Research Methods and Statistics for Psychology: cram pack

Formula sheets, the key method steps for every topic and 16 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

Chi-square tests

Test statistic
χ² = Σ(O − E)²/E
Goodness of fit
E = n·p, df = k − 1 − (estimated parameters)
Independence
E = row total × column total / grand total, df = (r − 1)(c − 1)
Critical values (α = 0.05)
df 1: 3.841, 2: 5.991, 3: 7.815, 4: 9.488
Decision
reject H0 if χ² > χ²crit

2Practice problems

1.Research methods in psychologyMedium

A Type I error occurs when a researcher:

  1. AUses the wrong statistical test
  2. BCollects too much data
  3. CRejects a null hypothesis that is actually true
  4. DFails to reject a null hypothesis that is false
2.Research methods in psychologyHard

In qualitative research, reflexivity means that the researcher:

  1. AConverts themes into numerical data
  2. BUses a random sample to remove bias
  3. CRepeats the study to check reliability
  4. DReflects on how their own background and assumptions may shape the analysis
3.Descriptive statisticsMedium
2025303540455055

Find the sample standard deviation s of the data: 48, 55, 18, 59, 59.

n = 5
s =
4.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 60 and standard deviation 15. Find the z-score z of a score of 90.

μ = 60σ = 15x = 90
z =
5.ProbabilityMedium
xp(x)00.3510.320.35μ = 1

For the distribution shown, find the variance Var(X) of X.

x: 0, 1, 2p(x): 0.35, 0.3, 0.35
Var(X) =
6.ProbabilityHard
n = 6, p = 0.5: P(X = 1) = ?k0123456

A test has 6 multiple-choice questions. A student who guesses gets each one right with probability 0.5, independently. What is the probability P of exactly 1 correct answers?

n = 6p = 0.5k = 1
P =
7.Normal distributionMedium
242.75260.25P = ?

The bag weights are normally distributed with mean 250 g and standard deviation 5 g. What fraction lies between 242.75 and 260.25 g? Give P as a decimal.

μ = 250σ = 5x1 = 242.75x2 = 260.25
P =
8.Normal distributionHard
μ = 250x = ?97.5%

The bag weights are normally distributed with mean 250 g and standard deviation 5 g. Find the value x below which 97.5% of them lie (the 97.5th percentile).

μ = 250σ = 5P = 97.5%
x = g
9.Confidence intervalsMedium
n = 6, s = 14LUx̄ = 61E = ?90%

A sample of 6 items has mean 61 and standard deviation s = 14. The population is roughly normal. Find the margin of error E of a 90% confidence interval for the mean.

n = 6x̄ = 61s = 1490%t(5) = 2.015
E =
10.Confidence intervalsHard
σ = 14, n = ?x̄ − Ex̄ + Ex̄E = 490%

The population standard deviation is 14. How large a sample n do you need so that a 90% confidence interval for the mean has a margin of error of at most 4?

σ = 14E = 490%
n =
11.Hypothesis tests & confidence intervalsMedium
2.14p = ?

The mean of a population is claimed to be 500; the population standard deviation is known to be 3. A random sample of 36 observations has a mean of 501.07. Test H₀: μ = 500 against H₁: μ > 500. Find the p-value p.

μ₀ = 500σ = 3n = 36x̄ = 501.07H₁: μ > μ₀
p =
12.Hypothesis tests & confidence intervalsHard
σ = 12, n = ?x̄ − Ex̄ + Ex̄E = 0.595%

How large must a sample be so that the 95% confidence interval for a mean has a margin of error of at most 0.5? The standard deviation is 12. Find the smallest sample size n.

σ = 12E = 0.595%
n =
13.Linear regression & correlationMedium
xy274156258301037xy51010203040

The table gives 5 paired observations of x = load in kN and y = extension in mm. Their sums are given. Find Pearson's correlation coefficient r from these sums.

n = 5Σx = 30Σy = 114Σx² = 220Σy² = 3168Σxy = 834
r =
14.Linear regression & correlationHard
xy253463667885109412106xy5106080100x = 9

The table gives 6 paired observations of x = advertising spend in k€ and y = sales in k€. Use the least-squares line ŷ = a + b·x. Predict ŷ for x = 9.

n = 6x = 9
ŷ =
15.Chi-square testsMedium
yesnoTotalmen4575120women453580Total90110200

The contingency table shows observed counts. Compute the chi-square statistic χ² for the test of independence between the row and column variables. Do not use a continuity correction.

N = 2002 × 2
χ² =
16.Chi-square testsHard
dfα = 0.05α = 0.0113.8416.63525.9919.21037.81511.34549.48813.277511.07015.086612.59216.812714.06718.475815.50720.090916.91921.6661018.30723.209

A chi-square test of independence is carried out on a contingency table with 3 rows and 4 columns (not counting the totals). Using the table, find the critical value χ²crit at significance level α = 0.05.

α = 0.05
χ²crit =

3Solutions

1.Research methods in psychology

Answer: C · Rejects a null hypothesis that is actually true

Why this is the answer

A Type I error claims an effect that does not exist. Its probability equals the significance level (often 0.05). A Type II error misses a real effect.

