too rapidly shrinks brain cells and can cause osmotic demyelination (central pontine myelinolysis), so sodium is checked often.
Answer
C · Raising sodium too fast can cause osmotic demyelination in the brain
3.Dosage calculations
Answer: V = 10 mL
Solution strengths: a percentage strength is grams per 100 mL, so 1% = 1 g/100 mL = 10 mg/mL. A ratio strength 1:1000 means 1 g in 1000 mL = 1 mg/mL; 1:10 000 is 0.1 mg/mL. For a dilution the amount of drug stays the same: C₁·V₁ = C₂·V₂.
Concentration
5% = 50 mg/mL
Volume
V = 500/50 = 10 mL
Answer
V = 10 mL
4.Dosage calculations
Answer: V = 0.87 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Volume
V = 4350/5000 = 0.87 mL
On the syringe
On this 1 mL syringe every small line is 0.01 mL.
Answer
V = 0.87 mL
5.Clinical pharmacokinetics
Answer: LD = 798.9 mg
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 0.7·70 = 49 L
Amount of active drug needed
Vd·C = 49·15 = 735 mg
Loading dose
LD = 735/(0.92·1) = 798.9 mg
Answer
LD = 798.9 mg
In practice the dose is rounded to a convenient amount.
6.Clinical pharmacokinetics
Answer: τ = 34.7 h
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Creatinine clearance (Cockcroft–Gault)
CrCl = (140 − 55)·91/(72·3.3)·0.85 = 27.67 mL/min
New interval
τ = 8·120/27.67 = 34.69 ≈ 34.7 h
Answer
τ = 34.7 h
In practice the interval is rounded to a convenient value such as 12, 24, 36 or 48 h.