Research Methods and Statistics for Psychology: cram pack

Formula sheets, the key method steps for every topic and 16 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

Chi-square tests

Test statistic
χ² = Σ(O − E)²/E
Goodness of fit
E = n·p, df = k − 1 − (estimated parameters)
Independence
E = row total × column total / grand total, df = (r − 1)(c − 1)
Critical values (α = 0.05)
df 1: 3.841, 2: 5.991, 3: 7.815, 4: 9.488
Decision
reject H0 if χ² > χ²crit

2Practice problems

1.Research methods in psychologyMedium

Which test is suitable for comparing the means of two independent groups with interval data that are roughly normal?

  1. APearson correlation
  2. BWilcoxon signed-rank test
  3. CIndependent samples t-test
  4. DChi-square test
2.Research methods in psychologyHard

A study reports t(28) = 2.50, p = .018 for two independent groups of equal size. How many participants took part?

  1. A56
  2. B28
  3. C30
  4. D29
3.Descriptive statisticsMedium
253035404550

Find the sample standard deviation s of the data: 50, 37, 32, 51, 21, 39.

n = 6
s =
4.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 100 and standard deviation 5. Find the z-score z of a score of 92.5.

μ = 100σ = 5x = 92.5
z =
5.ProbabilityMedium
xp(x)00.210.320.230.3μ = 1.6

For the distribution shown, find the variance Var(X) of X.

x: 0, 1, 2, 3p(x): 0.2, 0.3, 0.2, 0.3
Var(X) =
6.ProbabilityHard
n = 5, p = 0.3: P(X = 3) = ?k012345

A test has 5 multiple-choice questions. A student who guesses gets each one right with probability 0.3, independently. What is the probability P of exactly 3 correct answers?

n = 5p = 0.3k = 3
P =
7.Normal distributionMedium
172.4179.75P = ?

The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. What fraction lies between 172.4 and 179.75 cm? Give P as a decimal.

μ = 178σ = 7x1 = 172.4x2 = 179.75
P =
8.Normal distributionHard
μ = 178x = ?99%

The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. Find the value x below which 99% of them lie (the 99th percentile).

μ = 178σ = 7P = 99%
x = cm
9.Confidence intervalsMedium
x̄E₁ = 9.795%, n = 100x̄E₂ = ?95%, n = 25

A 95% confidence interval for a mean, based on 100 observations and a known σ, has a margin of error of 9.7. What is the margin of error E₂ if the same study uses 25 observations instead?

95%n₁ = 100E₁ = 9.7n₂ = 25
E₂ =
10.Confidence intervalsHard
σ = 31, n = ?x̄ − Ex̄ + Ex̄E = 399%

The population standard deviation is 31. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 3?

σ = 31E = 399%
n =
11.Hypothesis tests & confidence intervalsMedium
2.18p = ?

The mean of a population is claimed to be 500; the population standard deviation is known to be 18. A random sample of 144 observations has a mean of 503.27. Test H₀: μ = 500 against H₁: μ > 500. Find the p-value p.

μ₀ = 500σ = 18n = 144x̄ = 503.27H₁: μ > μ₀
p =
12.Hypothesis tests & confidence intervalsHard
z −1.64501.645

A sample of 49 measurements has mean 75.6. The population standard deviation is 5. Find the lower limit L of the 90% confidence interval for the mean.

x̄ = 75.6σ = 5n = 4990%
L =
13.Linear regression & correlationMedium
xy284116178231026xy5101020

The table gives 5 paired observations of x = load in kN and y = extension in mm. Find Pearson's correlation coefficient r.

n = 5
r =
14.Linear regression & correlationHard
xy25045566486310761278xy51050607080x = 3

The table gives 6 paired observations of x = hours studied and y = exam score. Use the least-squares line ŷ = a + b·x. A new observation (3, 51) is made. Find its residual e = y − ŷ.

n = 6(3, 51)
e =
15.Chi-square testsMedium
coughno coughTotalsmokers3189120non-smokers3565100Total66154220

The contingency table shows observed counts. Compute the chi-square statistic χ² for the test of independence between the row and column variables. Do not use a continuity correction.

N = 2202 × 2
χ² =
16.Chi-square testsHard
dfα = 0.05α = 0.0113.8416.63525.9919.21037.81511.34549.48813.277511.07015.086612.59216.812714.06718.475815.50720.090916.91921.6661018.30723.209

A chi-square test of independence is carried out on a contingency table with 2 rows and 4 columns (not counting the totals). Using the table, find the critical value χ²crit at significance level α = 0.01.

α = 0.01
χ²crit =

3Solutions

1.Research methods in psychology

Answer: C · Independent samples t-test

Why this is the answer

The independent t-test compares two group means. Chi-square is for frequencies; Wilcoxon is for related samples with non-parametric data.

Answer

C · Independent samples t-test
2.Research methods in psychology

Answer: C · 30

Why this is the answer

Degrees of freedom of 28 mean 28 + 2 = 30 participants, 15 in each group.

