Introductory Statistics: cram pack

Formula sheets, the key method steps for every topic and 12 practice problems, with full solutions at the back.

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1Formulas and methods

Descriptive statistics

Mean
x̄ = Σx/n
Sample standard deviation
s = √(Σ(x − x̄)²/(n − 1))
Median
middle value of the sorted data
z-score
z = (x − μ)/σ
Normal distribution
68% within ±1σ, 95% within ±2σ

Probability

Complement
P(not A) = 1 − P(A)
Addition rule
P(A ∪ B) = P(A) + P(B) − P(A ∩ B)
Independent events
P(A ∩ B) = P(A)·P(B)
Conditional probability
P(A|B) = P(A ∩ B)/P(B)
Binomial
P(X = k) = C(n,k)·pk(1 − p)n−k

Normal distribution

z-score
z = (x − μ)/σ
Below x
P(X < x) = Φ(z)
Above x
P(X > x) = 1 − Φ(z)
Between
Φ(z2) − Φ(z1)
Percentile
x = μ + z·σ

Method

  1. Convert the value to a z-score: z = (x − μ)/σ.
  2. Look up Φ(z), the area to the left of z.
  3. For the area to the right use 1 − Φ(z); for an interval subtract the two left areas.
  4. For a percentile, work backwards: find z for the area, then x = μ + z·σ.

Confidence intervals

σ known
x̄ ± z·σ/√n
σ unknown
x̄ ± t·s/√n, df = n − 1
Critical z
90%: 1.645, 95%: 1.96, 99%: 2.576
Sample size
n = (z·σ/E)², rounded up

Method

  1. Decide between z (population σ known) and t (only the sample s, with n − 1 degrees of freedom).
  2. Find the critical value for the confidence level.
  3. Margin of error: E = critical value × standard deviation/√n.
  4. Interval: x̄ ± E.

Hypothesis tests & confidence intervals

z-test for a mean
z = (x̄ − μ0)/(σ/√n)
t-test for a mean
t = (x̄ − μ0)/(s/√n), df = n − 1
Two-sided at 5%
reject H0 if |z| > 1.96
Confidence interval
x̄ ± z·σ/√n

Method

  1. State H₀ and H₁ and decide whether the test is one- or two-sided.
  2. Calculate the test statistic: (x̄ − μ₀)/(σ/√n), or with s and t.
  3. Compare with the critical value, or find the p-value.
  4. Reject H₀ if the statistic is beyond the critical value (p below α), and state the conclusion in words.

Linear regression & correlation

Sums of squares
Sxx = Σ(x − x̄)² = Σx² − (Σx)²/n, Sxy = Σxy − ΣxΣy/n
Slope
b = Sxy/Sxx
Intercept
a = ȳ − b·x̄
Correlation
r = Sxy/√(SxxSyy)
Residual
e = y − ŷ

2Practice problems

1.Descriptive statisticsMedium
20253035404550

Find the sample standard deviation s of the data: 53, 29, 48, 37, 19, 33.

n = 6
s =
2.Descriptive statisticsHard
z −2−1012

Exam scores are normally distributed with mean 60 and standard deviation 8. Find the z-score z of a score of 64.8.

μ = 60σ = 8x = 64.8
z =
3.ProbabilityMedium
xp(x)10.3520.1530.1540.350.05μ = 2.55

For the distribution shown, find the standard deviation σ of X.

x: 1, 2, 3, 4, 5p(x): 0.35, 0.15, 0.15, 0.3, 0.05
σ =
4.ProbabilityHard
n = 12, p = 0.2: P(X = 3) = ?k0123456789101112

A test has 12 multiple-choice questions. A student who guesses gets each one right with probability 0.2, independently. What is the probability P of exactly 3 correct answers?

n = 12p = 0.2k = 3
P =
5.Normal distributionMedium
22.441.3P = ?

The delivery times are normally distributed with mean 32 min and standard deviation 6 min. What fraction lies between 22.4 and 41.3 min? Give P as a decimal.

μ = 32σ = 6x1 = 22.4x2 = 41.3
P =
6.Normal distributionHard
μ = 32x = ?95%

The delivery times are normally distributed with mean 32 min and standard deviation 6 min. Find the value x below which 95% of them lie (the 95th percentile).

