Research Methods and Statistics for Psychology: cram pack

Formula sheets, the key method steps for every topic and 16 practice problems, with full solutions at the back.

New problemsBack to the course

In the print window, choose “Save as PDF” to keep a copy on your device.

1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

Chi-square tests

Test statistic
χ² = Σ(O − E)²/E
Goodness of fit
E = n·p, df = k − 1 − (estimated parameters)
Independence
E = row total × column total / grand total, df = (r − 1)(c − 1)
Critical values (α = 0.05)
df 1: 3.841, 2: 5.991, 3: 7.815, 4: 9.488
Decision
reject H0 if χ² > χ²crit

2Practice problems

1.Research methods in psychologyMedium

Publication bias refers to:

  1. AJournals publishing only qualitative research
  2. BReviewers favouring papers by authors from famous universities over lesser-known ones
  3. CStudies with significant results being more likely to be published than null results
  4. DResearchers publishing the same study twice
2.Research methods in psychologyHard

Patients chosen because they have extremely high anxiety scores show lower scores at a second test, even without treatment. What is the most likely explanation?

  1. AThe Hawthorne effect
  2. BA ceiling effect
  3. CCounterbalancing
  4. DRegression to the mean
3.Descriptive statisticsMedium
1520253035404550

Find the sample standard deviation s of the data: 49, 11, 14, 53, 45, 33, 35.

n = 7
s =
4.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 100 and standard deviation 20. Find the z-score z of a score of 125.

μ = 100σ = 20x = 125
z =
5.ProbabilityMedium
xp(x)00.3510.3520.3μ = 0.95

For the distribution shown, find the standard deviation σ of X.

x: 0, 1, 2p(x): 0.35, 0.35, 0.3
σ =
6.ProbabilityHard
n = 9, p = 0.2: P(X = 4) = ?k0123456789

A test has 9 multiple-choice questions. A student who guesses gets each one right with probability 0.2, independently. What is the probability P of exactly 4 correct answers?

n = 9p = 0.2k = 4
P =
7.Normal distributionMedium
175.9183.95P = ?

The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. What fraction lies between 175.9 and 183.95 cm? Give P as a decimal.

μ = 178σ = 7x1 = 175.9x2 = 183.95
P =
8.Normal distributionHard
μ = 500x = ?97.5%

The battery lifetimes are normally distributed with mean 500 h and standard deviation 40 h. Find the value x below which 97.5% of them lie (the 97.5th percentile).

μ = 500σ = 40P = 97.5%
x = h
9.Confidence intervalsMedium
x̄E₁ = 6.290%, n = 64x̄E₂ = ?95%, n = 576

A 90% confidence interval for a mean, based on 64 observations and a known σ, has a margin of error of 6.2. What is the margin of error E₂ of a 95% interval based on 576 observations?

90%n₁ = 64E₁ = 6.295%n₂ = 576
E₂ =
10.Confidence intervalsHard
μ₁ − μ₂, t(20) = 1.7250LUx̄₁ − x̄₂E = ?90%

Two fertilisers are tested. Plot group 1: 11 plots, mean yield 10 kg, standard deviation 5.5 kg. Plot group 2: 11 plots, mean −0.5 kg, standard deviation 3 kg. Assume equal variances (pooled t, df = n₁ + n₂ − 2). Find the margin of error E of the 90% confidence interval for μ₁ − μ₂.

n₁ = 11x̄₁ = 10s₁ = 5.5n₂ = 11x̄₂ = −0.5s₂ = 390%t(20) = 1.725
E = kg
11.Hypothesis tests & confidence intervalsMedium
−2.4p = ?

The mean of a population is claimed to be 120; the population standard deviation is known to be 30. A random sample of 144 observations has a mean of 114. Test H₀: μ = 120 against H₁: μ < 120. Find the p-value p.

μ₀ = 120σ = 30n = 144x̄ = 114H₁: μ < μ₀
p =
12.Hypothesis tests & confidence intervalsHard
−1.961.96z = ?

In a trial, 24 of 80 patients on treatment A recover, and 90 of 250 patients on treatment B. Using the pooled proportion, find the test statistic z for H₀: p₁ = p₂.

x₁ = 24n₁ = 80x₂ = 90n₂ = 250
z =
13.Linear regression & correlationMedium
xy121221319416519xy24161820

The table gives 5 paired observations of x = car age in years and y = price in k€. Find the coefficient of determination r² of the least-squares line.

n = 5
r² =
14.Linear regression & correlationHard
xy12422131441358xy2410152025x = 1.5

The table gives 5 paired observations of x = car age in years and y = price in k€. Use the least-squares line ŷ = a + b·x. Predict ŷ for x = 1.5.

n = 5x = 1.5
ŷ =
15.Chi-square testsMedium
yesnoTotalmen919100women4951100Total14060200

The contingency table shows observed counts. Compute the chi-square statistic χ² for the test of independence between the row and column variables. Do not use a continuity correction.

N = 2002 × 2
χ² =
16.Chi-square testsHard

A chi-square goodness-of-fit test checks whether counts in 6 categories follow a Poisson distribution whose mean is estimated from the same data. How many degrees of freedom df does the test have?

k = 6
df =

3Solutions

1.Research methods in psychology

Answer: C · Studies with significant results being more likely to be published than null results

Why this is the answer

When non-significant studies stay in file drawers, the published literature overestimates effect sizes, which distorts meta-analyses.