Answer

C · 30
3.Descriptive statistics

Answer: s = 11.31

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 230/6 = 38.33

Squared deviations

Σ(x − x̄)² = 11.67² + (−1.333)² + (−6.333)² + 12.67² + (−17.33)² + 0.6667² = 639.3

Standard deviation

s = √(639.3/5) = 11.31

Answer

s = 11.31
4.Descriptive statistics

Answer: z = −1.5

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (92.5 − 100)/5 = −1.5

Answer

z = −1.5
5.Probability

Answer: Var(X) = 1.24

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Mean

μ = 0·0.2 + 1·0.3 + 2·0.2 + 3·0.3 = 1.6

Mean of the squares

E(X²) = 0·0.2 + 1·0.3 + 4·0.2 + 9·0.3 = 3.8

Variance

Var(X) = 3.8 − 1.6² = 1.24

Answer

Var(X) = 1.24
6.Probability

Answer: P = 0.1323

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Binomial formula

P(X = 3) = 10·0.33·0.72 = 10·0.027·0.49 = 0.1323

Answer

P = 0.1323
7.Normal distribution

Answer: P = 0.3869

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (172.4 − 178)/7 = −0.8
z₂ = (179.75 − 178)/7 = 0.25

Area between

P = Φ(0.25) − Φ(−0.8) = 0.5987 − 0.2119 = 0.3869

Answer

P = 0.3869
8.Normal distribution

Answer: x = 194.3 cm

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z for the percentile

Φ(z) = 0.99 → z = 2.326

Back to x

x = 178 + 2.326·7 = 194.28 cm

Answer

x = 194.28 cm
9.Confidence intervals

Answer: E₂ = 19.4

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Ratio of margins

E₂/E₁ = (1.96/1.96)·√(100/25) = 2

New margin

E₂ = 9.7·2 = 19.4

Answer

E₂ = 19.4
10.Confidence intervals

Answer: n = 709

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (2.576·31/3)² = 708.6

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 709

Answer

n = 709
11.Hypothesis tests & confidence intervals

Answer: p = 0.01463

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 18/√144 = 1.5
z = (503.27 − 500)/1.5 = 2.18

Tail area

Φ(2.18) = 0.9854
1 − Φ(2.18) = 0.0146

p-value

p = 0.01463

Answer

p = 0.01463

p ≤ 0.05, so H₀ is rejected at the 5% level.

12.Hypothesis tests & confidence intervals

Answer: L = 74.42

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Margin of error

E = 1.645·5/√49 = 1.175

Interval limit

L = 75.6 − 1.175 = 74.42

Answer

L = 74.42
13.Linear regression & correlation

Answer: r = 0.9923

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 30/5 = 6
ȳ = 85/5 = 17

Sums of squares and products

Sxx = Σ(x − x̄)² = 40
Sxy = Σ(x − x̄)(y − ȳ) = 96
Syy = Σ(y − ȳ)² = 234

Correlation coefficient

r = 96/√(40·234) = 0.9923

Answer

r = 0.9923
14.Linear regression & correlation

Answer: e = −1.79

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 42/6 = 7
ȳ = 386/6 = 64.33

Sums of squares and products

Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 202

Regression line

b = 202/70 = 2.886
a = 64.33 − 2.886·7 = 44.13
ŷ = 44.13 + 2.886·x

Predicted value

ŷ = 44.13 + 2.886·3 = 52.79

Residual

e = 51 − 52.79 = −1.79

Answer

e = −1.79

The point lies below the line.

15.Chi-square tests

Answer: χ² = 2.183

Chi-square tests: compare observed counts O with the counts E expected under H₀ using χ² = Σ(O − E)²/E. Goodness of fit: E = n·p for each category, df = k − 1 (minus one more for each parameter estimated from the data). Independence in an r × c table: E = row total × column total / grand total, df = (r − 1)(c − 1). Reject H₀ when χ² exceeds the critical value for the chosen α.

Expected counts

smokers: 120·66/220 = 36, 120·154/220 = 84
non-smokers: 100·66/220 = 30, 100·154/220 = 70

Chi-square statistic

χ² = (31 − 36)²/36 + (89 − 84)²/84 + (35 − 30)²/30 + (65 − 70)²/70
χ² = 2.183

Answer

χ² = 2.183

df = 1. At α = 0.05 the critical value is 3.841, so H₀ (independence) is not rejected.

16.Chi-square tests

Answer: χ²crit = 11.35

Chi-square tests: compare observed counts O with the counts E expected under H₀ using χ² = Σ(O − E)²/E. Goodness of fit: E = n·p for each category, df = k − 1 (minus one more for each parameter estimated from the data). Independence in an r × c table: E = row total × column total / grand total, df = (r − 1)(c − 1). Reject H₀ when χ² exceeds the critical value for the chosen α.

Degrees of freedom

df = (2 − 1)·(4 − 1) = 3

Table

χ²crit(df = 3, α = 0.01) = 11.345

Answer

χ²crit = 11.345

Reject H₀ if the computed χ² is larger than this value.

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