Pharmacy Calculations: cram pack

Formula sheets, the key method steps for every topic and 6 practice problems, with full solutions at the back.

New problemsBack to the course

In the print window, choose “Save as PDF” to keep a copy on your device.

1Formulas and methods

Pharmacy calculations

Percentage strength
% w/v = g per 100 mL
Amount in a solution
g = % × mL / 100
Ratio strength
1:X = 1 g in X mL; % = 100 / X
Reconstitution
final volume = diluent + powder volume
Concentration
mg/mL = drug in vial / final volume
Alligation
parts of H = T − L, parts of L = H − T
Water or base
0%

Dosage calculations

Dose from strength
volume = dose / strength
Weight-based dose
dose = mg/kg × body weight
Tablets
number = dose / tablet strength
Units
1 g = 1000 mg, 1 mg = 1000 mcg

Method

  1. Convert the ordered dose and the stock strength to the same unit.
  2. Use desired over have times quantity: (D/H) × Q.
  3. For weight-based doses, multiply by the weight in kg first, then divide the daily dose by the number of doses.
  4. Estimate first and check that the answer is reasonable.

Clinical pharmacokinetics

Rate constant and half-life
k = ln 2/t½ = 0.693/t½
First-order decay
C = C₀·e−kt = C₀·(1/2)t/t½
Two levels
k = ln(C₁/C₂)/Δt
Volume and clearance
Vd = dose/C₀, CL = k·Vd
Loading dose
LD = Vd·C/(S·F)
Maintenance rate
R = CL·Css/(S·F)
Average steady state
Css,avg = S·F·D/(CL·τ)
Steady state
1 − (1/2)ⁿ after n half-lives; ≈ 97% after 5
Infusion
C = (R/CL)(1 − e−kt)
Interval and dose from peak and trough
τ = ln(Cpeak/Ctrough)/k, D = Vd·(Cpeak − Ctrough)
Cockcroft–Gault
CrCl = (140 − age) × kg/(72 × SCr mg/dL), × 0.85 for women
Renal adjustment
dose × CrCl/normal; Dettli Q = 1 − fe·(1 − CrCl/normal)

Method

  1. Convert the half-life to a rate constant: k = 0.693/t½.
  2. Turn per-kg values into totals: Vd (L) = L/kg × weight, CL (L/h) = L/kg/h × weight.
  3. Pick the relation: C = C₀·e−kt, LD = Vd·C/(S·F), maintenance rate = CL·Css/(S·F), τ = ln(Cpeak/Ctrough)/k.
  4. For kidney function, estimate CrCl with Cockcroft–Gault first, then scale the dose or the interval.
  5. Check the result: levels fall by half every half-life, and steady state takes about five half-lives.

2Practice problems

1.Pharmacy calculationsMedium
024681010 mL

A solution has a ratio strength of 1:10 000. You need 0.76 mg. Draw up the volume in the 10 mL syringe: what volume V is that?

1:10 0000.76 mg
V = mL
2.Pharmacy calculationsHard
23%sodium chloride+3%sodium chloride? mL13%250 mL

Practice exercise (made-up values, not clinical guidance). You must prepare 250 mL of 13% sodium chloride by mixing 23% and 3% sodium chloride. How many mL V of the 3% solution do you need? Round to the nearest whole mL.

23%3%13%250 mL
V = mL
3.Dosage calculationsMedium
17 kgBSA = 0.87 m²375 mg/m²D = ? mg

A patient weighing 17 kg has a body surface area of 0.87 m². The prescription is 375 mg/m². Find the dose D in mg.

17 kgBSA = 0.87 m²375 mg/m²
D = mg
4.Dosage calculationsHard
46 kg133 cmBSA = √(h·w/3600)175 mg/m²D = ? mg

A patient is 133 cm tall and weighs 46 kg. The prescription is 175 mg/m². Using the Mosteller formula BSA = √(height (cm) × weight (kg)/3600), find the dose D in mg.

