Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
10152025303540455055

Find the sample standard deviation s of the data: 39, 55, 10, 21, 39, 39, 45.

n = 7
s =
2.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 500 and standard deviation 50. Find the z-score z of a score of 425.

μ = 500σ = 50x = 425
z =
3.ProbabilityMedium
xp(x)00.220.3540.1560.3μ = 3.1

For the distribution shown, find the standard deviation σ of X.

x: 0, 2, 4, 6p(x): 0.2, 0.35, 0.15, 0.3
σ =
4.ProbabilityHard
xp(x)00.1510.3520.1530.35μ

X has the distribution shown, and Y = 0.5X + 5. Find the standard deviation σY of Y.

x: 0, 1, 2, 3p(x): 0.15, 0.35, 0.15, 0.35Y = 0.5X + 5
σY =
5.Normal distributionMedium
−3−2−10123zshaded area to the right of z = 0.3336

Drag z so that the shaded area under the standard normal curve, to the right of z, is 0.3336. Find z to two decimals.

A = 0.3336
z =
6.Normal distributionHard
μ = 250x = ?75%

The bag weights are normally distributed with mean 250 g and standard deviation 5 g. Find the value x below which 75% of them lie (the 75th percentile).

μ = 250σ = 5P = 75%
x = g
7.Confidence intervalsMedium
x̄E₁ = 1299%, n = 50x̄E₂ = ?90%, n = 200

A 99% confidence interval for a mean, based on 50 observations and a known σ, has a margin of error of 12. What is the margin of error E₂ of a 90% interval based on 200 observations?

99%n₁ = 50E₁ = 1290%n₂ = 200
E₂ =
8.Confidence intervalsHard
p ≈ 0.8, n = ?p̂ − Ep̂ + Ep̂E = 0.0295%

A pilot study suggests that about 0.8 of products are defective. How many products n must be inspected so that a 95% confidence interval for the proportion has a margin of error of at most 0.02?

p ≈ 0.8E = 0.0295%
n =
9.Hypothesis tests & confidence intervalsMedium
−2.282.28p = ?

The mean of a population is claimed to be 100; the population standard deviation is known to be 32. A random sample of 64 observations has a mean of 90.88. Test H₀: μ = 100 against H₁: μ ≠ 100. Find the p-value p.

μ₀ = 100σ = 32n = 64x̄ = 90.88H₁: μ ≠ μ₀
p =
10.Hypothesis tests & confidence intervalsHard
z −1.64501.645

A sample of 49 measurements has mean 50.5. The population standard deviation is 8. Find the upper limit U of the 90% confidence interval for the mean.

x̄ = 50.5σ = 8n = 4990%
U =
11.Linear regression & correlationMedium
xy127227325426521619xy2462025

The table gives 6 paired observations of x = car age in years and y = price in k€. Find the coefficient of determination r² of the least-squares line.

n = 6
r² =
12.Linear regression & correlationHard
xy127228326423520xy242025ŷ = 24

The table gives 5 paired observations of x = car age in years and y = price in k€. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 24?

n = 5ŷ = 24
x =

3Solutions

1.Descriptive statistics

Answer: s = 15.1

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 248/7 = 35.43

Squared deviations

Σ(x − x̄)² = 3.571² + 19.57² + (−25.43)² + (−14.43)² + 3.571² + 3.571² + 9.571² = 1368

Standard deviation

s = √(1368/6) = 15.1

Answer

s = 15.1
2.Descriptive statistics

Answer: z = −1.5

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (425 − 500)/50 = −1.5

Answer

z = −1.5
3.Probability

Answer: σ = 2.234

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Mean

μ = 0·0.2 + 2·0.35 + 4·0.15 + 6·0.3 = 3.1

Mean of the squares

E(X²) = 0·0.2 + 4·0.35 + 16·0.15 + 36·0.3 = 14.6

Variance

Var(X) = 14.6 − 3.1² = 4.99
σ = √4.99 = 2.234

Answer

σ = 2.234
4.Probability

Answer: σY = 0.55

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Spread of X

μ = 1.7, Var(X) = 1.21, σX = 1.1

Linear change

σY = |0.5|·1.1 = 0.55

Answer

σY = 0.55

The mean does move: E(Y) = 0.5·1.7 + 5 = 5.85.

5.Normal distribution

Answer: z = 0.43

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left of z

Φ(z) = 1 − 0.3336 = 0.6664

Read the z-table backwards

Find 0.6664 inside the table and read off z.

z = 0.43

Answer

z = 0.43
6.Normal distribution

Answer: x = 253.4 g

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z for the percentile

Φ(z) = 0.75 → z = 0.6745

Back to x

x = 250 + 0.6745·5 = 253.37 g

Answer

x = 253.37 g
7.Confidence intervals

Answer: E₂ = 3.832

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Ratio of margins

E₂/E₁ = (1.645/2.576)·√(50/200) = 0.3193

New margin

E₂ = 12·0.3193 = 3.832

Answer

E₂ = 3.832
8.Confidence intervals

Answer: n = 1537

Confidence interval for a proportion: p̂ ± z·√(p̂(1 − p̂)/n), where p̂ = x/n. To reach a margin E you need n ≥ z²·p(1 − p)/E², rounded up; without a prior estimate use p = 0.5, which gives the largest n.

Solve for n

n = 1.96²·0.8·0.2/0.02² = 1537

Round up

n = 1537

Answer

n = 1537
9.Hypothesis tests & confidence intervals

Answer: p = 0.02261

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 32/√64 = 4
z = (90.88 − 100)/4 = −2.28

Tail area

Φ(2.28) = 0.9887
1 − Φ(2.28) = 0.0113

p-value

p = 2·0.0113 = 0.02261

Answer

p = 0.02261

p ≤ 0.05, so H₀ is rejected at the 5% level.

10.Hypothesis tests & confidence intervals

Answer: U = 52.38

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Margin of error

E = 1.645·8/√49 = 1.88

Interval limit

U = 50.5 + 1.88 = 52.38

Answer

U = 52.38
11.Linear regression & correlation

Answer: r² = 0.8167

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 21/6 = 3.5
ȳ = 145/6 = 24.17

Sums of squares and products

Sxx = Σ(x − x̄)² = 17.5
Sxy = Σ(x − x̄)(y − ȳ) = −28.5
Syy = Σ(y − ȳ)² = 56.83

Coefficient of determination

r² = −28.5²/(17.5·56.83) = 0.8167

Answer

r² = 0.8167

About 81.67% of the variation in y is explained by the line.

12.Linear regression & correlation

Answer: x = 3.421

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 15/5 = 3
ȳ = 124/5 = 24.8

Sums of squares and products

Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = −19

Regression line

b = −19/10 = −1.9
a = 24.8 − (−1.9)·3 = 30.5
ŷ = 30.5 − 1.9·x

Solve for x

x = (24 − 30.5)/(−1.9) = 3.421

Answer

x = 3.421

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