Pharmacology: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.PharmacologyMedium

Which assessment is most important before giving a dose of IV morphine?

  1. ABlood glucose and temperature, checked before each dose
  2. BBowel sounds and urine colour
  3. CPupil size and hearing
  4. DRespiratory rate and level of sedation
2.PharmacologyHard

Which property makes a drug more likely to cross the blood–brain barrier?

  1. APositive charge at physiological pH
  2. BHigh lipid solubility and small size
  3. CLarge molecular weight and strong protein binding
  4. DHigh water solubility and strong ionisation
3.Dosage calculationsMedium
024681010 mL

A child weighing 12 kg is prescribed 7.5 mg/kg of a drug. The stock solution contains 50 mg/mL. Draw up the dose: what volume V do you give?

12 kg7.5 mg/kg50 mg/mL
V = mL
4.Dosage calculationsHard
40k units1000 mL? mL/h800 units/h

An infusion contains 40000 units of a drug in 1000 mL. The prescription is 800 units per hour. At what rate R do you set the pump, in mL/h?

40000 units/1000 mL800 units/h
R = mL/h
5.Clinical pharmacokineticsMedium
VCss​ = 10 mg/LR = ? mg/hCL = 0.035 L/kg/h68 kg

Practice exercise (made-up values, not clinical guidance). A 68 kg patient receives a theophylline infusion. The clearance is 0.035 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 10 mg/L?

68 kgCL = 0.035 L/kg/hCss = 10 mg/L
R = mg/h
6.Clinical pharmacokineticsHard
Vd = 0.3 L/kg0.5 → 6 mg/LD = ? mg94 kg

Practice exercise (made-up values, not clinical guidance). A 94 kg patient on regular gentamicin doses is at steady state. The target is a peak of 6 mg/L and a trough of 0.5 mg/L, and the volume of distribution is 0.3 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

94 kgVd = 0.3 L/kgCpeak = 6 mg/LCtrough = 0.5 mg/L
D = mg

3Solutions

1.Pharmacology

Answer: D · Respiratory rate and level of sedation

Why this is the answer

Opioids can cause respiratory depression, which is usually preceded by increasing sedation. Both are checked before and after each dose.

Answer

D · Respiratory rate and level of sedation
2.Pharmacology

Answer: B · High lipid solubility and small size

Why this is the answer

Small, lipophilic, non-ionised molecules diffuse across endothelial cell membranes. Charged or large, protein-bound drugs mostly stay out.

Answer

B · High lipid solubility and small size
3.Dosage calculations

Answer: V = 1.8 mL

Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.

Dose from body weight

D = 7.5·12 = 90 mg

Volume

V = 90/50 = 1.8 mL

On the syringe

On this 10 mL syringe every small line is 0.2 mL.

Answer

V = 1.8 mL
4.Dosage calculations

Answer: R = 20 mL/h

Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.

Concentration

40000/1000 = 40 units/mL

Pump rate

R = 800/40 = 20 mL/h

Answer

R = 20 mL/h
5.Clinical pharmacokinetics

Answer: R = 23.8 mg/h

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Clearance

CL = 0.035·68 = 2.38 L/h

Infusion rate

R = 2.38·10 = 23.8 mg/h

Answer

R = 23.8 mg/h
6.Clinical pharmacokinetics

Answer: D = 155.1 mg

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Volume of distribution

Vd = 0.3·94 = 28.2 L

Dose

D = 28.2·(6 − 0.5) = 155.1 mg

Answer

D = 155.1 mg

In practice the dose is rounded to a convenient amount.

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