Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
Practice exercise (made-up values, not clinical guidance). A vial contains oxacillin 2000 mg as a powder. The practice label says to add 11.5 mL of sterile water; the powder adds 1 mL to the volume. The prescribed dose is 1600 mg. What volume V do you draw up? Round to one decimal place.
2000 mg11.5 mL+1 mL1600 mg
V = mL
2.Pharmacy calculationsHard
A vial holds 1000 mg of powder. You add 4.5 mL of diluent, and the powder adds 0.5 mL of volume. The prescription is 840 mg. Draw up the dose: what volume V do you give?
1000 mg4.5 mL + 0.5 mL840 mg
V = mL
3.Dosage calculationsMedium
A patient weighs 15 kg. The prescribed dose is 15 mg/kg per day, given in 3 equal doses. How many milligrams D are given per dose?
15 kg15 mg/kg/day3× per day
D = mg
4.Dosage calculationsHard
A child weighing 14 kg is prescribed 10 mg/kg per dose of an oral suspension that contains 125 mg in 5 mL. What volume V do you give?
14 kg10 mg/kg125 mg/5 mL
V = mL
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 35 mg/L at 1 h and 10.7 mg/L at 13 h. Assume first-order elimination. Find the half-life t½.
C1 = 35 mg/L (1 h)C2 = 10.7 mg/L (13 h)
t½ = h
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 66 kg patient has a theophylline level of 9 mg/L; the target is 15 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?
66 kgVd = 0.5 L/kgC = 9 → 15 mg/LS = 0.8
LD = mg
3Solutions
1.Pharmacy calculations
Answer: V = 10 mL
Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Final volume
11.5 + 1 = 12.5 mL
Concentration
2000/12.5 = 160 mg/mL
Volume to give
V = 1600/160 = 10 mL
Answer
V = 10 mL
2.Pharmacy calculations
Answer: V = 4.2 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Final volume and concentration
4.5 + 0.5 = 5 mL
C = 1000/5 = 200 mg/mL
Volume
V = 840/200 = 4.2 mL
Answer
V = 4.2 mL
3.Dosage calculations
Answer: D = 75 mg
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Total per day
15·15 = 225 mg
Per dose
D = 225/3 = 75 mg
Answer
D = 75 mg
4.Dosage calculations
Answer: V = 5.6 mL
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Dose from weight
10·14 = 140 mg
Volume
V = (140/125)·5 = 5.6 mL
Answer
V = 5.6 mL
5.Clinical pharmacokinetics
Answer: t½ = 7.019 h
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(35/10.7)/12 = 1.185/12 = 0.09876 h⁻¹
Half-life
t½ = 0.693/0.09876 = 7.019 h
Answer
t½ = 7.019 h
6.Clinical pharmacokinetics
Answer: LD = 247.5 mg
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Volume of distribution
Vd = 0.5·66 = 33 L
Rise needed
15 − 9 = 6 mg/L
Loading dose
LD = 33·6/(0.8·1) = 247.5 mg
Answer
LD = 247.5 mg
In practice the dose is rounded to a convenient amount.