Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
35404550

Find the sample standard deviation s of the data: 41, 33, 31, 47, 52.

n = 5
s =
2.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 50 and standard deviation 12. Find the z-score z of a score of 74.

μ = 50σ = 12x = 74
z =
3.ProbabilityMedium
xp(x)00.2510.320.3530.1μ = 1.3

For the distribution shown, find the variance Var(X) of X.

x: 0, 1, 2, 3p(x): 0.25, 0.3, 0.35, 0.1
Var(X) =
4.ProbabilityHard
xp(x)100.1200.2300.35400.35μ

X has the distribution shown, and Y = 5X + 1. Find the standard deviation σY of Y.

x: 10, 20, 30, 40p(x): 0.1, 0.2, 0.35, 0.35Y = 5X + 1
σY =
5.Normal distributionMedium
88123.25P = ?

The IQ scores are normally distributed with mean 100 points and standard deviation 15 points. What fraction lies between 88 and 123.25 points? Give P as a decimal.

μ = 100σ = 15x1 = 88x2 = 123.25
P =
6.Normal distributionHard
235240245250255260265gbottom 80%

The bag weights are normally distributed with mean 250 g and standard deviation 5 g. Drag the cut-off so the shaded bottom 80% is to the left of it. Find the cut-off x.

μ = 250 gσ = 5 g80%
x = g
7.Confidence intervalsMedium
n = 21, s = 17LUx̄ = 86.5E = ?90%

A sample of 21 items has mean 86.5 and standard deviation s = 17. The population is roughly normal. Find the margin of error E of a 90% confidence interval for the mean.

n = 21x̄ = 86.5s = 1790%t(20) = 1.725
E =
8.Confidence intervalsHard
μ₁ − μ₂, t(20) = 2.0860LUx̄₁ − x̄₂E = ?95%

Two fertilisers are tested. Plot group 1: 12 plots, mean yield 90.5 kg, standard deviation 4.5 kg. Plot group 2: 10 plots, mean 86 kg, standard deviation 8.5 kg. Assume equal variances (pooled t, df = n₁ + n₂ − 2). Find the margin of error E of the 95% confidence interval for μ₁ − μ₂.

n₁ = 12x̄₁ = 90.5s₁ = 4.5n₂ = 10x̄₂ = 86s₂ = 8.595%t(20) = 2.086
E = kg
9.Hypothesis tests & confidence intervalsMedium
−2.482.48p = ?

The mean of a population is claimed to be 100; the population standard deviation is known to be 12. A random sample of 64 observations has a mean of 103.72. Test H₀: μ = 100 against H₁: μ ≠ 100. Find the p-value p.

μ₀ = 100σ = 12n = 64x̄ = 103.72H₁: μ ≠ μ₀
p =
10.Hypothesis tests & confidence intervalsHard
H₀H₁μ₀x̄cμ₀ + 1α = 0.05βσ = 11, power 80%, n = ?

A one-sided z test at α = 0.05 must detect a shift of the mean of 1 units with a power of 80%. The standard deviation is 11. Find the minimum sample size n.

α = 0.05power = 80%δ = 1σ = 11zα = 1.645zβ = 0.842
n =
11.Linear regression & correlationMedium
xy12522331741451368xy2461020

The table gives 6 paired observations of x = car age in years and y = price in k€. Their sums are given. Find Pearson's correlation coefficient r from these sums.

n = 6Σx = 21Σy = 100Σx² = 91Σy² = 1872Σxy = 291
r =
12.Linear regression & correlationHard
xy2941461882310281231xy510102030ŷ = 22

The table gives 6 paired observations of x = load in kN and y = extension in mm. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 22?

n = 6ŷ = 22
x =

3Solutions

1.Descriptive statistics

Answer: s = 8.955

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 204/5 = 40.8

Squared deviations

Σ(x − x̄)² = 0.2² + (−7.8)² + (−9.8)² + 6.2² + 11.2² = 320.8

Standard deviation

s = √(320.8/4) = 8.955

Answer

s = 8.955
2.Descriptive statistics

Answer: z = 2

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (74 − 50)/12 = 2

Answer

z = 2
3.Probability

Answer: Var(X) = 0.91

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Mean

μ = 0·0.25 + 1·0.3 + 2·0.35 + 3·0.1 = 1.3

Mean of the squares

E(X²) = 0·0.25 + 1·0.3 + 4·0.35 + 9·0.1 = 2.6

Variance

Var(X) = 2.6 − 1.3² = 0.91

Answer

Var(X) = 0.91
4.Probability

Answer: σY = 48.67

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Spread of X

μ = 29.5, Var(X) = 94.75, σX = 9.734

Linear change

σY = |5|·9.734 = 48.67

Answer

σY = 48.67

The mean does move: E(Y) = 5·29.5 + 1 = 148.5.

5.Normal distribution

Answer: P = 0.7276

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (88 − 100)/15 = −0.8
z₂ = (123.25 − 100)/15 = 1.55

Area between

P = Φ(1.55) − Φ(−0.8) = 0.9394 − 0.2119 = 0.7276

Answer

P = 0.7276
6.Normal distribution

Answer: x = 254.2 g

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left

Φ(z) = 0.8

z from the table

z ≈ 0.84

Back to the original units

x = 250 + 0.84·5 = 254.2 g

Answer

x = 254.2 g
7.Confidence intervals

Answer: E = 6.399

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 20, t = 1.725

Margin of error

E = 1.725·17/√21 = 6.399

Answer

E = 6.399
8.Confidence intervals

Answer: E = 5.901 kg

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Pooled standard deviation

sp² = (11·4.5² + 9·8.5²)/20 = 43.65
sp = 6.607

Margin of error

E = 2.086·6.607·√(1/12 + 1/10) = 5.901

Answer

E = 5.901 kg
9.Hypothesis tests & confidence intervals

Answer: p = 0.01314

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 12/√64 = 1.5
z = (103.72 − 100)/1.5 = 2.48

Tail area

Φ(2.48) = 0.9934
1 − Φ(2.48) = 0.0066

p-value

p = 2·0.0066 = 0.01314

Answer

p = 0.01314

p ≤ 0.05, so H₀ is rejected at the 5% level.

10.Hypothesis tests & confidence intervals

Answer: n = 749

Sample size for a test: to detect a true shift δ with power 1 − β in a one-sided z test at level α, the standard error must satisfy δ = (z_α + z_β)·σ/√n, so n = ((z_α + z_β)·σ/δ)², rounded up.

Solve for n

n = ((1.645 + 0.842)·11/1)² = 748.4

Round up

n = 749

Answer

n = 749
11.Linear regression & correlation

Answer: r = −0.9842

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Centred sums

Sxy = 291 − 21·100/6 = −59
Sxx = 91 − 21²/6 = 17.5
Syy = 1872 − 100²/6 = 205.3

Correlation coefficient

r = −59/√(17.5·205.3) = −0.9842

Answer

r = −0.9842
12.Linear regression & correlation

Answer: x = 7.669

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 42/6 = 7
ȳ = 123/6 = 20.5

Sums of squares and products

Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 157

Regression line

b = 157/70 = 2.243
a = 20.5 − 2.243·7 = 4.8
ŷ = 4.8 + 2.243·x

Solve for x

x = (22 − 4.8)/2.243 = 7.669

Answer

x = 7.669

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