Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
A solution has a ratio strength of 1:10 000. You need 0.64 mg. Draw up the volume in the 10 mL syringe: what volume V is that?
1:10 0000.64 mg
V = mL
2.Pharmacy calculationsHard
A vial holds 500 mg of powder. You add 3.6 mL of diluent, and the powder adds 0.4 mL of volume. The prescription is 350 mg. Draw up the dose: what volume V do you give?
500 mg3.6 mL + 0.4 mL350 mg
V = mL
3.Dosage calculationsMedium
A patient weighs 12 kg and is prescribed 15 mg/kg as a single dose. Find the dose D in mg.
12 kg15 mg/kg
D = mg
4.Dosage calculationsHard
The prescription is 0.5 mg. The ampoule contains 2000 micrograms per mL. Draw up the dose in the 1 mL syringe: what volume V do you give?
0.5 mg2000 mcg/mL
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 150 mg of gentamicin. The level back-extrapolated to time zero is 7 mg/L and the half-life is 3.5 h. Find the clearance CL in L/h.
D = 150 mgC₀ = 7 mg/Lt½ = 3.5 h
CL = L/h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). An 88 kg patient takes oral aminophylline (S = 0.8, F = 1) every 12 h. The theophylline clearance is 0.045 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Strength in mg/mL
1000 mg/10 000 mL = 0.1 mg/mL
Volume
V = 0.64/0.1 = 6.4 mL
Answer
V = 6.4 mL
2.Pharmacy calculations
Answer: V = 2.8 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Final volume and concentration
3.6 + 0.4 = 4 mL
C = 500/4 = 125 mg/mL
Volume
V = 350/125 = 2.8 mL
Answer
V = 2.8 mL
3.Dosage calculations
Answer: D = 180 mg
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Dose
15·12 = 180 mg
Answer
D = 180 mg
4.Dosage calculations
Answer: V = 0.25 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Same units
0.5 mg = 500 mcg
Volume
V = 500/2000 = 0.25 mL
Answer
V = 0.25 mL
5.Clinical pharmacokinetics
Answer: CL = 4.244 L/h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 150/7 = 21.43 L
Rate constant
k = 0.693/3.5 = 0.198 h⁻¹
Clearance
CL = 0.198·21.43 = 4.244 L/h
Answer
CL = 4.244 L/h
6.Clinical pharmacokinetics
Answer: D = 594 mg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Clearance
CL = 0.045·88 = 3.96 L/h
Dose
D = Css,avg·CL·τ/(S·F) = 10·3.96·12/(0.8·1) = 594 mg