Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
2530354045505560

Find the sample standard deviation s of the data: 25, 26, 22, 53, 39, 60.

n = 6
s =
2.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 60 and standard deviation 10. Find the z-score z of a score of 55.

μ = 60σ = 10x = 55
z =
3.ProbabilityMedium
red: 6blue: 7

A bag holds 6 red and 7 blue balls. You draw two balls without putting the first one back. What is the probability P that both are red?

6 / 7
P =
4.ProbabilityHard
€p(x)−30.8490.151470.01

A game costs €3 to play. You win €12 with probability 0.15 and €150 with probability 0.01; otherwise you win nothing. The stake is not returned. Find the expected net gain E(G) per game.

stake = €3€12: p = 0.15€150: p = 0.01
E(G) = €
5.Normal distributionMedium
32.344.3P = ?

The delivery times are normally distributed with mean 32 min and standard deviation 6 min. What fraction lies between 32.3 and 44.3 min? Give P as a decimal.

μ = 32σ = 6x1 = 32.3x2 = 44.3
P =
6.Normal distributionHard
35455565758595pointsbottom 75%

The exam scores are normally distributed with mean 65 points and standard deviation 10 points. Drag the cut-off so the shaded bottom 75% is to the left of it. Find the cut-off x.

μ = 65 pointsσ = 10 points75%
x = points
7.Confidence intervalsMedium
n = 25, s = 1.5LUx̄ = 75E = ?95%

A sample of 25 items has mean 75 and standard deviation s = 1.5. The population is roughly normal. Find the margin of error E of a 95% confidence interval for the mean.

n = 25x̄ = 75s = 1.595%t(24) = 2.064
E =
8.Confidence intervalsHard
σ = 17, n = ?x̄ − Ex̄ + Ex̄E = 1.590%

The population standard deviation is 17. How large a sample n do you need so that a 90% confidence interval for the mean has a margin of error of at most 1.5?

σ = 17E = 1.590%
n =
9.Hypothesis tests & confidence intervalsMedium
−2.4p = ?

The mean of a population is claimed to be 120; the population standard deviation is known to be 24. A random sample of 64 observations has a mean of 112.8. Test H₀: μ = 120 against H₁: μ < 120. Find the p-value p.

μ₀ = 120σ = 24n = 64x̄ = 112.8H₁: μ < μ₀
p =
10.Hypothesis tests & confidence intervalsHard
σ = 8, n = ?x̄ − Ex̄ + Ex̄E = 0.599%

How large must a sample be so that the 99% confidence interval for a mean has a margin of error of at most 0.5? The standard deviation is 8. Find the smallest sample size n.

σ = 8E = 0.599%
n =
11.Linear regression & correlationMedium
xy355464567666778xy46607080

The table gives 5 paired observations of x = hours studied and y = exam score. Find the coefficient of determination r² of the least-squares line.

n = 5
r² =
12.Linear regression & correlationHard
xy123221321419514xy241520x = 1.5

The table gives 5 paired observations of x = car age in years and y = price in k€. Use the least-squares line ŷ = a + b·x. A new observation (1.5, 25) is made. Find its residual e = y − ŷ.

n = 5(1.5, 25)
e =

3Solutions

1.Descriptive statistics

Answer: s = 15.98

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 225/6 = 37.5

Squared deviations

Σ(x − x̄)² = (−12.5)² + (−11.5)² + (−15.5)² + 15.5² + 1.5² + 22.5² = 1278

Standard deviation

s = √(1278/5) = 15.98

Answer

s = 15.98
2.Descriptive statistics

Answer: z = −0.5

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (55 − 60)/10 = −0.5

Answer

z = −0.5
3.Probability

Answer: P = 0.1923

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

First and second draw

P = 6/13 · 5/12 = 30/156 = 0.1923

Answer

P = 0.1923
4.Probability

Answer: E(G) = 0.3 €

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Net outcomes

G: 9 (p = 0.15), 147 (p = 0.01), −3 (p = 0.84)

Expected value

E(G) = 9·0.15 + 147·0.01 − 3·0.84 = 0.3 €

Answer

E(G) = 0.3 €

A positive value means you win money on average.

5.Normal distribution

Answer: P = 0.4599

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (32.3 − 32)/6 = 0.05
z₂ = (44.3 − 32)/6 = 2.05

Area between

P = Φ(2.05) − Φ(0.05) = 0.9798 − 0.5199 = 0.4599

Answer

P = 0.4599
6.Normal distribution

Answer: x = 71.7 points

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left

Φ(z) = 0.75

z from the table

z ≈ 0.67

Back to the original units

x = 65 + 0.67·10 = 71.7 points

Answer

x = 71.7 points
7.Confidence intervals

Answer: E = 0.6192

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 24, t = 2.064

Margin of error

E = 2.064·1.5/√25 = 0.6192

Answer

E = 0.6192
8.Confidence intervals

Answer: n = 348

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (1.645·17/1.5)² = 347.6

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 348

Answer

n = 348
9.Hypothesis tests & confidence intervals

Answer: p = 0.008198

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 24/√64 = 3
z = (112.8 − 120)/3 = −2.4

Tail area

Φ(2.4) = 0.9918
1 − Φ(2.4) = 0.0082

p-value

p = 0.008198

Answer

p = 0.008198

p ≤ 0.05, so H₀ is rejected at the 5% level.

10.Hypothesis tests & confidence intervals

Answer: n = 1699

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Solve for n

n = (2.576·8/0.5)² = 1699

Round up

n = 1699

Answer

n = 1699
11.Linear regression & correlation

Answer: r² = 0.8533

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 25/5 = 5
ȳ = 330/5 = 66

Sums of squares and products

Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = 48
Syy = Σ(y − ȳ)² = 270

Coefficient of determination

r² = 48²/(10·270) = 0.8533

Answer

r² = 0.8533

About 85.33% of the variation in y is explained by the line.

12.Linear regression & correlation

Answer: e = 2.4

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 15/5 = 3
ȳ = 98/5 = 19.6

Sums of squares and products

Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = −20

Regression line

b = −20/10 = −2
a = 19.6 − (−2)·3 = 25.6
ŷ = 25.6 − 2·x

Predicted value

ŷ = 25.6 + (−2)·1.5 = 22.6

Residual

e = 25 − 22.6 = 2.4

Answer

e = 2.4

The point lies above the line.

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