Pharmacy Calculations: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

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1Formulas and methods

Pharmacy calculations

Percentage strength
% w/v = g per 100 mL
Amount in a solution
g = % × mL / 100
Ratio strength
1:X = 1 g in X mL; % = 100 / X
Reconstitution
final volume = diluent + powder volume
Concentration
mg/mL = drug in vial / final volume
Alligation
parts of H = T − L, parts of L = H − T
Water or base
0%

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.Pharmacy calculationsMedium
oxacillin 2 gAdd 11.5 mL sterile water.Powder volume: 1 mL.1600 mg → ? mL

Practice exercise (made-up values, not clinical guidance). A vial contains oxacillin 2000 mg as a powder. The practice label says to add 11.5 mL of sterile water; the powder adds 1 mL to the volume. The prescribed dose is 1600 mg. What volume V do you draw up? Round to one decimal place.

2000 mg11.5 mL+1 mL1600 mg
V = mL
2.Pharmacy calculationsHard
0123455 mL

A vial holds 1000 mg of powder. You add 4.5 mL of diluent, and the powder adds 0.5 mL of volume. The prescription is 840 mg. Draw up the dose: what volume V do you give?

1000 mg4.5 mL + 0.5 mL840 mg
V = mL
3.Dosage calculationsMedium
15 kg15 mg/kg/day3× per dayD = ? mg

A patient weighs 15 kg. The prescribed dose is 15 mg/kg per day, given in 3 equal doses. How many milligrams D are given per dose?

15 kg15 mg/kg/day3× per day
D = mg
4.Dosage calculationsHard
125 mg/5 mLV = ? mL

A child weighing 14 kg is prescribed 10 mg/kg per dose of an oral suspension that contains 125 mg in 5 mL. What volume V do you give?

14 kg10 mg/kg125 mg/5 mL
V = mL
5.Clinical pharmacokineticsMedium
110100t (h)C (mg/L)1 h35 mg/L13 h10.7 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 35 mg/L at 1 h and 10.7 mg/L at 13 h. Assume first-order elimination. Find the half-life t½.

C1 = 35 mg/L (1 h)C2 = 10.7 mg/L (13 h)
t½ = h
6.Clinical pharmacokineticsHard
Vd = 0.5 L/kg9 → 15 mg/LLD = ? mg66 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 66 kg patient has a theophylline level of 9 mg/L; the target is 15 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

66 kgVd = 0.5 L/kgC = 9 → 15 mg/LS = 0.8
LD = mg

3Solutions

1.Pharmacy calculations

Answer: V = 10 mL

Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Final volume

11.5 + 1 = 12.5 mL

Concentration

2000/12.5 = 160 mg/mL

Volume to give

V = 1600/160 = 10 mL

Answer

V = 10 mL
2.Pharmacy calculations

Answer: V = 4.2 mL

Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.

Final volume and concentration

4.5 + 0.5 = 5 mL
C = 1000/5 = 200 mg/mL

Volume

V = 840/200 = 4.2 mL

Answer

V = 4.2 mL
3.Dosage calculations

Answer: D = 75 mg

Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.

Total per day

15·15 = 225 mg

Per dose

D = 225/3 = 75 mg

Answer

D = 75 mg
4.Dosage calculations

Answer: V = 5.6 mL

Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.

Dose from weight

10·14 = 140 mg

Volume

V = (140/125)·5 = 5.6 mL

Answer

V = 5.6 mL
5.Clinical pharmacokinetics

Answer: t½ = 7.019 h

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Elimination rate constant

k = ln(35/10.7)/12 = 1.185/12 = 0.09876 h⁻¹

Half-life

t½ = 0.693/0.09876 = 7.019 h

Answer

t½ = 7.019 h
6.Clinical pharmacokinetics

Answer: LD = 247.5 mg

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Volume of distribution

Vd = 0.5·66 = 33 L

Rise needed

15 − 9 = 6 mg/L

Loading dose

LD = 33·6/(0.8·1) = 247.5 mg

Answer

LD = 247.5 mg

In practice the dose is rounded to a convenient amount.

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