Pharmacy Calculations: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

Pharmacy calculations

Percentage strength
% w/v = g per 100 mL
Amount in a solution
g = % × mL / 100
Ratio strength
1:X = 1 g in X mL; % = 100 / X
Reconstitution
final volume = diluent + powder volume
Concentration
mg/mL = drug in vial / final volume
Alligation
parts of H = T − L, parts of L = H − T
Water or base
0%

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.Pharmacy calculationsMedium
ceftriaxone 2 gAdd 19.2 mL sterile water.Powder volume: 0.8 mL.? mg/mL

Practice exercise (made-up values, not clinical guidance). A vial contains ceftriaxone 2000 mg as a powder. The practice label says to add 19.2 mL of sterile water; the powder adds 0.8 mL to the volume. What is the concentration C in mg/mL after reconstitution?

2000 mg19.2 mL+0.8 mL
C = mg/mL
2.Pharmacy calculationsHard
10%150 g+2%salicylic acid? g4%salicylic acid

Practice exercise (made-up values, not clinical guidance). You have 150 g of 10% salicylic acid ointment. How many grams m of 2% salicylic acid ointment must you add to make a 4% ointment? Round to the nearest whole gram.

150 g · 10%2%4%
m = g
3.Dosage calculationsMedium
024681010 mL

A child weighing 34 kg is prescribed 5 mg/kg of a drug. The stock solution contains 25 mg/mL. Draw up the dose: what volume V do you give?

34 kg5 mg/kg25 mg/mL
V = mL
4.Dosage calculationsHard
00.10.20.30.40.50.60.70.80.911 mL

The prescription is 0.18 mg. The ampoule contains 1000 micrograms per mL. Draw up the dose in the 1 mL syringe: what volume V do you give?

0.18 mg1000 mcg/mL
V = mL
5.Clinical pharmacokineticsMedium
10100t (h)C (mg/L)1 h30 mg/L11 h12.6 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 30 mg/L at 1 h and 12.6 mg/L at 11 h. Assume first-order elimination. Find the elimination rate constant k.

C1 = 30 mg/L (1 h)C2 = 12.6 mg/L (11 h)
k = h⁻¹
6.Clinical pharmacokineticsHard
VCss,avg​ = 10 mg/LD = ? mg · q12hCL = 0.04 L/kg/h73 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 73 kg patient takes oral aminophylline (S = 0.8, F = 1) every 12 h. The theophylline clearance is 0.04 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.04 L/kg/hτ = 12 hS = 0.8F = 173 kgCss,avg = 10 mg/L
D = mg

3Solutions

1.Pharmacy calculations

Answer: C = 100 mg/mL

Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Final volume

19.2 + 0.8 = 20 mL

Concentration

C = 2000/20 = 100 mg/mL

Answer

C = 100 mg/mL
2.Pharmacy calculations

Answer: m = 450 g

Alligation: to mix a higher strength H and a lower strength L into a target strength T, take (T − L) parts of H and (H − T) parts of L. The parts are crossed: each stock gets the distance from the target to the other stock. Water or a plain base counts as 0%. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Alligation parts

10%: 4 − 2 = 2 parts
2%: 10 − 4 = 6 parts

Scale to the amount you have

m = 150·6/2 = 450 g

Answer

m = 450 g

Check: 150 g + 450 g = 600 g of 4% ointment.

3.Dosage calculations

Answer: V = 6.8 mL

Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.

Dose from body weight

D = 5·34 = 170 mg

Volume

V = 170/25 = 6.8 mL

On the syringe

On this 10 mL syringe every small line is 0.2 mL.

Answer

V = 6.8 mL
4.Dosage calculations

Answer: V = 0.18 mL

Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.

Same units

0.18 mg = 180 mcg

Volume

V = 180/1000 = 0.18 mL

Answer

V = 0.18 mL
5.Clinical pharmacokinetics

Answer: k = 0.08675 h⁻¹

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Elimination rate constant

k = ln(30/12.6)/10 = 0.8675/10 = 0.08675 h⁻¹

Answer

k = 0.08675 h⁻¹
6.Clinical pharmacokinetics

Answer: D = 438 mg

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Clearance

CL = 0.04·73 = 2.92 L/h

Dose

D = Css,avg·CL·τ/(S·F) = 10·2.92·12/(0.8·1) = 438 mg

Answer

D = 438 mg

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