Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
Practice exercise (made-up values, not clinical guidance). A vial contains cefazolin 1000 mg as a powder. The practice label says to add 4.5 mL of sterile water; the powder adds 0.5 mL to the volume. The prescribed dose is 250 mg. What volume V do you draw up? Round to one decimal place.
1000 mg4.5 mL+0.5 mL250 mg
V = mL
2.Pharmacy calculationsHard
A vial holds 250 mg of powder. You add 9.5 mL of diluent, and the powder adds 0.5 mL of volume. The prescription is 90 mg. Draw up the dose: what volume V do you give?
250 mg9.5 mL + 0.5 mL90 mg
V = mL
3.Dosage calculationsMedium
A child weighing 7 kg is prescribed 2 mg/kg of a drug. The stock solution contains 10 mg/mL. Draw up the dose: what volume V do you give?
7 kg2 mg/kg10 mg/mL
V = mL
4.Dosage calculationsHard
An infusion contains 25000 units of a drug in 1000 mL. The prescription is 1200 units per hour. At what rate R do you set the pump, in mL/h?
25000 units/1000 mL1200 units/h
R = mL/h
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). An 82 kg patient is to receive an aminophylline infusion (salt factor S = 0.8: 80% of aminophylline is theophylline). The theophylline clearance is 0.045 L/kg/h. What aminophylline infusion rate R in mg/h gives a steady-state theophylline level of 15 mg/L?
82 kgCL = 0.045 L/kg/hCss = 15 mg/LS = 0.8
R = mg/h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 48-year-old woman weighs 90 kg and has a serum creatinine of 2.2 mg/dL (194 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual vancomycin regimen is 1000 mg every 12 h for a creatinine clearance of 100 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.
Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Final volume
4.5 + 0.5 = 5 mL
Concentration
1000/5 = 200 mg/mL
Volume to give
V = 250/200 = 1.25 ≈ 1.3 mL
Answer
V = 1.3 mL
2.Pharmacy calculations
Answer: V = 3.6 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Final volume and concentration
9.5 + 0.5 = 10 mL
C = 250/10 = 25 mg/mL
Volume
V = 90/25 = 3.6 mL
Answer
V = 3.6 mL
3.Dosage calculations
Answer: V = 1.4 mL
Drawing up a dose: volume = (prescribed dose/stock strength) × stock volume. Convert to the same units first, then check that the volume fits the syringe and lands on one of its graduations.
Dose from body weight
D = 2·7 = 14 mg
Volume
V = 14/10 = 1.4 mL
On the syringe
On this 10 mL syringe every small line is 0.2 mL.
Answer
V = 1.4 mL
4.Dosage calculations
Answer: R = 48 mL/h
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Concentration
25000/1000 = 25 units/mL
Pump rate
R = 1200/25 = 48 mL/h
Answer
R = 48 mL/h
5.Clinical pharmacokinetics
Answer: R = 69.19 mg/h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Clearance
CL = 0.045·82 = 3.69 L/h
Infusion rate
R = CL·Css/S = 3.69·15/0.8 = 69.19 mg/h
Answer
R = 69.19 mg/h
6.Clinical pharmacokinetics
Answer: τ = 27 h
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Creatinine clearance (Cockcroft–Gault)
CrCl = (140 − 48)·90/(72·2.2)·0.85 = 44.43 mL/min
New interval
τ = 12·100/44.43 = 27.01 ≈ 27 h
Answer
τ = 27 h
In practice the interval is rounded to a convenient value such as 12, 24, 36 or 48 h.