Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
303540455055

Find the sample standard deviation s of the data: 32, 29, 55, 54, 32, 33.

n = 6
s =
2.Descriptive statisticsHard
z −2−1012

A quantity is normally distributed with mean 170 and standard deviation 8. What proportion P of values is below 154?

μ = 170σ = 8x = 154
P =
3.ProbabilityMedium
xp(x)00.210.320.0530.140.35μ = 2.1

For the distribution shown, find the variance Var(X) of X.

x: 0, 1, 2, 3, 4p(x): 0.2, 0.3, 0.05, 0.1, 0.35
Var(X) =
4.ProbabilityHard
n = 8, p = 0.1: P(X = 3) = ?k012345678

A test has 8 multiple-choice questions. A student who guesses gets each one right with probability 0.1, independently. What is the probability P of exactly 3 correct answers?

n = 8p = 0.1k = 3
P =
5.Normal distributionMedium
−3−2−10123zshaded area to the right of z = 0.8749

Drag z so that the shaded area under the standard normal curve, to the right of z, is 0.8749. Find z to two decimals.

A = 0.8749
z =
6.Normal distributionHard
μ = 32x = ?10%

The delivery times are normally distributed with mean 32 min and standard deviation 6 min. Find the value x below which 10% of them lie (the 10th percentile).

μ = 32σ = 6P = 10%
x = min
7.Confidence intervalsMedium
x̄E₁ = 2.695%, n = 64x̄E₂ = ?90%, n = 64

A 95% confidence interval for a mean, based on 64 observations and a known σ, has a margin of error of 2.6. What is the margin of error E₂ of a 90% interval from the same data?

95%n₁ = 64E₁ = 2.690%
E₂ =
8.Confidence intervalsHard
σ = 20, n = ?x̄ − Ex̄ + Ex̄E = 0.595%

The population standard deviation is 20. How large a sample n do you need so that a 95% confidence interval for the mean has a margin of error of at most 0.5?

σ = 20E = 0.595%
n =
9.Hypothesis tests & confidence intervalsMedium
−2.2622.262t = ?df = 9

10 employees take a typing test before and after a training course. For each person the difference d = after − before (words per minute) is recorded. The mean difference is −5.91 and the standard deviation of the differences is 5.5. Find the paired test statistic t for H₀: μd = 0.

n = 10d̄ = −5.91sd = 5.5
t =
10.Hypothesis tests & confidence intervalsHard
μ₀x̄c

A one-sided z test of H₀: μ = 500 against H₁: μ < 500 is done at α = 0.05 with a sample of 36; the standard deviation is known to be 9. In reality the mean is 498.05. Find the probability of a Type II error β in percent.

μ₀ = 500μ = 498.05σ = 9n = 36α = 0.05
β = %
11.Linear regression & correlationMedium
xy126226322421519617xy2462025

The table gives 6 paired observations of x = car age in years and y = price in k€. Their sums are given. Find Pearson's correlation coefficient r from these sums.

n = 6Σx = 21Σy = 131Σx² = 91Σy² = 2927Σxy = 425
r =
12.Linear regression & correlationHard
xy1373395537609591170xy5104060x = 4

The table gives 6 paired observations of x = advertising spend in k€ and y = sales in k€. Use the least-squares line ŷ = a + b·x. A new observation (4, 42) is made. Find its residual e = y − ŷ.

n = 6(4, 42)
e =

3Solutions

1.Descriptive statistics

Answer: s = 11.96

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 235/6 = 39.17

Squared deviations

Σ(x − x̄)² = (−7.167)² + (−10.17)² + 15.83² + 14.83² + (−7.167)² + (−6.167)² = 714.8

Standard deviation

s = √(714.8/5) = 11.96

Answer

s = 11.96
2.Descriptive statistics

Answer: P = 0.02275

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = −2

Standard normal table

Φ(−2) = 0.02275
P = 0.02275

Answer

P = 0.02275
3.Probability

Answer: Var(X) = 2.59

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Mean

μ = 0·0.2 + 1·0.3 + 2·0.05 + 3·0.1 + 4·0.35 = 2.1

Mean of the squares

E(X²) = 0·0.2 + 1·0.3 + 4·0.05 + 9·0.1 + 16·0.35 = 7

Variance

Var(X) = 7 − 2.1² = 2.59

Answer

Var(X) = 2.59
4.Probability

Answer: P = 0.03307

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Binomial formula

P(X = 3) = 56·0.13·0.95 = 56·0.001·0.5905 = 0.03307

Answer

P = 0.03307
5.Normal distribution

Answer: z = −1.15

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left of z

Φ(z) = 1 − 0.8749 = 0.1251

Read the z-table backwards

Find 0.1251 inside the table and read off z.

z = −1.15

Answer

z = −1.15
6.Normal distribution

Answer: x = 24.31 min

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z for the percentile

Φ(z) = 0.1 → z = −1.282

Back to x

x = 32 + −1.282·6 = 24.31 min

Answer

x = 24.31 min
7.Confidence intervals

Answer: E₂ = 2.182

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Ratio of margins

E₂/E₁ = (1.645/1.96)·√(64/64) = 0.8393

New margin

E₂ = 2.6·0.8393 = 2.182

Answer

E₂ = 2.182
8.Confidence intervals

Answer: n = 6147

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (1.96·20/0.5)² = 6147

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 6147

Answer

n = 6147
9.Hypothesis tests & confidence intervals

Answer: t = −3.398

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Standard error of the mean difference

SE = 5.5/√10 = 1.739

Test statistic

t = −5.91/1.739 = −3.398

Answer

t = −3.398

With df = 9, the two-sided 5% critical value is 2.262; |t| is larger, so H₀ is rejected.

10.Hypothesis tests & confidence intervals

Answer: β = 63.5 %

Power of a test: power = 1 − β is the probability of rejecting H₀ when it is false. Find the cutoff x̄c from μ₀ and z_α, then compute the probability of landing beyond x̄c using the true mean: z = (x̄c − μ)/(σ/√n).

Critical sample mean

SE = 9/√36 = 1.5
x̄c = 500 − 1.645·1.5 = 497.5

z under the true mean

z = (497.5 − 498.05)/1.5 = −0.345

Type II error

power = P(Z < −0.345) = 36.5%
β = 100% − 36.5% = 63.5%

Answer

β = 63.5%
11.Linear regression & correlation

Answer: r = −0.9796

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Centred sums

Sxy = 425 − 21·131/6 = −33.5
Sxx = 91 − 21²/6 = 17.5
Syy = 2927 − 131²/6 = 66.83

Correlation coefficient

r = −33.5/√(17.5·66.83) = −0.9796

Answer

r = −0.9796
12.Linear regression & correlation

Answer: e = −4.371

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 36/6 = 6
ȳ = 318/6 = 53

Sums of squares and products

Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 232

Regression line

b = 232/70 = 3.314
a = 53 − 3.314·6 = 33.11
ŷ = 33.11 + 3.314·x

Predicted value

ŷ = 33.11 + 3.314·4 = 46.37

Residual

e = 42 − 46.37 = −4.371

Answer

e = −4.371

The point lies below the line.

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