Answer

C · Rejects a null hypothesis that is actually true
2.Research methods in psychology

Answer: D · Reflects on how their own background and assumptions may shape the analysis

Why this is the answer

Reflexivity acknowledges the researcher's influence on data collection and interpretation, and is a key quality criterion in qualitative work.

Answer

D · Reflects on how their own background and assumptions may shape the analysis
3.Descriptive statistics

Answer: s = 17.25

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 239/5 = 47.8

Squared deviations

Σ(x − x̄)² = 0.2² + 7.2² + (−29.8)² + 11.2² + 11.2² = 1191

Standard deviation

s = √(1191/4) = 17.25

Answer

s = 17.25
4.Descriptive statistics

Answer: z = 2

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (90 − 60)/15 = 2

Answer

z = 2
5.Probability

Answer: Var(X) = 0.7

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Mean

μ = 0·0.35 + 1·0.3 + 2·0.35 = 1

Mean of the squares

E(X²) = 0·0.35 + 1·0.3 + 4·0.35 = 1.7

Variance

Var(X) = 1.7 − 1² = 0.7

Answer

Var(X) = 0.7
6.Probability

Answer: P = 0.09375

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Binomial formula

P(X = 1) = 6·0.51·0.55 = 6·0.5·0.03125 = 0.09375

Answer

P = 0.09375
7.Normal distribution

Answer: P = 0.9063

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (242.75 − 250)/5 = −1.45
z₂ = (260.25 − 250)/5 = 2.05

Area between

P = Φ(2.05) − Φ(−1.45) = 0.9798 − 0.07353 = 0.9063

Answer

P = 0.9063
8.Normal distribution

Answer: x = 259.8 g

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z for the percentile

Φ(z) = 0.975 → z = 1.96

Back to x

x = 250 + 1.96·5 = 259.8 g

Answer

x = 259.8 g
9.Confidence intervals

Answer: E = 11.52

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 5, t = 2.015

Margin of error

E = 2.015·14/√6 = 11.52

Answer

E = 11.52
10.Confidence intervals

Answer: n = 34

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (1.645·14/4)² = 33.15

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 34

Answer

n = 34
11.Hypothesis tests & confidence intervals

Answer: p = 0.01618

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 3/√36 = 0.5
z = (501.07 − 500)/0.5 = 2.14

Tail area

Φ(2.14) = 0.9838
1 − Φ(2.14) = 0.0162

p-value

p = 0.01618

Answer

p = 0.01618

p ≤ 0.05, so H₀ is rejected at the 5% level.

12.Hypothesis tests & confidence intervals

Answer: n = 2213

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Solve for n

n = (1.96·12/0.5)² = 2213

Round up

n = 2213

Answer

n = 2213
13.Linear regression & correlation

Answer: r = 0.9944

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Centred sums

Sxy = 834 − 30·114/5 = 150
Sxx = 220 − 30²/5 = 40
Syy = 3168 − 114²/5 = 568.8

Correlation coefficient

r = 150/√(40·568.8) = 0.9944

Answer

r = 0.9944
14.Linear regression & correlation

Answer: ŷ = 88.74

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 42/6 = 7
ȳ = 468/6 = 78

Sums of squares and products

Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 376

Regression line

b = 376/70 = 5.371
a = 78 − 5.371·7 = 40.4
ŷ = 40.4 + 5.371·x

Prediction

ŷ = 40.4 + 5.371·9 = 88.74

Answer

ŷ = 88.74
15.Chi-square tests

Answer: χ² = 6.818

Chi-square tests: compare observed counts O with the counts E expected under H₀ using χ² = Σ(O − E)²/E. Goodness of fit: E = n·p for each category, df = k − 1 (minus one more for each parameter estimated from the data). Independence in an r × c table: E = row total × column total / grand total, df = (r − 1)(c − 1). Reject H₀ when χ² exceeds the critical value for the chosen α.

Expected counts

men: 120·90/200 = 54, 120·110/200 = 66
women: 80·90/200 = 36, 80·110/200 = 44

Chi-square statistic

χ² = (45 − 54)²/54 + (75 − 66)²/66 + (45 − 36)²/36 + (35 − 44)²/44
χ² = 6.818

Answer

χ² = 6.818

df = 1. At α = 0.05 the critical value is 3.841, so H₀ (independence) is rejected.

16.Chi-square tests

Answer: χ²crit = 12.59

Chi-square tests: compare observed counts O with the counts E expected under H₀ using χ² = Σ(O − E)²/E. Goodness of fit: E = n·p for each category, df = k − 1 (minus one more for each parameter estimated from the data). Independence in an r × c table: E = row total × column total / grand total, df = (r − 1)(c − 1). Reject H₀ when χ² exceeds the critical value for the chosen α.

Degrees of freedom

df = (3 − 1)·(4 − 1) = 6

Table

χ²crit(df = 6, α = 0.05) = 12.592

Answer

χ²crit = 12.592

Reject H₀ if the computed χ² is larger than this value.

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