Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
15202530354045

Find the sample standard deviation s of the data: 48, 33, 44, 28, 18, 13, 30.

n = 7
s =
2.Descriptive statisticsHard
z −2−1012

A quantity is normally distributed with mean 60 and standard deviation 20. What proportion P of values is above 40?

μ = 60σ = 20x = 40
P =
3.ProbabilityMedium
red: 4blue: 7

A bag holds 4 red and 7 blue balls. You draw two balls without putting the first one back. What is the probability P that both are red?

4 / 7
P =
4.ProbabilityHard
xp(x)10.320.230.340.2μ

X has the distribution shown, and Y = 3X + 5. Find the standard deviation σY of Y.

x: 1, 2, 3, 4p(x): 0.3, 0.2, 0.3, 0.2Y = 3X + 5
σY =
5.Normal distributionMedium
−3−2−10123zshaded area between −z and z = 0.8926

Drag z so that the shaded area between −z and z under the standard normal curve is 0.8926. Find z to two decimals.

A = 0.8926
z =
6.Normal distributionHard
35455565758595pointsbottom 25%

The exam scores are normally distributed with mean 65 points and standard deviation 10 points. Drag the cut-off so the shaded bottom 25% is to the left of it. Find the cut-off x.

μ = 65 pointsσ = 10 points25%
x = points
7.Confidence intervalsMedium
n = 20, s = 4.5LUx̄ = 26E = ?90%

A sample of 20 items has mean 26 and standard deviation s = 4.5. The population is roughly normal. Find the margin of error E of a 90% confidence interval for the mean.

n = 20x̄ = 26s = 4.590%t(19) = 1.729
E =
8.Confidence intervalsHard
σ = 13, n = ?x̄ − Ex̄ + Ex̄E = 0.595%

The population standard deviation is 13. How large a sample n do you need so that a 95% confidence interval for the mean has a margin of error of at most 0.5?

σ = 13E = 0.595%
n =
9.Hypothesis tests & confidence intervalsMedium
−0.960.96p = ?

The mean of a population is claimed to be 50; the population standard deviation is known to be 2.5. A random sample of 25 observations has a mean of 49.52. Test H₀: μ = 50 against H₁: μ ≠ 50. Find the p-value p.

μ₀ = 50σ = 2.5n = 25x̄ = 49.52H₁: μ ≠ μ₀
p =
10.Hypothesis tests & confidence intervalsHard
H₀H₁μ₀x̄cμ₀ + 4α = 0.05βσ = 16, power 90%, n = ?

A one-sided z test at α = 0.05 must detect a shift of the mean of 4 units with a power of 90%. The standard deviation is 16. Find the minimum sample size n.

α = 0.05power = 90%δ = 4σ = 16zα = 1.645zβ = 1.282
n =
11.Linear regression & correlationMedium
xy353459560670772875xy4686070

The table gives 6 paired observations of x = hours studied and y = exam score. Their sums are given. Find Pearson's correlation coefficient r from these sums.

n = 6Σx = 33Σy = 389Σx² = 199Σy² = 25599Σxy = 2219
r =
12.Linear regression & correlationHard
xy336437545645750xy4635404550x = 6.5

The table gives 5 paired observations of x = advertising spend in k€ and y = sales in k€. Use the least-squares line ŷ = a + b·x. Predict ŷ for x = 6.5.

n = 5x = 6.5
ŷ =

3Solutions

1.Descriptive statistics

Answer: s = 12.67

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 214/7 = 30.57

Squared deviations

Σ(x − x̄)² = 17.43² + 2.429² + 13.43² + (−2.571)² + (−12.57)² + (−17.57)² + (−0.5714)² = 963.7

Standard deviation

s = √(963.7/6) = 12.67

Answer

s = 12.67
2.Descriptive statistics

Answer: P = 0.8413

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = −1

Standard normal table

Φ(−1) = 0.1587
P = 1 − 0.1587 = 0.8413

Answer

P = 0.8413
3.Probability

Answer: P = 0.1091

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

First and second draw

P = 4/11 · 3/10 = 12/110 = 0.1091

Answer

P = 0.1091
4.Probability

Answer: σY = 3.341

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Spread of X

μ = 2.4, Var(X) = 1.24, σX = 1.114

Linear change

σY = |3|·1.114 = 3.341

Answer

σY = 3.341

The mean does move: E(Y) = 3·2.4 + 5 = 12.2.

5.Normal distribution

Answer: z = 1.61

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left of z

Φ(z) = (1 + 0.8926)/2 = 0.9463

Read the z-table backwards

Find 0.9463 inside the table and read off z.

z = 1.61

Answer

z = 1.61
6.Normal distribution

Answer: x = 58.3 points

From an area back to z: Φ(z) is the area to the left of z. For a left-tail area A, find z with Φ(z) = A in the table. A right-tail area A means Φ(z) = 1 − A. A central area A between −z and z leaves (1 − A)/2 in each tail, so Φ(z) = (1 + A)/2. For a value x, use x = μ + zσ.

Area to the left

Φ(z) = 0.25

z from the table

z ≈ −0.67

Back to the original units

x = 65 − 0.67·10 = 58.3 points

Answer

x = 58.3 points
7.Confidence intervals

Answer: E = 1.74

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Critical value

df = n − 1 = 19, t = 1.729

Margin of error

E = 1.729·4.5/√20 = 1.74

Answer

E = 1.74
8.Confidence intervals

Answer: n = 2597

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (1.96·13/0.5)² = 2597

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 2597

Answer

n = 2597
9.Hypothesis tests & confidence intervals

Answer: p = 0.3371

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Test statistic

SE = σ/√n = 2.5/√25 = 0.5
z = (49.52 − 50)/0.5 = −0.96

Tail area

Φ(0.96) = 0.8315
1 − Φ(0.96) = 0.1685

p-value

p = 2·0.1685 = 0.3371

Answer

p = 0.3371

p > 0.05, so H₀ is not rejected at the 5% level.

10.Hypothesis tests & confidence intervals

Answer: n = 138

Sample size for a test: to detect a true shift δ with power 1 − β in a one-sided z test at level α, the standard error must satisfy δ = (z_α + z_β)·σ/√n, so n = ((z_α + z_β)·σ/δ)², rounded up.

Solve for n

n = ((1.645 + 1.282)·16/4)² = 137.1

Round up

n = 138

Answer

n = 138
11.Linear regression & correlation

Answer: r = 0.9764

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Centred sums

Sxy = 2219 − 33·389/6 = 79.5
Sxx = 199 − 33²/6 = 17.5
Syy = 25599 − 389²/6 = 378.8

Correlation coefficient

r = 79.5/√(17.5·378.8) = 0.9764

Answer

r = 0.9764
12.Linear regression & correlation

Answer: ŷ = 48

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 25/5 = 5
ȳ = 213/5 = 42.6

Sums of squares and products

Sxx = Σ(x − x̄)² = 10
Sxy = Σ(x − x̄)(y − ȳ) = 36

Regression line

b = 36/10 = 3.6
a = 42.6 − 3.6·5 = 24.6
ŷ = 24.6 + 3.6·x

Prediction

ŷ = 24.6 + 3.6·6.5 = 48

Answer

ŷ = 48

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