133 cm46 kg175 mg/m²
D = mg
5.Clinical pharmacokineticsMedium
110100t (h)C (mg/L)2 h25 mg/L14 h8.8 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 25 mg/L at 2 h and 8.8 mg/L at 14 h. Assume first-order elimination. Find the half-life t½.

C1 = 25 mg/L (2 h)C2 = 8.8 mg/L (14 h)
t½ = h
6.Clinical pharmacokineticsHard
t (h)C (mg/L)Css​4 hC = ?

Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 35 mg/h with no loading dose. The patient's clearance is 3.5 L/h and the half-life is 8 h. What is the level C after 4 h?

R = 35 mg/hCL = 3.5 L/ht½ = 8 ht = 4 h
C = mg/L

3Solutions

1.Pharmacy calculations

Answer: V = 7.6 mL

Strength to volume: turn the strength into mg per mL first. A w/v percentage is grams per 100 mL, so x% = 10x mg/mL. A ratio strength 1:n is 1 g in n mL. After reconstitution the concentration is the powder's dose over the final volume (diluent + powder volume). Then volume = dose/concentration.

Strength in mg/mL

1000 mg/10 000 mL = 0.1 mg/mL

Volume

V = 0.76/0.1 = 7.6 mL

Answer

V = 7.6 mL
2.Pharmacy calculations

Answer: V = 125 mL

Alligation: to mix a higher strength H and a lower strength L into a target strength T, take (T − L) parts of H and (H − T) parts of L. The parts are crossed: each stock gets the distance from the target to the other stock. Water or a plain base counts as 0%. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Alligation parts

23%: 13 − 3 = 10 parts
3%: 23 − 13 = 10 parts
total: 20 parts

Share the volume

V = 250·10/20 = 125 mL

Answer

V = 125 mL

Check: 125 mL of 23% + 125 mL of 3% = 250 mL.

3.Dosage calculations

Answer: D = 326.3 mg

Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).

Dose

D = 375·0.87 = 326.3 mg

Answer

D = 326.3 mg
4.Dosage calculations

Answer: D = 228.1 mg

Body-surface-area dosing: many cytotoxic and some paediatric doses are prescribed per square metre of body surface area: dose (mg) = dose per m² × BSA (m²). The Mosteller formula estimates BSA = √(height (cm) × weight (kg)/3600).

Body surface area

BSA = √(133·46/3600) = √1.699 = 1.304 m²

Dose

D = 175·1.304 = 228.1 mg

Answer

D = 228.1 mg
5.Clinical pharmacokinetics

Answer: t½ = 7.966 h

Clearance and volume: at steady state the dosing rate equals the elimination rate, so the maintenance rate = CL × Css. A loading dose is LD = Vd × C/(S × F), with S the salt factor (fraction of active drug in the salt) and F the bioavailability (1 for IV). From two levels, k = ln(C₁/C₂)/Δt; for an IV bolus Vd = dose/C₀ and CL = k × Vd. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Elimination rate constant

k = ln(25/8.8)/12 = 1.044/12 = 0.08701 h⁻¹

Half-life

t½ = 0.693/0.08701 = 7.966 h

Answer

t½ = 7.966 h
6.Clinical pharmacokinetics

Answer: C = 2.929 mg/L

Designing a regimen: with rapid IV doses the level falls from peak to trough during the interval, so τ = ln(Cpeak/Ctrough)/k and the dose that restores the peak is Vd × (Cpeak − Ctrough). The average steady-state level is Css,avg = S·F·dose/(CL·τ). An infusion rises as C = (R/CL)(1 − e−kt). For a drug cleared by the kidneys, the dose is scaled with the creatinine clearance. The numbers are for practice only; at the bedside always follow local protocols and have high-risk doses double-checked.

Steady-state level

Css = 35/3.5 = 10 mg/L

Rate constant

k = 0.693/8 = 0.08664 h⁻¹

Level after the given time

C = 10·(1 − e−0.08664·4) = 2.929 mg/L

Answer

C = 2.929 mg/L

ExamProblems · examproblems.com/courses/pharmacy-calculations