Answer

C · Studies with significant results being more likely to be published than null results
2.Research methods in psychology

Answer: D · Regression to the mean

Why this is the answer

When people are selected for extreme scores, measurement error and chance mean their later scores tend to move towards the average. Control groups help separate this from treatment effects.

Answer

D · Regression to the mean
3.Descriptive statistics

Answer: s = 16.52

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 240/7 = 34.29

Squared deviations

Σ(x − x̄)² = 14.71² + (−23.29)² + (−20.29)² + 18.71² + 10.71² + (−1.286)² + 0.7143² = 1637

Standard deviation

s = √(1637/6) = 16.52

Answer

s = 16.52
4.Descriptive statistics

Answer: z = 1.25

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (125 − 100)/20 = 1.25

Answer

z = 1.25
5.Probability

Answer: σ = 0.8047

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Mean

μ = 0·0.35 + 1·0.35 + 2·0.3 = 0.95

Mean of the squares

E(X²) = 0·0.35 + 1·0.35 + 4·0.3 = 1.55

Variance

Var(X) = 1.55 − 0.95² = 0.6475
σ = √0.6475 = 0.8047

Answer

σ = 0.8047
6.Probability

Answer: P = 0.06606

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Binomial formula

P(X = 4) = 126·0.24·0.85 = 126·0.0016·0.3277 = 0.06606

Answer

P = 0.06606
7.Normal distribution

Answer: P = 0.4202

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (175.9 − 178)/7 = −0.3
z₂ = (183.95 − 178)/7 = 0.85

Area between

P = Φ(0.85) − Φ(−0.3) = 0.8023 − 0.3821 = 0.4202

Answer

P = 0.4202
8.Normal distribution

Answer: x = 578.4 h

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z for the percentile

Φ(z) = 0.975 → z = 1.96

Back to x

x = 500 + 1.96·40 = 578.4 h

Answer

x = 578.4 h
9.Confidence intervals

Answer: E₂ = 2.462

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Ratio of margins

E₂/E₁ = (1.96/1.645)·√(64/576) = 0.3972

New margin

E₂ = 6.2·0.3972 = 2.462

Answer

E₂ = 2.462
10.Confidence intervals

Answer: E = 3.258 kg

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Pooled standard deviation

sp² = (10·5.5² + 10·3²)/20 = 19.63
sp = 4.43

Margin of error

E = 1.725·4.43·√(1/11 + 1/11) = 3.258

Answer

E = 3.258 kg
11.Hypothesis tests & confidence intervals

Answer: p = 0.008198

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 30/√144 = 2.5
z = (114 − 120)/2.5 = −2.4

Tail area

Φ(2.4) = 0.9918
1 − Φ(2.4) = 0.0082

p-value

p = 0.008198

Answer

p = 0.008198

p ≤ 0.05, so H₀ is rejected at the 5% level.

12.Hypothesis tests & confidence intervals

Answer: z = −0.9823

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Sample proportions

p̂₁ = 24/80 = 0.3
p̂₂ = 90/250 = 0.36
p̂ = 114/330 = 0.3455

Standard error under H₀

SE = √(0.3455·0.6545·(1/80 + 1/250)) = 0.06108

Test statistic

z = (0.3 − 0.36)/0.06108 = −0.9823

Answer

z = −0.9823

|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).

13.Linear regression & correlation

Answer: r² = 0.4821

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 15/5 = 3
ȳ = 96/5 = 19.2

Sums of squares and products

Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = −9
Syy = Σ(y − ȳ)² = 16.8

Coefficient of determination

r² = −9²/(10·16.8) = 0.4821

Answer

r² = 0.4821

About 48.21% of the variation in y is explained by the line.

14.Linear regression & correlation

Answer: ŷ = 22

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 15/5 = 3
ȳ = 80/5 = 16

Sums of squares and products

Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = −40

Regression line

b = −40/10 = −4
a = 16 − (−4)·3 = 28
ŷ = 28 − 4·x

Prediction

ŷ = 28 + (−4)·1.5 = 22

Answer

ŷ = 22
15.Chi-square tests

Answer: χ² = 42

Chi-square tests: compare observed counts O with the counts E expected under H₀ using χ² = Σ(O − E)²/E. Goodness of fit: E = n·p for each category, df = k − 1 (minus one more for each parameter estimated from the data). Independence in an r × c table: E = row total × column total / grand total, df = (r − 1)(c − 1). Reject H₀ when χ² exceeds the critical value for the chosen α.

Expected counts

men: 100·140/200 = 70, 100·60/200 = 30
women: 100·140/200 = 70, 100·60/200 = 30

Chi-square statistic

χ² = (91 − 70)²/70 + (9 − 30)²/30 + (49 − 70)²/70 + (51 − 30)²/30
χ² = 42

Answer

χ² = 42

df = 1. At α = 0.05 the critical value is 3.841, so H₀ (independence) is rejected.

16.Chi-square tests

Answer: df = 4

Chi-square tests: compare observed counts O with the counts E expected under H₀ using χ² = Σ(O − E)²/E. Goodness of fit: E = n·p for each category, df = k − 1 (minus one more for each parameter estimated from the data). Independence in an r × c table: E = row total × column total / grand total, df = (r − 1)(c − 1). Reject H₀ when χ² exceeds the critical value for the chosen α.

Degrees of freedom

df = 6 − 1 − 1 = 4

Answer

df = 4

ExamProblems · examproblems.com/courses/research-methods-psychology