Research Methods and Statistics for Psychology: cram pack

Formula sheets, the key method steps for every topic and 16 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

Chi-square tests

Test statistic
χ² = Σ(O − E)²/E
Goodness of fit
E = n·p, df = k − 1 − (estimated parameters)
Independence
E = row total × column total / grand total, df = (r − 1)(c − 1)
Critical values (α = 0.05)
df 1: 3.841, 2: 5.991, 3: 7.815, 4: 9.488
Decision
reject H0 if χ² > χ²crit

2Practice problems

1.Research methods in psychologyMedium

A researcher wants to test whether there is an association between gender (male/female) and preferred film genre (four categories). Which test is appropriate?

  1. AChi-square test of independence
  2. BPearson's correlation
  3. CPaired t-test
  4. DOne-way ANOVA
2.Research methods in psychologyHard

Which non-parametric test compares two related samples, such as before-and-after scores on an ordinal scale?

  1. AIndependent t-test
  2. BChi-square test of independence
  3. CMann–Whitney U test
  4. DWilcoxon signed-rank test
3.Descriptive statisticsMedium
1520253035404550

Find the sample standard deviation s of the data: 18, 54, 18, 21, 13, 26.

n = 6
s =
4.Descriptive statisticsHard
z −2−1012

A quantity is normally distributed with mean 170 and standard deviation 20. What proportion P of values is above 150?

μ = 170σ = 20x = 150
P =
5.ProbabilityMedium
P(at least one six) = ??1?2?3?4?5P(six) = 1/6 on each roll

A fair die is rolled 5 times. What is the probability P of getting at least one six?

n = 5
P =
6.ProbabilityHard
n = 8, p = 0.6: P(X = 5) = ?k012345678

A test has 8 multiple-choice questions. A student who guesses gets each one right with probability 0.6, independently. What is the probability P of exactly 5 correct answers?

n = 8p = 0.6k = 5
P =
7.Normal distributionMedium
240252.5P = ?

The bag weights are normally distributed with mean 250 g and standard deviation 5 g. What fraction lies between 240 and 252.5 g? Give P as a decimal.

μ = 250σ = 5x1 = 240x2 = 252.5
P =
8.Normal distributionHard
157164171178185192199cmbottom 40%

The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. Drag the cut-off so the shaded bottom 40% is to the left of it. Find the cut-off x.

μ = 178 cmσ = 7 cm40%
x = cm
9.Confidence intervalsMedium
n = 8, s = 18.5LU = ?x̄ = 64.5E99%

A sample of 8 items has mean 64.5 and standard deviation s = 18.5. The population is roughly normal. Find the upper limit of the 99% confidence interval for the mean.

n = 8x̄ = 64.5s = 18.599%t(7) = 3.499
upper limit =
10.Confidence intervalsHard
p = 0.5, n = ?p̂ − Ep̂ + Ep̂E = 0.02599%

Nothing is known in advance about the proportion of defective products. How many products n must be inspected so that a 99% confidence interval for the proportion has a margin of error of at most 0.025?

p = 0.5E = 0.02599%
n =
11.Hypothesis tests & confidence intervalsMedium
0.8p = ?

The mean of a population is claimed to be 500; the population standard deviation is known to be 48. A random sample of 144 observations has a mean of 503.2. Test H₀: μ = 500 against H₁: μ > 500. Find the p-value p.

μ₀ = 500σ = 48n = 144x̄ = 503.2H₁: μ > μ₀
p =
12.Hypothesis tests & confidence intervalsHard
z −1.9601.96

A sample of 100 measurements has mean 75.6. The population standard deviation is 4. Find the upper limit U of the 95% confidence interval for the mean.

x̄ = 75.6σ = 4n = 10095%
U =
13.Linear regression & correlationMedium
xy14711786201122312926141xy152025100

The table gives 5 paired observations of x = temperature in °C and y = ice creams sold. Find Pearson's correlation coefficient r.

n = 5
r =
14.Linear regression & correlationHard
xy1533635757949106xy56080100x = 2

The table gives 5 paired observations of x = hours studied and y = exam score. Use the least-squares line ŷ = a + b·x. Predict ŷ for x = 2.

n = 5x = 2
ŷ =
15.Chi-square testsMedium
busbikecarTotalstudents19253680staff413544120Total606080200

The contingency table shows observed counts. Compute the chi-square statistic χ² for the test of independence between the row and column variables. Do not use a continuity correction.

N = 2002 × 3
χ² =
16.Chi-square testsHard
dfα = 0.05α = 0.0113.8416.63525.9919.21037.81511.34549.48813.277511.07015.086612.59216.812714.06718.475815.50720.090916.91921.6661018.30723.209

A chi-square goodness-of-fit test compares observed counts in 8 categories with fully specified expected proportions (no parameters are estimated from the data). Using the table, find the critical value χ²crit at significance level α = 0.05.

α = 0.05
χ²crit =

3Solutions

1.Research methods in psychology

Answer: A · Chi-square test of independence

Why this is the answer

The chi-square test compares observed with expected frequencies in a contingency table to test whether two categorical variables are associated.

Answer

A · Chi-square test of independence
2.Research methods in psychology

Answer: D · Wilcoxon signed-rank test

Why this is the answer

The Wilcoxon signed-rank test is for paired ordinal data; Mann–Whitney U is its counterpart for independent groups.

