Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
Check the result: levels fall by half every half-life, and steady state takes about five half-lives.
2Practice problems
1.Pharmacy calculationsMedium
Practice exercise (made-up values, not clinical guidance). A vial contains oxacillin 2000 mg as a powder. The practice label says to add 11.5 mL of sterile water; the powder adds 1 mL to the volume. The prescribed dose is 500 mg. What volume V do you draw up? Round to one decimal place.
2000 mg11.5 mL+1 mL500 mg
V = mL
2.Pharmacy calculationsHard
A vial holds 250 mg of powder. You add 9.8 mL of diluent, and the powder adds 0.2 mL of volume. The prescription is 52.5 mg. Draw up the dose: what volume V do you give?
250 mg9.8 mL + 0.2 mL52.5 mg
V = mL
3.Dosage calculationsMedium
How many milligrams of drug m are in 5 mL of a 1% (w/v) solution?
1% w/v5 mL
m = mg
4.Dosage calculationsHard
An infusion contains 40000 units of a drug in 250 mL. The prescription is 2000 units per hour. At what rate R do you set the pump, in mL/h?
40000 units/250 mL2000 units/h
R = mL/h
5.Clinical pharmacokineticsMedium
Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 10 mg/L at 2 h and 3.5 mg/L at 5 h. Assume first-order elimination. Find the elimination rate constant k.
C1 = 10 mg/L (2 h)C2 = 3.5 mg/L (5 h)
k = h⁻¹
6.Clinical pharmacokineticsHard
Practice exercise (made-up values, not clinical guidance). A 90 kg patient takes oral theophylline (F = 1) every 12 h. The clearance is 0.045 L/kg/h. Each dose is 200 mg of theophylline. Find the average steady-state level Css,avg.
Reconstitution: the powder takes up space, so the final volume is the diluent plus the powder volume. Concentration = drug in the vial/final volume, and the volume to give = dose/concentration. On a multi-strength label, use the concentration that belongs to the amount of diluent you actually added. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Final volume
11.5 + 1 = 12.5 mL
Concentration
2000/12.5 = 160 mg/mL
Volume to give
V = 500/160 = 3.125 ≈ 3.1 mL
Answer
V = 3.1 mL
2.Pharmacy calculations
Answer: V = 2.1 mL
Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.
Final volume and concentration
9.8 + 0.2 = 10 mL
C = 250/10 = 25 mg/mL
Volume
V = 52.5/25 = 2.1 mL
Answer
V = 2.1 mL
3.Dosage calculations
Answer: m = 50 mg
Solution strengths: a percentage strength is grams per 100 mL, so 1% = 1 g/100 mL = 10 mg/mL. A ratio strength 1:1000 means 1 g in 1000 mL = 1 mg/mL; 1:10 000 is 0.1 mg/mL. For a dilution the amount of drug stays the same: C₁·V₁ = C₂·V₂.
Concentration
1% = 1 g/100 mL = 10 mg/mL
Mass of drug
m = 10·5 = 50 mg
Answer
m = 50 mg
4.Dosage calculations
Answer: R = 12.5 mL/h
Dose calculation: the amount to give equals what is prescribed divided by what you have, times the quantity it comes in: amount = (desired dose/stock strength) × stock volume. Always keep the units the same (convert g to mg, mg to mcg first) and check that the answer is sensible.
Concentration
40000/250 = 160 units/mL
Pump rate
R = 2000/160 = 12.5 mL/h
Answer
R = 12.5 mL/h
5.Clinical pharmacokinetics
Answer: k = 0.3499 h⁻¹
Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.
Elimination rate constant
k = ln(10/3.5)/3 = 1.05/3 = 0.3499 h⁻¹
Answer
k = 0.3499 h⁻¹
6.Clinical pharmacokinetics
Answer: Css,avg = 4.115 mg/L
Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.