Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
Practice exercise (made-up values, not clinical guidance). A vial contains ceftriaxone 1000 mg as a powder. The practice label says to add 9.6 mL of sterile water; the powder adds 0.4 mL to the volume. What is the concentration C in mg/mL after reconstitution?
1000 mg9.6 mL+0.4 mL
C = mg/mL
2.Pharmacy calculationsHard
A vial holds 2000 mg of powder. You add 4.5 mL of diluent, and the powder adds 0.5 mL of volume. The prescription is 1560 mg. Draw up the dose: what volume V do you give?
2000 mg4.5 mL + 0.5 mL1560 mg
V = mL
3.Dosage calculationsMedium
A child weighing 8 kg is prescribed 15 mg/kg of a drug. The stock solution contains 20 mg/mL. Draw up the dose: what volume V do you give?
8 kg15 mg/kg20 mg/mL
V = mL
4.Dosage calculationsHard
A patient weighs 173.8 lb. The prescription is 10 mg/kg as a single dose, and the stock contains 250 mg in 5 mL. Using 1 kg = 2.2 lb, what volume V do you give?
173.8 lb10 mg/kg250 mg/5 mL1 kg = 2.2 lb
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 6 mg/L at 1 h and 1.5 mg/L at 7 h. Assume first-order elimination. Find the half-life t½.
C1 = 6 mg/L (1 h)C2 = 1.5 mg/L (7 h)
t½ = h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 42 mg/h with no loading dose. The patient's clearance is 3.5 L/h and the half-life is 8 h. What is the level C after 3 h?
R = 42 mg/hCL = 3.5 L/ht½ = 8 ht = 3 h
C = mg/L
3Solutions
1.Pharmacy calculations
Answer: C = 100 mg/mL
Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Final volume
9.6 + 0.4 = 10 mL
Concentration
C = 1000/10 = 100 mg/mL
Answer
C = 100 mg/mL
2.Pharmacy calculations
Answer: V = 3.9 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Final volume and concentration
4.5 + 0.5 = 5 mL
C = 2000/5 = 400 mg/mL
Volume
V = 1560/400 = 3.9 mL
Answer
V = 3.9 mL
3.Dosage calculations
Answer: V = 6 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Dose from body weight
D = 15·8 = 120 mg
Volume
V = 120/20 = 6 mL
On the syringe
On this 10 mL syringe every small line is 0.2 mL.
Answer
V = 6 mL
4.Dosage calculations
Answer: V = 15.8 mL
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Weight in kg
173.8/2.2 = 79 kg
Dose
10·79 = 790 mg
Volume
V = (790/250)·5 = 15.8 mL
Answer
V = 15.8 mL
5.Clinical pharmacokinetics
Answer: t½ = 3 h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(6/1.5)/6 = 1.386/6 = 0.231 h⁻¹
Half-life
t½ = 0.693/0.231 = 3 h
Answer
t½ = 3 h
6.Clinical pharmacokinetics
Answer: C = 2.747 mg/L
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.