Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
15202530354045

Find the sample standard deviation s of the data: 13, 34, 44, 20, 19, 46.

n = 6
s =
2.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 50 and standard deviation 10. Find the z-score z of a score of 35.

μ = 50σ = 10x = 35
z =
3.ProbabilityMedium
n = 10k = 5N = ?

In how many ways N can a committee of 5 people be chosen from a group of 10? The order does not matter.

n = 10k = 5
N =
4.ProbabilityHard
xp(x)00.3510.320.0530.3μ

X has the distribution shown, and Y = 0.5X + 5. Find the standard deviation σY of Y.

x: 0, 1, 2, 3p(x): 0.35, 0.3, 0.05, 0.3Y = 0.5X + 5
σY =
5.Normal distributionMedium
175.9179.75P = ?

The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. What fraction lies between 175.9 and 179.75 cm? Give P as a decimal.

μ = 178σ = 7x1 = 175.9x2 = 179.75
P =
6.Normal distributionHard
235240245250255260265gtop 15%

The bag weights are normally distributed with mean 250 g and standard deviation 5 g. Drag the cut-off so the shaded top 15% is to the right of it. Find the cut-off x.

μ = 250 gσ = 5 g15%
x = g
7.Confidence intervalsMedium
n = 11, s = 1.5L = ?Ux̄ = 88E95%

A sample of 11 items has mean 88 and standard deviation s = 1.5. The population is roughly normal. Find the lower limit of the 95% confidence interval for the mean.

n = 11x̄ = 88s = 1.595%t(10) = 2.228
lower limit =
8.Confidence intervalsHard
p = 0.5, n = ?p̂ − Ep̂ + Ep̂E = 0.0490%

Nothing is known in advance about the proportion of defective products. How many products n must be inspected so that a 90% confidence interval for the proportion has a margin of error of at most 0.04?

p = 0.5E = 0.0490%
n =
9.Hypothesis tests & confidence intervalsMedium
−2.0862.086t = ?df = 20

Two teaching methods are compared. Group 1: 9 students, mean score 47, standard deviation 7.5. Group 2: 13 students, mean score 38.6, standard deviation 9. Assume equal population variances and use the pooled two-sample t test. Find the test statistic t for H₀: μ₁ = μ₂, taking the difference as x̄₁ − x̄₂ (group 1 minus group 2).

n₁ = 9x̄₁ = 47s₁ = 7.5n₂ = 13x̄₂ = 38.6s₂ = 9
t =
10.Hypothesis tests & confidence intervalsHard
z −1.9601.96

A sample of 64 measurements has mean 52.8. The population standard deviation is 20. Find the lower limit L of the 95% confidence interval for the mean.

x̄ = 52.8σ = 20n = 6495%
L =
11.Linear regression & correlationMedium
xy25446568389710104xy5106080100

The table gives 5 paired observations of x = hours studied and y = exam score. Find the coefficient of determination r² of the least-squares line.

n = 5
r² =
12.Linear regression & correlationHard
xy128222321420518614xy246152025x = 4.5

The table gives 6 paired observations of x = car age in years and y = price in k€. Use the least-squares line ŷ = a + b·x. A new observation (4.5, 23) is made. Find its residual e = y − ŷ.

n = 6(4.5, 23)
e =

3Solutions

1.Descriptive statistics

Answer: s = 13.97

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 176/6 = 29.33

Squared deviations

Σ(x − x̄)² = (−16.33)² + 4.667² + 14.67² + (−9.333)² + (−10.33)² + 16.67² = 975.3

Standard deviation

s = √(975.3/5) = 13.97

Answer

s = 13.97
2.Descriptive statistics

Answer: z = −1.5

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (35 − 50)/10 = −1.5

Answer

z = −1.5
3.Probability

Answer: N = 252

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Combinations

C(10, 5) = (10·9·8·7·6)/(5·4·3·2·1) = 252

Answer

N = 252
4.Probability

Answer: σY = 0.6144

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Spread of X

μ = 1.3, Var(X) = 1.51, σX = 1.229

Linear change

σY = |0.5|·1.229 = 0.6144

Answer

σY = 0.6144

The mean does move: E(Y) = 0.5·1.3 + 5 = 5.65.

5.Normal distribution

Answer: P = 0.2166

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (175.9 − 178)/7 = −0.3
z₂ = (179.75 − 178)/7 = 0.25

Area between

P = Φ(0.25) − Φ(−0.3) = 0.5987 − 0.3821 = 0.2166

Answer

P = 0.2166
6.Normal distribution

Answer: x = 255.2 g

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left

Φ(z) = 0.85

z from the table

z ≈ 1.04

Back to the original units

x = 250 + 1.04·5 = 255.2 g

Answer

x = 255.2 g
7.Confidence intervals

Answer: lower limit = 86.99

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 10, t = 2.228

Margin of error

E = 2.228·1.5/√11 = 1.008

Interval

88 ± 1.008 → [86.99, 89.01]

Answer

lower limit = 86.99
8.Confidence intervals

Answer: n = 423

Confidence interval for a proportion: p̂ ± z·√(p̂(1 − p̂)/n), where p̂ = x/n. To reach a margin E you need n ≥ z²·p(1 − p)/E², rounded up; without a prior estimate use p = 0.5, which gives the largest n.

Solve for n

n = 1.645²·0.5·0.5/0.04² = 422.8

Round up

n = 423

Answer

n = 423
9.Hypothesis tests & confidence intervals

Answer: t = 2.297

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Pooled variance

sp² = (8·7.5² + 12·9²)/20 = 71.1
sp = 8.432

Standard error

SE = 8.432·√(1/9 + 1/13) = 3.656

Test statistic

t = (47 − 38.6)/3.656 = 2.297

Answer

t = 2.297

With df = 20, the two-sided 5% critical value is 2.086; |t| is larger, so H₀ is rejected.

10.Hypothesis tests & confidence intervals

Answer: L = 47.9

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Margin of error

E = 1.96·20/√64 = 4.9

Interval limit

L = 52.8 − 4.9 = 47.9

Answer

L = 47.9
11.Linear regression & correlation

Answer: r² = 0.9826

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 30/5 = 6
ȳ = 403/5 = 80.6

Sums of squares and products

Sxx = Σ(x − x̄)² = 40
Sxy = Σ(x − x̄)(y − ȳ) = 264
Syy = Σ(y − ȳ)² = 1773

Coefficient of determination

r² = 264²/(40·1773) = 0.9826

Answer

r² = 0.9826

About 98.26% of the variation in y is explained by the line.

12.Linear regression & correlation

Answer: e = 4.871

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 21/6 = 3.5
ȳ = 123/6 = 20.5

Sums of squares and products

Sxx = Σ(x − x̄)² = 17.5
Sxy = Σ(x − x̄)(y − ȳ) = −41.5

Regression line

b = −41.5/17.5 = −2.371
a = 20.5 − (−2.371)·3.5 = 28.8
ŷ = 28.8 − 2.371·x

Predicted value

ŷ = 28.8 + (−2.371)·4.5 = 18.13

Residual

e = 23 − 18.13 = 4.871

Answer

e = 4.871

The point lies above the line.

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