Pharmacy Calculations: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

Pharmacy calculations

Percentage strength
% w/v = g per 100 mL
Amount in a solution
g = % × mL / 100
Ratio strength
1:X = 1 g in X mL; % = 100 / X
Reconstitution
final volume = diluent + powder volume
Concentration
mg/mL = drug in vial / final volume
Alligation
parts of H = T − L, parts of L = H − T
Water or base
0%

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.Pharmacy calculationsMedium
024681010 mL

A solution has a ratio strength of 1:10 000. You need 0.6 mg. Draw up the volume in the 10 mL syringe: what volume V is that?

1:10 0000.6 mg
V = mL
2.Pharmacy calculationsHard
0123455 mL

A vial holds 1000 mg of powder. You add 3.5 mL of diluent, and the powder adds 0.5 mL of volume. The prescription is 325 mg. Draw up the dose: what volume V do you give?

1000 mg3.5 mL + 0.5 mL325 mg
V = mL
3.Dosage calculationsMedium
0.5%w/vV = ? mL

A dose of 15 mg is needed from a 0.5% (w/v) solution. What volume V contains this dose?

15 mg0.5% w/v
V = mL
4.Dosage calculationsHard
53 kg170 cmBSA = √(h·w/3600)50 mg/m²D = ? mg

A patient is 170 cm tall and weighs 53 kg. The prescription is 50 mg/m². Using the Mosteller formula BSA = √(height (cm) × weight (kg)/3600), find the dose D in mg.

170 cm53 kg50 mg/m²
D = mg
5.Clinical pharmacokineticsMedium
VCss​ = 20 mg/LR = ? mg/hCL = 65 mL/min

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 65 mL/min. What infusion rate R in mg/h gives a steady-state level of 20 mg/L?

CL = 65 mL/minCss = 20 mg/L
R = mg/h
6.Clinical pharmacokineticsHard
0.1110100t (h)C (mg/L)Cpeak​ = 10τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's tobramycin half-life is 2 h. The target is a peak of 10 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2 hCpeak = 10 mg/LCtrough = 0.5 mg/L
τ = h

3Solutions

1.Pharmacy calculations

Answer: V = 6 mL

Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.

Strength in mg/mL

1000 mg/10 000 mL = 0.1 mg/mL

Volume

V = 0.6/0.1 = 6 mL

Answer

V = 6 mL
2.Pharmacy calculations

Answer: V = 1.3 mL

Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.

Final volume and concentration

3.5 + 0.5 = 4 mL
C = 1000/4 = 250 mg/mL

Volume

V = 325/250 = 1.3 mL

Answer

V = 1.3 mL
3.Dosage calculations

Answer: V = 3 mL

Solution strengths: a percentage strength is grams per 100 mL, so 1% = 1 g/100 mL = 10 mg/mL. A ratio strength 1:1000 means 1 g in 1000 mL = 1 mg/mL; 1:10 000 is 0.1 mg/mL. For a dilution the amount of drug stays the same: C₁·V₁ = C₂·V₂.

Concentration

0.5% = 5 mg/mL

Volume

V = 15/5 = 3 mL

Answer

V = 3 mL
4.Dosage calculations

Answer: D = 79.1 mg

Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).

Body surface area

BSA = √(170·53/3600) = √2.503 = 1.582 m²

Dose

D = 50·1.582 = 79.1 mg

Answer

D = 79.1 mg
5.Clinical pharmacokinetics

Answer: R = 78 mg/h

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Clearance in L/h

65·60/1000 = 3.9 L/h

Infusion rate

R = 3.9·20 = 78 mg/h

Answer

R = 78 mg/h
6.Clinical pharmacokinetics

Answer: τ = 8.6 h

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Rate constant

k = 0.693/2 = 0.3466 h⁻¹

Dosing interval

τ = ln(10/0.5)/0.3466 = 2.996/0.3466 = 8.644 ≈ 8.6 h

Answer

τ = 8.6 h

In practice the interval is rounded to a convenient value such as 8, 12, 24 or 36 h, and the levels are checked again.

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