Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
A solution has a ratio strength of 1:10 000. You need 0.2 mg. Draw up the volume in the 10 mL syringe: what volume V is that?
1:10 0000.2 mg
V = mL
2.Pharmacy calculationsHard
Practice exercise (made-up values, not clinical guidance). You have 200 g of 10% salicylic acid ointment. How many grams m of 2% salicylic acid ointment must you add to make a 4% ointment? Round to the nearest whole gram.
200 g · 10%2%4%
m = g
3.Dosage calculationsMedium
A child weighing 16 kg is prescribed 5 mg/kg of a drug. The stock solution contains 10 mg/mL. Draw up the dose: what volume V do you give?
16 kg5 mg/kg10 mg/mL
V = mL
4.Dosage calculationsHard
A patient weighs 72.6 lb. The prescription is 15 mg/kg as a single dose, and the stock contains 250 mg in 5 mL. Using 1 kg = 2.2 lb, what volume V do you give?
72.6 lb15 mg/kg250 mg/5 mL1 kg = 2.2 lb
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). A patient has a lidocaine clearance of 850 mL/min. What infusion rate R in mg/min keeps the steady-state level at 2 mg/L?
CL = 850 mL/minCss = 2 mg/L
R = mg/min
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 52.5 mg/h with no loading dose. The patient's clearance is 3.5 L/h and the half-life is 6 h. What is the level C after 16 h?
R = 52.5 mg/hCL = 3.5 L/ht½ = 6 ht = 16 h
C = mg/L
3Solutions
1.Pharmacy calculations
Answer: V = 2 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Strength in mg/mL
1000 mg/10 000 mL = 0.1 mg/mL
Volume
V = 0.2/0.1 = 2 mL
Answer
V = 2 mL
2.Pharmacy calculations
Answer: m = 600 g
Alligation: to mix a higher strength H and a lower strength L into a target strength T, take (T − L) parts of H and (H − T) parts of L. The parts are crossed: each stock gets the distance from the target to the other stock. Water or a plain base counts as 0%. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Alligation parts
10%: 4 − 2 = 2 parts
2%: 10 − 4 = 6 parts
Scale to the amount you have
m = 200·6/2 = 600 g
Answer
m = 600 g
Check: 200 g + 600 g = 800 g of 4% ointment.
3.Dosage calculations
Answer: V = 8 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Dose from body weight
D = 5·16 = 80 mg
Volume
V = 80/10 = 8 mL
On the syringe
On this 10 mL syringe every small line is 0.2 mL.
Answer
V = 8 mL
4.Dosage calculations
Answer: V = 9.9 mL
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Weight in kg
72.6/2.2 = 33 kg
Dose
15·33 = 495 mg
Volume
V = (495/250)·5 = 9.9 mL
Answer
V = 9.9 mL
5.Clinical pharmacokinetics
Answer: R = 1.7 mg/min
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Clearance in L/min
850 mL/min = 0.85 L/min
Infusion rate
R = 0.85·2 = 1.7 mg/min
Answer
R = 1.7 mg/min
6.Clinical pharmacokinetics
Answer: C = 12.64 mg/L
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.