Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
2530354045505560

Find the sample standard deviation s of the data: 47, 58, 24, 35, 54, 24, 60.

n = 7
s =
2.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 70 and standard deviation 5. Find the z-score z of a score of 72.

μ = 70σ = 5x = 72
z =
3.ProbabilityMedium
red: 6blue: 7

A bag holds 6 red and 7 blue balls. You draw two balls without putting the first one back. What is the probability P that both are red?

6 / 7
P =
4.ProbabilityHard
n = 5, p = 0.3: P(X ≤ 1) = ?k012345

5 components are tested, and each one fails with probability 0.3, independently. What is the probability P that at most one fails?

n = 5p = 0.3
P =
5.Normal distributionMedium
−3−2−10123zshaded area between −z and z = 0.9233

Drag z so that the shaded area between −z and z under the standard normal curve is 0.9233. Find z to two decimals.

A = 0.9233
z =
6.Normal distributionHard
380420460500540580620htop 95%

The battery lifetimes are normally distributed with mean 500 h and standard deviation 40 h. Drag the cut-off so the shaded top 95% is to the right of it. Find the cut-off x.

μ = 500 hσ = 40 h95%
x = h
7.Confidence intervalsMedium
n = 21, s = 13L = ?Ux̄ = 66E99%

A sample of 21 items has mean 66 and standard deviation s = 13. The population is roughly normal. Find the lower limit of the 99% confidence interval for the mean.

n = 21x̄ = 66s = 1399%t(20) = 2.845
lower limit =
8.Confidence intervalsHard
μ₁ − μ₂, t(15) = 2.1310LUx̄₁ − x̄₂E = ?95%

Two fertilisers are tested. Plot group 1: 12 plots, mean yield 13.5 kg, standard deviation 7.5 kg. Plot group 2: 5 plots, mean 22.5 kg, standard deviation 1 kg. Assume equal variances (pooled t, df = n₁ + n₂ − 2). Find the margin of error E of the 95% confidence interval for μ₁ − μ₂.

n₁ = 12x̄₁ = 13.5s₁ = 7.5n₂ = 5x̄₂ = 22.5s₂ = 195%t(15) = 2.131
E = kg
9.Hypothesis tests & confidence intervalsMedium
−1.961.96z = ?

Two production lines make the same part. Line 1: a sample of 60 parts has mean length 135.5 mm, and the line's known standard deviation is 20 mm. Line 2: a sample of 30 parts has mean 141.7 mm, known standard deviation 16 mm. Find the test statistic z for H₀: μ₁ = μ₂, taking the difference as x̄₁ − x̄₂ (line 1 minus line 2).

n₁ = 60x̄₁ = 135.5 mmσ₁ = 20 mmn₂ = 30x̄₂ = 141.7 mmσ₂ = 16 mm
z =
10.Hypothesis tests & confidence intervalsHard
−1.961.96z = ?

In a trial, 135 of 300 patients on treatment A recover, and 31 of 80 patients on treatment B. Using the pooled proportion, find the test statistic z for H₀: p₁ = p₂.

x₁ = 135n₁ = 300x₂ = 31n₂ = 80
z =
11.Linear regression & correlationMedium
xy344444558657761xy465060

The table gives 5 paired observations of x = advertising spend in k€ and y = sales in k€. Their sums are given. Find Pearson's correlation coefficient r from these sums.

n = 5Σx = 25Σy = 264Σx² = 135Σy² = 14206Σxy = 1367
r =
12.Linear regression & correlationHard
xy24545665886810691277xy51050607080ŷ = 50

The table gives 6 paired observations of x = hours studied and y = exam score. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 50?

n = 6ŷ = 50
x =

3Solutions

1.Descriptive statistics

Answer: s = 15.48

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 302/7 = 43.14

Squared deviations

Σ(x − x̄)² = 3.857² + 14.86² + (−19.14)² + (−8.143)² + 10.86² + (−19.14)² + 16.86² = 1437

Standard deviation

s = √(1437/6) = 15.48

Answer

s = 15.48
2.Descriptive statistics

Answer: z = 0.4

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (72 − 70)/5 = 0.4

Answer

z = 0.4
3.Probability

Answer: P = 0.1923

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

First and second draw

P = 6/13 · 5/12 = 30/156 = 0.1923

Answer

P = 0.1923
4.Probability

Answer: P = 0.5282

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Zero and one failure

P(X = 0) = 0.75 = 0.1681
P(X = 1) = 5·0.3·0.74 = 0.3601

Add them

P = 0.1681 + 0.3601 = 0.5282

Answer

P = 0.5282
5.Normal distribution

Answer: z = 1.77

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left of z

Φ(z) = (1 + 0.9233)/2 = 0.9616

Read the z-table backwards

Find 0.9616 inside the table and read off z.

z = 1.77

Answer

z = 1.77
6.Normal distribution

Answer: x = 434 h

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left

Φ(z) = 0.05

z from the table

z ≈ −1.64

Back to the original units

x = 500 − 1.64·40 = 434 h

Answer

x = 434 h
7.Confidence intervals

Answer: lower limit = 57.93

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 20, t = 2.845

Margin of error

E = 2.845·13/√21 = 8.071

Interval

66 ± 8.071 → [57.93, 74.07]

Answer

lower limit = 57.93
8.Confidence intervals

Answer: E = 7.309 kg

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Pooled standard deviation

sp² = (11·7.5² + 4·1²)/15 = 41.52
sp = 6.443

Margin of error

E = 2.131·6.443·√(1/12 + 1/5) = 7.309

Answer

E = 7.309 kg
9.Hypothesis tests & confidence intervals

Answer: z = −1.59

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Standard error of the difference

SE = √(20²/60 + 16²/30) = √15.2 = 3.899

Test statistic

z = (135.5 − 141.7)/3.899 = −1.59

Answer

z = −1.59

|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).

10.Hypothesis tests & confidence intervals

Answer: z = 1.001

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Sample proportions

p̂₁ = 135/300 = 0.45
p̂₂ = 31/80 = 0.3875
p̂ = 166/380 = 0.4368

Standard error under H₀

SE = √(0.4368·0.5632·(1/300 + 1/80)) = 0.06241

Test statistic

z = (0.45 − 0.3875)/0.06241 = 1.001

Answer

z = 1.001

|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).

11.Linear regression & correlation

Answer: r = 0.9099

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Centred sums

Sxy = 1367 − 25·264/5 = 47
Sxx = 135 − 25²/5 = 10
Syy = 14206 − 264²/5 = 266.8

Correlation coefficient

r = 47/√(10·266.8) = 0.9099

Answer

r = 0.9099
12.Linear regression & correlation

Answer: x = 2.925

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 42/6 = 7
ȳ = 373/6 = 62.17

Sums of squares and products

Sxx = Σ(x − x̄)² = 70
Sxy = Σ(x − x̄)(y − ȳ) = 209

Regression line

b = 209/70 = 2.986
a = 62.17 − 2.986·7 = 41.27
ŷ = 41.27 + 2.986·x

Solve for x

x = (50 − 41.27)/2.986 = 2.925

Answer

x = 2.925

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