Answer

D · Wilcoxon signed-rank test
3.Descriptive statistics

Answer: s = 14.83

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 150/6 = 25

Squared deviations

Σ(x − x̄)² = (−7)² + 29² + (−7)² + (−4)² + (−12)² + 1² = 1100

Standard deviation

s = √(1100/5) = 14.83

Answer

s = 14.83
4.Descriptive statistics

Answer: P = 0.8413

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = −1

Standard normal table

Φ(−1) = 0.1587
P = 1 − 0.1587 = 0.8413

Answer

P = 0.8413
5.Probability

Answer: P = 0.5981

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Complement

P(no six) = (5/6)5 = 0.4019
P = 1 − 0.4019 = 0.5981

Answer

P = 0.5981
6.Probability

Answer: P = 0.2787

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Binomial formula

P(X = 5) = 56·0.65·0.43 = 56·0.07776·0.064 = 0.2787

Answer

P = 0.2787
7.Normal distribution

Answer: P = 0.6687

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (240 − 250)/5 = −2
z₂ = (252.5 − 250)/5 = 0.5

Area between

P = Φ(0.5) − Φ(−2) = 0.6915 − 0.02275 = 0.6687

Answer

P = 0.6687
8.Normal distribution

Answer: x = 176.3 cm

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left

Φ(z) = 0.4

z from the table

z ≈ −0.25

Back to the original units

x = 178 − 0.25·7 = 176.3 cm

Answer

x = 176.3 cm
9.Confidence intervals

Answer: upper limit = 87.39

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 7, t = 3.499

Margin of error

E = 3.499·18.5/√8 = 22.89

Interval

64.5 ± 22.89 → [41.61, 87.39]

Answer

upper limit = 87.39
10.Confidence intervals

Answer: n = 2655

Confidence interval for a proportion: p̂ ± z·√(p̂(1 − p̂)/n), where p̂ = x/n. To reach a margin E you need n ≥ z²·p(1 − p)/E², rounded up; without a prior estimate use p = 0.5, which gives the largest n.

Solve for n

n = 2.576²·0.5·0.5/0.025² = 2654

Round up

n = 2655

Answer

n = 2655
11.Hypothesis tests & confidence intervals

Answer: p = 0.2119

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 48/√144 = 4
z = (503.2 − 500)/4 = 0.8

Tail area

Φ(0.8) = 0.7881
1 − Φ(0.8) = 0.2119

p-value

p = 0.2119

Answer

p = 0.2119

p > 0.05, so H₀ is not rejected at the 5% level.

12.Hypothesis tests & confidence intervals

Answer: U = 76.38

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Margin of error

E = 1.96·4/√100 = 0.784

Interval limit

U = 75.6 + 0.784 = 76.38

Answer

U = 76.38
13.Linear regression & correlation

Answer: r = 0.9926

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 100/5 = 20
ȳ = 539/5 = 107.8

Sums of squares and products

Sxx = Σ(x − x̄)² = 90
Sxy = Σ(x − x̄)(y − ȳ) = 549
Syy = Σ(y − ȳ)² = 3399

Correlation coefficient

r = 549/√(90·3399) = 0.9926

Answer

r = 0.9926
14.Linear regression & correlation

Answer: ŷ = 57.65

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 25/5 = 5
ȳ = 391/5 = 78.2

Sums of squares and products

Sxx = Σ(x − x̄)² = 40
Sxy = Σ(x − x̄)(y − ȳ) = 274

Regression line

b = 274/40 = 6.85
a = 78.2 − 6.85·5 = 43.95
ŷ = 43.95 + 6.85·x

Prediction

ŷ = 43.95 + 6.85·2 = 57.65

Answer

ŷ = 57.65
15.Chi-square tests

Answer: χ² = 2.639

Chi-square tests: compare observed counts O with the counts E expected under H₀ using χ² = Σ(O − E)²/E. Goodness of fit: E = n·p for each category, df = k − 1 (minus one more for each parameter estimated from the data). Independence in an r × c table: E = row total × column total / grand total, df = (r − 1)(c − 1). Reject H₀ when χ² exceeds the critical value for the chosen α.

Expected counts

students: 80·60/200 = 24, 80·60/200 = 24, 80·80/200 = 32
staff: 120·60/200 = 36, 120·60/200 = 36, 120·80/200 = 48

Chi-square statistic

χ² = (19 − 24)²/24 + (25 − 24)²/24 + (36 − 32)²/32 + (41 − 36)²/36 + (35 − 36)²/36 + (44 − 48)²/48
χ² = 2.639

Answer

χ² = 2.639

df = 2. At α = 0.05 the critical value is 5.991, so H₀ (independence) is not rejected.

16.Chi-square tests

Answer: χ²crit = 14.07

Chi-square tests: compare observed counts O with the counts E expected under H₀ using χ² = Σ(O − E)²/E. Goodness of fit: E = n·p for each category, df = k − 1 (minus one more for each parameter estimated from the data). Independence in an r × c table: E = row total × column total / grand total, df = (r − 1)(c − 1). Reject H₀ when χ² exceeds the critical value for the chosen α.

Degrees of freedom

df = 8 − 1 = 7

Table

χ²crit(df = 7, α = 0.05) = 14.067

Answer

χ²crit = 14.067

Reject H₀ if the computed χ² is larger than this value.

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