Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
152025303540

Find the sample standard deviation s of the data: 44, 21, 26, 13, 18, 16, 37.

n = 7
s =
2.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 70 and standard deviation 12. Find the z-score z of a score of 88.

μ = 70σ = 12x = 88
z =
3.ProbabilityMedium
xp(x)100.25200.35300.25400.15μ = 23

For the distribution shown, find the standard deviation σ of X.

x: 10, 20, 30, 40p(x): 0.25, 0.35, 0.25, 0.15
σ =
4.ProbabilityHard
n = 10, p = 0.1: P(X = 5) = ?k012345678910

A test has 10 multiple-choice questions. A student who guesses gets each one right with probability 0.1, independently. What is the probability P of exactly 5 correct answers?

n = 10p = 0.1k = 5
P =
5.Normal distributionMedium
−3−2−10123zshaded area between −z and z = 0.8557

Drag z so that the shaded area between −z and z under the standard normal curve is 0.8557. Find z to two decimals.

A = 0.8557
z =
6.Normal distributionHard
4 s0X − Y?

Runner A's lap time X and runner B's lap time Y are independent and normal: X has mean 52 s and standard deviation 4 s, Y has mean 48 s and standard deviation 3 s. Find the probability P that X is greater than Y. Round z to two decimals.

μX = 52 s, σX = 4 sμY = 48 s, σY = 3 s
P =
7.Confidence intervalsMedium
μ₁ − μ₂0L = ?Ux̄₁ − x̄₂E95%

The battery life of two phone models is compared. Model 1: 30 phones, mean 70 h, known standard deviation 19 h. Model 2: 50 phones, mean 60 h, known standard deviation 18 h. Find the lower limit of the 95% confidence interval for μ₁ − μ₂.

n₁ = 30x̄₁ = 70 hσ₁ = 19 hn₂ = 50x̄₂ = 60 hσ₂ = 18 h95%
lower limit = h
8.Confidence intervalsHard
μ₁ − μ₂, t(15) = 2.9470LUx̄₁ − x̄₂E = ?99%

Two fertilisers are tested. Plot group 1: 10 plots, mean yield 45 kg, standard deviation 5 kg. Plot group 2: 7 plots, mean 55 kg, standard deviation 10 kg. Assume equal variances (pooled t, df = n₁ + n₂ − 2). Find the margin of error E of the 99% confidence interval for μ₁ − μ₂.

n₁ = 10x̄₁ = 45s₁ = 5n₂ = 7x̄₂ = 55s₂ = 1099%t(15) = 2.947
E = kg
9.Hypothesis tests & confidence intervalsMedium
−1.961.96z = ?

Two production lines make the same part. Line 1: a sample of 60 parts has mean length 43 mm, and the line's known standard deviation is 6 mm. Line 2: a sample of 50 parts has mean 41.7 mm, known standard deviation 4 mm. Find the test statistic z for H₀: μ₁ = μ₂, taking the difference as x̄₁ − x̄₂ (line 1 minus line 2).

n₁ = 60x̄₁ = 43 mmσ₁ = 6 mmn₂ = 50x̄₂ = 41.7 mmσ₂ = 4 mm
z =
10.Hypothesis tests & confidence intervalsHard
−1.961.96z = ?

In a trial, 60 of 300 patients on treatment A recover, and 17 of 100 patients on treatment B. Using the pooled proportion, find the test statistic z for H₀: p₁ = p₂.

x₁ = 60n₁ = 300x₂ = 17n₂ = 100
z =
11.Linear regression & correlationMedium
xy16471847205522732477xy2050607080

The table gives 5 paired observations of x = temperature in °C and y = ice creams sold. Find the coefficient of determination r² of the least-squares line.

n = 5
r² =
12.Linear regression & correlationHard
xy142241344446548xy2445ŷ = 47

The table gives 5 paired observations of x = advertising spend in k€ and y = sales in k€. Use the least-squares line ŷ = a + b·x. For which value x does the line predict ŷ = 47?