μ = 32σ = 6P = 95%
x = min
7.Confidence intervalsMedium
μ₁ − μ₂0LUx̄₁ − x̄₂E = ?95%

The battery life of two phone models is compared. Model 1: 50 phones, mean 119.5 h, known standard deviation 17 h. Model 2: 100 phones, mean 120.5 h, known standard deviation 15 h. Find the margin of error E of the 95% confidence interval for μ₁ − μ₂.

n₁ = 50x̄₁ = 119.5 hσ₁ = 17 hn₂ = 100x̄₂ = 120.5 hσ₂ = 15 h95%
E = h
8.Confidence intervalsHard
σ = 19, n = ?x̄ − Ex̄ + Ex̄E = 599%

The population standard deviation is 19. How large a sample n do you need so that a 99% confidence interval for the mean has a margin of error of at most 5?

σ = 19E = 599%
n =
9.Hypothesis tests & confidence intervalsMedium
−2.1792.179t = ?df = 12

13 employees take a typing test before and after a training course. For each person the difference d = after − before (words per minute) is recorded. The mean difference is 3.45 and the standard deviation of the differences is 11.3. Find the paired test statistic t for H₀: μd = 0.

n = 13d̄ = 3.45sd = 11.3
t =
10.Hypothesis tests & confidence intervalsHard
−1.961.96z = ?

In a trial, 75 of 250 patients on treatment A recover, and 23 of 120 patients on treatment B. Using the pooled proportion, find the test statistic z for H₀: p₁ = p₂.

x₁ = 75n₁ = 250x₂ = 23n₂ = 120
z =
11.Linear regression & correlationMedium
xy125339549761978xy5406080

The table gives 5 paired observations of x = advertising spend in k€ and y = sales in k€. Their sums are given. Find Pearson's correlation coefficient r from these sums.

n = 5Σx = 25Σy = 252Σx² = 165Σy² = 14352Σxy = 1516
r =
12.Linear regression & correlationHard
xy129232335445543655xy246304050x = 5.5

The table gives 6 paired observations of x = advertising spend in k€ and y = sales in k€. Use the least-squares line ŷ = a + b·x. Predict ŷ for x = 5.5.

n = 6x = 5.5
ŷ =

3Solutions

1.Descriptive statistics

Answer: s = 12.49

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Mean

x̄ = 219/6 = 36.5

Squared deviations

Σ(x − x̄)² = 16.5² + (−7.5)² + 11.5² + 0.5² + (−17.5)² + (−3.5)² = 779.5

Standard deviation

s = √(779.5/5) = 12.49

Answer

s = 12.49
2.Descriptive statistics

Answer: z = 0.6

Descriptive statistics: the mean is the sum divided by n; the median is the middle value of the sorted data (the average of the two middle values when n is even). The sample standard deviation is s = √(Σ(x − x̄)²/(n − 1)). A z-score z = (x − μ)/σ says how many standard deviations a value lies from the mean.

Standardise

z = (64.8 − 60)/8 = 0.6

Answer

z = 0.6
3.Probability

Answer: σ = 1.359

Discrete random variables: a probability distribution lists every value x a variable can take with its probability p(x); the probabilities are between 0 and 1 and add up to 1. The expected value (mean) is E(X) = Σx·p(x), the long-run average. The variance is Var(X) = Σ(x − μ)²·p(x) = E(X²) − μ², and the standard deviation σ = √Var(X). For a linear change Y = aX + b: E(Y) = a·E(X) + b, Var(Y) = a²·Var(X) and σY = |a|·σX; adding a constant does not change the spread.

Mean

μ = 1·0.35 + 2·0.15 + 3·0.15 + 4·0.3 + 5·0.05 = 2.55

Mean of the squares

E(X²) = 1·0.35 + 4·0.15 + 9·0.15 + 16·0.3 + 25·0.05 = 8.35

Variance

Var(X) = 8.35 − 2.55² = 1.848
σ = √1.848 = 1.359

Answer

σ = 1.359
4.Probability

Answer: P = 0.2362

Probability: with equally likely outcomes, P(A) = favourable/total. For independent events multiply: P(A and B) = P(A)·P(B). The complement often helps: P(at least one) = 1 − P(none). Binomial: in n independent trials with success probability p, P(X = k) = C(n, k)·pᵏ·(1 − p)ⁿ⁻ᵏ.

