Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
Practice exercise (made-up values, not clinical guidance). A vial contains ampicillin 1000 mg as a powder. The practice label says to add 3.5 mL of sterile water; the powder adds 0.5 mL to the volume. What is the concentration C in mg/mL after reconstitution?
1000 mg3.5 mL+0.5 mL
C = mg/mL
2.Pharmacy calculationsHard
A vial holds 1000 mg of powder. You add 1.5 mL of diluent, and the powder adds 0.5 mL of volume. The prescription is 500 mg. Draw up the dose: what volume V do you give?
1000 mg1.5 mL + 0.5 mL500 mg
V = mL
3.Dosage calculationsMedium
A patient weighing 88 kg has a body surface area of 1.75 m². The prescription is 135 mg/m². Find the dose D in mg.
88 kgBSA = 1.75 m²135 mg/m²
D = mg
4.Dosage calculationsHard
A child weighing 24 kg is prescribed 20 mg/kg per dose of an oral suspension that contains 120 mg in 5 mL. What volume V do you give?
24 kg20 mg/kg120 mg/5 mL
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 35 mg/L at 1 h and 8.8 mg/L at 13 h. Assume first-order elimination. Find the half-life t½.
C1 = 35 mg/L (1 h)C2 = 8.8 mg/L (13 h)
t½ = h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). An 80 kg patient has a phenytoin level of 9 mg/L; the target is 15 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?
80 kgVd = 0.7 L/kgC = 9 → 15 mg/LS = 0.92
LD = mg
3Solutions
1.Pharmacy calculations
Answer: C = 250 mg/mL
Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Final volume
3.5 + 0.5 = 4 mL
Concentration
C = 1000/4 = 250 mg/mL
Answer
C = 250 mg/mL
2.Pharmacy calculations
Answer: V = 1 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Final volume and concentration
1.5 + 0.5 = 2 mL
C = 1000/2 = 500 mg/mL
Volume
V = 500/500 = 1 mL
Answer
V = 1 mL
3.Dosage calculations
Answer: D = 236.3 mg
Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).
Dose
D = 135·1.75 = 236.3 mg
Answer
D = 236.3 mg
4.Dosage calculations
Answer: V = 20 mL
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Dose from weight
20·24 = 480 mg
Volume
V = (480/120)·5 = 20 mL
Answer
V = 20 mL
5.Clinical pharmacokinetics
Answer: t½ = 6.025 h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(35/8.8)/12 = 1.381/12 = 0.115 h⁻¹
Half-life
t½ = 0.693/0.115 = 6.025 h
Answer
t½ = 6.025 h
6.Clinical pharmacokinetics
Answer: LD = 365.2 mg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 0.7·80 = 56 L
Rise needed
15 − 9 = 6 mg/L
Loading dose
LD = 56·6/(0.92·1) = 365.2 mg
Answer
LD = 365.2 mg
In practice the dose is rounded to a convenient amount.