n = 5ŷ = 47
x =

3Solutions

1.Descriptive statistics

Answer: s = 11.52

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 175/7 = 25

Squared deviations

Σ(x − x̄)² = 19² + (−4)² + 1² + (−12)² + (−7)² + (−9)² + 12² = 796

Standard deviation

s = √(796/6) = 11.52

Answer

s = 11.52
2.Descriptive statistics

Answer: z = 1.5

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (88 − 70)/12 = 1.5

Answer

z = 1.5
3.Probability

Answer: σ = 10.05

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Mean

μ = 10·0.25 + 20·0.35 + 30·0.25 + 40·0.15 = 23

Mean of the squares

E(X²) = 100·0.25 + 400·0.35 + 900·0.25 + 1600·0.15 = 630

Variance

Var(X) = 630 − 23² = 101
σ = √101 = 10.05

Answer

σ = 10.05
4.Probability

Answer: P = 0.001488

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Binomial formula

P(X = 5) = 252·0.15·0.95 = 252·1 × 10⁻⁵·0.5905 = 0.001488

Answer

P = 0.001488
5.Normal distribution

Answer: z = 1.46

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left of z

Φ(z) = (1 + 0.8557)/2 = 0.9279

Read the z-table backwards

Find 0.9279 inside the table and read off z.

z = 1.46

Answer

z = 1.46
6.Normal distribution

Answer: P = 0.7881

Sums and differences of normal variables: if X and Y are independent and normal, X + Y and X − Y are normal too. Means add or subtract: E(X ± Y) = μX ± μY. Variances always add, also for a difference: Var(X ± Y) = σX² + σY², so σ = √(σX² + σY²). Standard deviations never add directly. The total of n independent items with the same distribution has mean n·μ and standard deviation σ·√n. Then standardise as usual: z = (x − mean)/σ and read Φ(z).

Distribution of the difference

μ = 52 − 48 = 4 s, σ = 5 s

Standardise

z = (0 − 4)/5 = −0.8

Probability

P = 1 − Φ(−0.8) = 0.7881

Answer

P = 0.7881
7.Confidence intervals

Answer: lower limit = 1.567 h

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Point estimate

x̄₁ − x̄₂ = 70 − 60 = 10

Standard error

SE = √(19²/30 + 18²/50) = 4.303

Margin of error

E = 1.96·4.303 = 8.433

Interval

10 ± 8.433 → [1.567, 18.43]

Answer

lower limit = 1.567 h

The interval does not contain 0, so the means differ significantly.

8.Confidence intervals

Answer: E = 10.77 kg

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Pooled standard deviation

sp² = (9·5² + 6·10²)/15 = 55
sp = 7.416

Margin of error

E = 2.947·7.416·√(1/10 + 1/7) = 10.77

Answer

E = 10.77 kg
9.Hypothesis tests & confidence intervals

Answer: z = 1.355

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Standard error of the difference

SE = √(6²/60 + 4²/50) = √0.92 = 0.9592

Test statistic

z = (43 − 41.7)/0.9592 = 1.355

Answer

z = 1.355

|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).

10.Hypothesis tests & confidence intervals

Answer: z = 0.659

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Sample proportions

p̂₁ = 60/300 = 0.2
p̂₂ = 17/100 = 0.17
p̂ = 77/400 = 0.1925

Standard error under H₀

SE = √(0.1925·0.8075·(1/300 + 1/100)) = 0.04553

Test statistic

z = (0.2 − 0.17)/0.04553 = 0.659

Answer

z = 0.659

|z| < 1.96, so H₀ is not rejected at the 5% level (two-sided).

11.Linear regression & correlation

Answer: r² = 0.9011

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 100/5 = 20
ȳ = 299/5 = 59.8

Sums of squares and products

Sxx = Σ(x − x̄)² = 40
Sxy = Σ(x − x̄)(y − ȳ) = 172
Syy = Σ(y − ȳ)² = 820.8

Coefficient of determination

r² = 172²/(40·820.8) = 0.9011

Answer

r² = 0.9011

About 90.11% of the variation in y is explained by the line.

12.Linear regression & correlation

Answer: x = 4.647

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 15/5 = 3
ȳ = 221/5 = 44.2

Sums of squares and products

Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = 17

Regression line

b = 17/10 = 1.7
a = 44.2 − 1.7·3 = 39.1
ŷ = 39.1 + 1.7·x

Solve for x

x = (47 − 39.1)/1.7 = 4.647

Answer

x = 4.647

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