Binomial formula

P(X = 3) = 220·0.23·0.89 = 220·0.008·0.1342 = 0.2362

Answer

P = 0.2362
5.Normal distribution

Answer: P = 0.8846

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z-scores

z₁ = (22.4 − 32)/6 = −1.6
z₂ = (41.3 − 32)/6 = 1.55

Area between

P = Φ(1.55) − Φ(−1.6) = 0.9394 − 0.0548 = 0.8846

Answer

P = 0.8846
6.Normal distribution

Answer: x = 41.87 min

Normal distribution: convert a value x to a z-score, z = (x − μ)/σ, which counts standard deviations from the mean. A z-table (or Φ(z)) gives the area to the left of z, which is P(X < x). The area to the right is 1 − Φ(z), and the area between two values is the difference of their two areas.

z for the percentile

Φ(z) = 0.95 → z = 1.645

Back to x

x = 32 + 1.645·6 = 41.87 min

Answer

x = 41.87 min
7.Confidence intervals

Answer: E = 5.554 h

Interval for a difference: estimate ± critical value × standard error. For two independent means with known σ: SE = √(σ₁²/n₁ + σ₂²/n₂) and z. With equal unknown variances: pooled s_p and t with n₁ + n₂ − 2 degrees of freedom. For paired data, work with the differences: d̄ ± t·s_d/√n.

Point estimate

x̄₁ − x̄₂ = 119.5 − 120.5 = −1

Standard error

SE = √(17²/50 + 15²/100) = 2.834

Margin of error

E = 1.96·2.834 = 5.554

Answer

E = 5.554 h

The interval contains 0, so the data do not show a significant difference.

8.Confidence intervals

Answer: n = 96

Confidence interval for a mean: x̄ ± margin of error. With a known population σ the margin is z·σ/√n; with only the sample standard deviation s, use t with n − 1 degrees of freedom: t·s/√n. Critical values: z = 1.645 (90%), 1.96 (95%), 2.576 (99%). To get a margin E or smaller, you need n ≥ (z·σ/E)², rounded up.

Solve for n

n = (2.576·19/5)² = 95.82

Round up

A sample size is a whole number, and rounding down would make the margin too large.

n = 96

Answer

n = 96
9.Hypothesis tests & confidence intervals

Answer: t = 1.101

Testing a mean: the test statistic measures how many standard errors the sample mean lies from the value claimed in H₀: z = (x̄ − μ₀)/(σ/√n) when σ is known, t = (x̄ − μ₀)/(s/√n) when it is estimated from the sample. A confidence interval is x̄ ± (critical value)·(standard error).

Standard error of the mean difference

SE = 11.3/√13 = 3.134

Test statistic

t = 3.45/3.134 = 1.101

Answer

t = 1.101

With df = 12, the two-sided 5% critical value is 2.179; |t| is smaller, so H₀ is not rejected.

10.Hypothesis tests & confidence intervals

Answer: z = 2.211

Hypothesis test: the test statistic = (estimate − value under H₀)/(standard error under H₀). The p-value is the probability, assuming H₀ is true, of a statistic at least as extreme as the one observed: the area in one tail for a one-sided H₁, twice the tail area for a two-sided H₁. Reject H₀ when p ≤ α.

Sample proportions

p̂₁ = 75/250 = 0.3
p̂₂ = 23/120 = 0.1917
p̂ = 98/370 = 0.2649

Standard error under H₀

SE = √(0.2649·0.7351·(1/250 + 1/120)) = 0.049

Test statistic

z = (0.3 − 0.1917)/0.049 = 2.211

Answer

z = 2.211

|z| > 1.96, so H₀ is rejected at the 5% level (two-sided).

11.Linear regression & correlation

Answer: r = 0.9961

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Centred sums

Sxy = 1516 − 25·252/5 = 256
Sxx = 165 − 25²/5 = 40
Syy = 14352 − 252²/5 = 1651

Correlation coefficient

r = 256/√(40·1651) = 0.9961

Answer

r = 0.9961
12.Linear regression & correlation

Answer: ŷ = 49.72

Least-squares regression: with x̄ and ȳ the means, Sxx = Σ(x − x̄)², Syy = Σ(y − ȳ)² and Sxy = Σ(x − x̄)(y − ȳ), the line ŷ = a + b·x has slope b = Sxy/Sxx and intercept a = ȳ − b·x̄, so it always passes through (x̄, ȳ). Pearson's correlation coefficient r = Sxy/√(Sxx·Syy) lies between −1 and 1; r² is the fraction of the variation in y explained by the line.

Means

x̄ = 21/6 = 3.5
ȳ = 239/6 = 39.83

Sums of squares and products

Sxx = Σ(x − x̄)² = 17.5
Sxy = Σ(x − x̄)(y − ȳ) = 86.5

Regression line

b = 86.5/17.5 = 4.943
a = 39.83 − 4.943·3.5 = 22.53
ŷ = 22.53 + 4.943·x

Prediction

ŷ = 22.53 + 4.943·5.5 = 49.72

Answer

ŷ = 49.72

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