Pharmacy Calculations: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

Pharmacy calculations

Percentage strength
% w/v = g per 100 mL
Amount in a solution
g = % × mL / 100
Ratio strength
1:X = 1 g in X mL; % = 100 / X
Reconstitution
final volume = diluent + powder volume
Concentration
mg/mL = drug in vial / final volume
Alligation
parts of H = T − L, parts of L = H − T
Water or base
0%

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.Pharmacy calculationsMedium
ampicillin 1 gAdd 3.5 mL sterile water.Powder volume: 0.5 mL.? mg/mL

Practice exercise (made-up values, not clinical guidance). A vial contains ampicillin 1000 mg as a powder. The practice label says to add 3.5 mL of sterile water; the powder adds 0.5 mL to the volume. What is the concentration C in mg/mL after reconstitution?

1000 mg3.5 mL+0.5 mL
C = mg/mL
2.Pharmacy calculationsHard
23%sodium chloride+3%sodium chloride? mL5%750 mL

Practice exercise (made-up values, not clinical guidance). You must prepare 750 mL of 5% sodium chloride by mixing 23% and 3% sodium chloride. How many mL V of the 3% solution do you need? Round to the nearest whole mL.

23%3%5%750 mL
V = mL
3.Dosage calculationsMedium
12 kg5 mg/kg/day2× per dayD = ? mg

A patient weighs 12 kg. The prescribed dose is 5 mg/kg per day, given in 2 equal doses. How many milligrams D are given per dose?

12 kg5 mg/kg/day2× per day
D = mg
4.Dosage calculationsHard
200 mg/5 mLV = ? mL

A patient weighs 55 lb. The prescription is 1 mg/kg as a single dose, and the stock contains 200 mg in 5 mL. Using 1 kg = 2.2 lb, what volume V do you give? Round to two decimal places.

55 lb1 mg/kg200 mg/5 mL1 kg = 2.2 lb
V = mL
5.Clinical pharmacokineticsMedium
110100t (h)C (mg/L)1 h25 mg/L9 h9.9 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 25 mg/L at 1 h and 9.9 mg/L at 9 h. Assume first-order elimination. Find the half-life t½.

C1 = 25 mg/L (1 h)C2 = 9.9 mg/L (9 h)
t½ = h
6.Clinical pharmacokineticsHard
VCss,avg​ = ?500 mg · q8hCL = 0.035 L/kg/h68 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 68 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.035 L/kg/h. Each dose is 500 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.035 L/kg/hτ = 8 hS = 1F = 168 kgD = 500 mg
Css,avg = mg/L

3Solutions

1.Pharmacy calculations

Answer: C = 250 mg/mL

Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Final volume

3.5 + 0.5 = 4 mL

Concentration

C = 1000/4 = 250 mg/mL

Answer

C = 250 mg/mL
2.Pharmacy calculations

Answer: V = 675 mL

Alligation: to mix a higher strength H and a lower strength L into a target strength T, take (T − L) parts of H and (H − T) parts of L. The parts are crossed: each stock gets the distance from the target to the other stock. Water or a plain base counts as 0%. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Alligation parts

23%: 5 − 3 = 2 parts
3%: 23 − 5 = 18 parts
total: 20 parts

Share the volume

V = 750·18/20 = 675 mL

Answer

V = 675 mL

Check: 75 mL of 23% + 675 mL of 3% = 750 mL.

3.Dosage calculations

Answer: D = 30 mg

Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.

Total per day

5·12 = 60 mg

Per dose

D = 60/2 = 30 mg

Answer

D = 30 mg
4.Dosage calculations

Answer: V = 0.63 mL

Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.

Weight in kg

55/2.2 = 25 kg

Dose

1·25 = 25 mg

Volume

V = (25/200)·5 = 0.625 ≈ 0.63 mL

Answer

V = 0.63 mL
5.Clinical pharmacokinetics

Answer: t½ = 5.986 h

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Elimination rate constant

k = ln(25/9.9)/8 = 0.9263/8 = 0.1158 h⁻¹

Half-life

t½ = 0.693/0.1158 = 5.986 h

Answer

t½ = 5.986 h
6.Clinical pharmacokinetics

Answer: Css,avg = 26.26 mg/L

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Clearance

CL = 0.035·68 = 2.38 L/h

Average steady-state level

Css,avg = S·F·D/(CL·τ) = 1·1·500/(2.38·8) = 26.26 mg/L

Answer

Css,avg = 26.26 mg/L

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