Pharmacy Calculations: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

Pharmacy calculations

Percentage strength
% w/v = g per 100 mL
Amount in a solution
g = % × mL / 100
Ratio strength
1:X = 1 g in X mL; % = 100 / X
Reconstitution
final volume = diluent + powder volume
Concentration
mg/mL = drug in vial / final volume
Alligation
parts of H = T − L, parts of L = H − T
Water or base
0%

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.Pharmacy calculationsMedium
ceftriaxone 2 gAdd 19.2 mL sterile water.Powder volume: 0.8 mL.? mg/mL

Practice exercise (made-up values, not clinical guidance). A vial contains ceftriaxone 2000 mg as a powder. The practice label says to add 19.2 mL of sterile water; the powder adds 0.8 mL to the volume. What is the concentration C in mg/mL after reconstitution?

2000 mg19.2 mL+0.8 mL
C = mg/mL
2.Pharmacy calculationsHard
0123455 mL

A vial holds 500 mg of powder. You add 9.6 mL of diluent, and the powder adds 0.4 mL of volume. The prescription is 200 mg. Draw up the dose: what volume V do you give?

500 mg9.6 mL + 0.4 mL200 mg
V = mL
3.Dosage calculationsMedium
30 kgBSA = 0.96 m²100 mg/m²D = ? mg

A patient weighing 30 kg has a body surface area of 0.96 m². The prescription is 100 mg/m². Find the dose D in mg.

30 kgBSA = 0.96 m²100 mg/m²
D = mg
4.Dosage calculationsHard
50%stockwater = ? mL

You must prepare 250 mL of a 5% (w/v) solution from a 50% (w/v) stock solution. How much water W must be added to the stock?

C₁ = 50%C₂ = 5%V₂ = 250 mL
W = mL
5.Clinical pharmacokineticsMedium
Vd = 0.5 L/kgC = 15 mg/LLD = ? mg100 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 100 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 15 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

100 kgVd = 0.5 L/kgC = 15 mg/LS = 0.8
LD = mg
6.Clinical pharmacokineticsHard
VCss,avg​ = ?250 mg · q8hCL = 0.045 L/kg/h51 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 51 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.045 L/kg/h. Each dose is 250 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.045 L/kg/hτ = 8 hS = 1F = 151 kgD = 250 mg
Css,avg = mg/L

3Solutions

1.Pharmacy calculations

Answer: C = 100 mg/mL

Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Final volume

19.2 + 0.8 = 20 mL

Concentration

C = 2000/20 = 100 mg/mL

Answer

C = 100 mg/mL
2.Pharmacy calculations

Answer: V = 4 mL

Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.

Final volume and concentration

9.6 + 0.4 = 10 mL
C = 500/10 = 50 mg/mL

Volume

V = 200/50 = 4 mL

Answer

V = 4 mL
3.Dosage calculations

Answer: D = 96 mg

Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).

Dose

D = 100·0.96 = 96 mg

Answer

D = 96 mg
4.Dosage calculations

Answer: W = 225 mL

Solution strengths: a percentage strength is grams per 100 mL, so 1% = 1 g/100 mL = 10 mg/mL. A ratio strength 1:1000 means 1 g in 1000 mL = 1 mg/mL; 1:10 000 is 0.1 mg/mL. For a dilution the amount of drug stays the same: C₁·V₁ = C₂·V₂.

Volume of stock

V₁ = 5·250/50 = 25 mL

Water to add

W = 250 − 25 = 225 mL

Answer

W = 225 mL
5.Clinical pharmacokinetics

Answer: LD = 937.5 mg

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Volume of distribution

Vd = 0.5·100 = 50 L

Amount of active drug needed

Vd·C = 50·15 = 750 mg

Loading dose

LD = 750/(0.8·1) = 937.5 mg

Answer

LD = 937.5 mg

In practice the dose is rounded to a convenient amount.

6.Clinical pharmacokinetics

Answer: Css,avg = 13.62 mg/L

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Clearance

CL = 0.045·51 = 2.295 L/h

Average steady-state level

Css,avg = S·F·D/(CL·τ) = 1·1·250/(2.295·8) = 13.62 mg/L

Answer

Css,avg = 13.62 mg/L

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