Pharmacology: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.PharmacologyMedium

Why are benzodiazepines used with great caution in older people?

  1. AThey are not absorbed from the gut after age 65
  2. BThey cause permanent hearing loss in older people
  3. CThey cause severe high blood pressure in older people
  4. DThey raise the risk of confusion, falls and fractures
2.PharmacologyHard

A woman has received a high-dose oxytocin infusion with large volumes of hypotonic fluid for many hours. She now has a headache, confusion and a low serum sodium. What is the most likely cause?

  1. AWater intoxication from the antidiuretic effect of oxytocin
  2. BNormal tiredness after a long labour
  3. CExcessive salt in the infusion fluid
  4. DAn allergic reaction to oxytocin causing brain swelling
3.Dosage calculationsMedium
15 kg7.5 mg/kg/day2× per dayD = ? mg

A patient weighs 15 kg. The prescribed dose is 7.5 mg/kg per day, given in 2 equal doses. How many milligrams D are given per dose?

15 kg7.5 mg/kg/day2× per day
D = mg
4.Dosage calculationsHard
00.10.20.30.40.50.60.70.80.911 mL

The prescription is 3350 units of a drug that comes as 5000 units/mL. Draw up the dose in the 1 mL syringe: what volume V do you give?

3350 units5000 units/mL
V = mL
5.Clinical pharmacokineticsMedium
110100t (h)C (mg/L)1 h30 mg/L17 h9.9 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 30 mg/L at 1 h and 9.9 mg/L at 17 h. Assume first-order elimination. Find the elimination rate constant k.

C1 = 30 mg/L (1 h)C2 = 9.9 mg/L (17 h)
k = h⁻¹
6.Clinical pharmacokineticsHard
Vd = 0.3 L/kg0.5 → 8 mg/LD = ? mg56 kg

Practice exercise (made-up values, not clinical guidance). A 56 kg patient on regular gentamicin doses is at steady state. The target is a peak of 8 mg/L and a trough of 0.5 mg/L, and the volume of distribution is 0.3 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

56 kgVd = 0.3 L/kgCpeak = 8 mg/LCtrough = 0.5 mg/L
D = mg

3Solutions

1.Pharmacology

Answer: D · They raise the risk of confusion, falls and fractures

Why this is the answer

Older people are more sensitive to benzodiazepines and often eliminate them more slowly. Sedation, unsteadiness and confusion raise the risk of falls and fractures.

Answer

D · They raise the risk of confusion, falls and fractures
2.Pharmacology

Answer: A · Water intoxication from the antidiuretic effect of oxytocin

Why this is the answer

Oxytocin has antidiuretic activity at high doses. With large volumes of fluid this can cause water retention and dilutional hyponatraemia, so fluid balance and sodium are monitored.

Answer

A · Water intoxication from the antidiuretic effect of oxytocin
3.Dosage calculations

Answer: D = 56.25 mg

Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.

Total per day

7.5·15 = 112.5 mg

Per dose

D = 112.5/2 = 56.25 mg

Answer

D = 56.25 mg
4.Dosage calculations

Answer: V = 0.67 mL

Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.

Volume

V = 3350/5000 = 0.67 mL

On the syringe

On this 1 mL syringe every small line is 0.01 mL.

Answer

V = 0.67 mL
5.Clinical pharmacokinetics

Answer: k = 0.06929 h⁻¹

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Elimination rate constant

k = ln(30/9.9)/16 = 1.109/16 = 0.06929 h⁻¹

Answer

k = 0.06929 h⁻¹
6.Clinical pharmacokinetics

Answer: D = 126 mg

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Volume of distribution

Vd = 0.3·56 = 16.8 L

Dose

D = 16.8·(8 − 0.5) = 126 mg

Answer

D = 126 mg

In practice the dose is rounded to a convenient amount.

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