Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
A solution has a ratio strength of 1:1000. You need 0.46 mg. Draw up the volume in the 1 mL syringe: what volume V is that?
1:10000.46 mg
V = mL
2.Pharmacy calculationsHard
A vial holds 2000 mg of powder. You add 4.2 mL of diluent, and the powder adds 0.8 mL of volume. The prescription is 1600 mg. Draw up the dose: what volume V do you give?
2000 mg4.2 mL + 0.8 mL1600 mg
V = mL
3.Dosage calculationsMedium
A patient weighs 18 kg. The prescribed dose is 25 mg/kg per day, given in 2 equal doses. How many milligrams D are given per dose?
18 kg25 mg/kg/day2× per day
D = mg
4.Dosage calculationsHard
You must prepare 1000 mL of a 1% (w/v) solution from a 10% (w/v) stock solution. What volume of stock V₁ do you need?
C₁ = 10%C₂ = 1%V₂ = 1000 mL
V₁ = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 6 mg/L at 1 h and 3.4 mg/L at 3 h. Assume first-order elimination. Find the half-life t½.
C1 = 6 mg/L (1 h)C2 = 3.4 mg/L (3 h)
t½ = h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 24 mg/h with no loading dose. The patient's clearance is 2 L/h and the half-life is 8 h. What is the level C after 7 h?
R = 24 mg/hCL = 2 L/ht½ = 8 ht = 7 h
C = mg/L
3Solutions
1.Pharmacy calculations
Answer: V = 0.46 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Strength in mg/mL
1000 mg/1000 mL = 1 mg/mL
Volume
V = 0.46/1 = 0.46 mL
Answer
V = 0.46 mL
2.Pharmacy calculations
Answer: V = 4 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Final volume and concentration
4.2 + 0.8 = 5 mL
C = 2000/5 = 400 mg/mL
Volume
V = 1600/400 = 4 mL
Answer
V = 4 mL
3.Dosage calculations
Answer: D = 225 mg
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Total per day
25·18 = 450 mg
Per dose
D = 450/2 = 225 mg
Answer
D = 225 mg
4.Dosage calculations
Answer: V₁ = 100 mL
Solution strengths: a percentage strength is grams per 100 mL, so 1% = 1 g/100 mL = 10 mg/mL. A ratio strength 1:1000 means 1 g in 1000 mL = 1 mg/mL; 1:10 000 is 0.1 mg/mL. For a dilution the amount of drug stays the same: C₁·V₁ = C₂·V₂.
Volume of stock
V₁ = 1·1000/10 = 100 mL
Answer
V₁ = 100 mL
5.Clinical pharmacokinetics
Answer: t½ = 2.441 h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(6/3.4)/2 = 0.568/2 = 0.284 h⁻¹
Half-life
t½ = 0.693/0.284 = 2.441 h
Answer
t½ = 2.441 h
6.Clinical pharmacokinetics
Answer: C = 5.457 mg/L
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.