Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
2025303540455055

Find the sample standard deviation s of the data: 22, 45, 44, 17, 58, 52.

n = 6
s =
2.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 500 and standard deviation 60. Find the z-score z of a score of 536.

μ = 500σ = 60x = 536
z =
3.ProbabilityMedium
n = 10k = 5N = ?

In how many ways N can a committee of 5 people be chosen from a group of 10? The order does not matter.

n = 10k = 5
N =
4.ProbabilityHard
€p(x)−10.8410.15190.01

A game costs €1 to play. You win €2 with probability 0.15 and €20 with probability 0.01; otherwise you win nothing. The stake is not returned. Find the expected net gain E(G) per game.

stake = €1€2: p = 0.15€20: p = 0.01
E(G) = €
5.Normal distributionMedium
164186.4P = ?

The heights of adult men are normally distributed with mean 178 cm and standard deviation 7 cm. What fraction lies between 164 and 186.4 cm? Give P as a decimal.

μ = 178σ = 7x1 = 164x2 = 186.4
P =
6.Normal distributionHard
35455565758595pointsbottom 40%

The exam scores are normally distributed with mean 65 points and standard deviation 10 points. Drag the cut-off so the shaded bottom 40% is to the left of it. Find the cut-off x.

μ = 65 pointsσ = 10 points40%
x = points
7.Confidence intervalsMedium
n = 11, s = 18LUx̄ = 100.5E = ?95%

A sample of 11 items has mean 100.5 and standard deviation s = 18. The population is roughly normal. Find the margin of error E of a 95% confidence interval for the mean.

n = 11x̄ = 100.5s = 1895%t(10) = 2.228
E =
8.Confidence intervalsHard
σ = 11, n = ?x̄ − Ex̄ + Ex̄E = 0.599%

The population standard deviation is 11. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 0.5?

σ = 11E = 0.599%
n =
9.Hypothesis tests & confidence intervalsMedium
−2.282.28p = ?

The mean of a population is claimed to be 100; the population standard deviation is known to be 24. A random sample of 144 observations has a mean of 95.44. Test H₀: μ = 100 against H₁: μ ≠ 100. Find the p-value p.

μ₀ = 100σ = 24n = 144x̄ = 95.44H₁: μ ≠ μ₀
p =
10.Hypothesis tests & confidence intervalsHard
μ₀x̄c

A one-sided z test of H₀: μ = 50 against H₁: μ > 50 is done at α = 0.05 with a sample of 64; the standard deviation is known to be 12. In reality the mean is 52.4. Find the probability of a Type II error β in percent.

μ₀ = 50μ = 52.4σ = 12n = 64α = 0.05
β = %
11.Linear regression & correlationMedium
xy360573788910311112xy5106080100

The table gives 5 paired observations of x = hours studied and y = exam score. Find Pearson's correlation coefficient r.

n = 5
r =
12.Linear regression & correlationHard
xy15421852216924762792xy152025406080ŷ = 48

The table gives 5 paired observations of x = temperature in °C and y = ice creams sold. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 48?

n = 5ŷ = 48
x =

3Solutions

1.Descriptive statistics

Answer: s = 16.5

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 238/6 = 39.67

Squared deviations

Σ(x − x̄)² = (−17.67)² + 5.333² + 4.333² + (−22.67)² + 18.33² + 12.33² = 1361

Standard deviation

s = √(1361/5) = 16.5

Answer

s = 16.5
2.Descriptive statistics

Answer: z = 0.6

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (536 − 500)/60 = 0.6

Answer

z = 0.6
3.Probability

Answer: N = 252

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Combinations

C(10, 5) = (10·9·8·7·6)/(5·4·3·2·1) = 252

Answer

N = 252
4.Probability

Answer: E(G) = −0.5 €

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Net outcomes

G: 1 (p = 0.15), 19 (p = 0.01), −1 (p = 0.84)

Expected value

E(G) = 1·0.15 + 19·0.01 − 1·0.84 = −0.5 €

Answer

E(G) = −0.5 €

A negative value means you lose money on average.

5.Normal distribution

Answer: P = 0.8622

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (164 − 178)/7 = −2
z₂ = (186.4 − 178)/7 = 1.2

Area between

P = Φ(1.2) − Φ(−2) = 0.8849 − 0.02275 = 0.8622

Answer

P = 0.8622
6.Normal distribution

Answer: x = 62.5 points

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left

Φ(z) = 0.4

z from the table

z ≈ −0.25

Back to the original units

x = 65 − 0.25·10 = 62.5 points

Answer

x = 62.5 points
7.Confidence intervals

Answer: E = 12.09

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 10, t = 2.228

Margin of error

E = 2.228·18/√11 = 12.09

Answer

E = 12.09
8.Confidence intervals

Answer: n = 3212

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (2.576·11/0.5)² = 3212

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 3212

Answer

n = 3212
9.Hypothesis tests & confidence intervals

Answer: p = 0.02261

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 24/√144 = 2
z = (95.44 − 100)/2 = −2.28

Tail area

Φ(2.28) = 0.9887
1 − Φ(2.28) = 0.0113

p-value

p = 2·0.0113 = 0.02261

Answer

p = 0.02261

p ≤ 0.05, so H₀ is rejected at the 5% level.

10.Hypothesis tests & confidence intervals

Answer: β = 51.79 %

Power of a test: power = 1 − β is the probability of rejecting H₀ when it is false. Find the cutoff x̄c from μ₀ and z_α, then compute the probability of landing beyond x̄c using the true mean: z = (x̄c − μ)/(σ/√n).

Critical sample mean

SE = 12/√64 = 1.5
x̄c = 50 + 1.645·1.5 = 52.47

z under the true mean

z = (52.47 − 52.4)/1.5 = 0.045

Type II error

power = P(Z > 0.045) = 48.21%
β = 100% − 48.21% = 51.79%

Answer

β = 51.79%
11.Linear regression & correlation

Answer: r = 0.9969

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 35/5 = 7
ȳ = 436/5 = 87.2

Sums of squares and products

Sxx = Σ(x − x̄)² = 40
Sxy = Σ(x − x̄)(y − ȳ) = 268
Syy = Σ(y − ȳ)² = 1807

Correlation coefficient

r = 268/√(40·1807) = 0.9969

Answer

r = 0.9969
12.Linear regression & correlation

Answer: x = 16.6

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 105/5 = 21
ȳ = 331/5 = 66.2

Sums of squares and products

Sxx = Σ(x − x̄)² = 90
Sxy = Σ(x − x̄)(y − ȳ) = 372

Regression line

b = 372/90 = 4.133
a = 66.2 − 4.133·21 = −20.6
ŷ = −20.6 + 4.133·x

Solve for x

x = (48 − (−20.6))/4.133 = 16.6

Answer

x = 16.6

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