Arterial blood gas interpretation worksheet with answers

Free printable Arterial blood gas interpretation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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Name: ____________________   Date: ____________

1.Easy
pH7.357.457.56PaCO₂mmHg354548HCO₃⁻mmol/L222642respiratorymetabolicacidosisalkalosis

A practice arterial blood gas shows pH 7.56, PaCO₂ 48 mmHg (6.4 kPa) and HCO₃⁻ 42 mmol/L. Which primary disorder is it? Click the cell in the grid.

pH 7.56PaCO₂ 48 mmHg (6.4 kPa)HCO₃⁻ 42 mmol/L
  1. 1respiratory acidosis
  2. 2metabolic acidosis
  3. 3respiratory alkalosis
  4. 4metabolic alkalosis
2.Easy
pH7.357.457.64PaCO₂mmHg354523HCO₃⁻mmol/L222624respiratorymetabolicacidosisalkalosis

A practice arterial blood gas shows pH 7.64, PaCO₂ 23 mmHg (3.1 kPa) and HCO₃⁻ 24 mmol/L. Which primary disorder is it? Click the cell in the grid.

pH 7.64PaCO₂ 23 mmHg (3.1 kPa)HCO₃⁻ 24 mmol/L
  1. 1respiratory acidosis
  2. 2metabolic acidosis
  3. 3respiratory alkalosis
  4. 4metabolic alkalosis
3.Medium
pH7.357.457.08PaCO₂mmHg354538HCO₃⁻mmol/L222611uncompensatedpartially compensatedfully compensated

A practice arterial blood gas shows pH 7.08, PaCO₂ 38 mmHg (5.1 kPa) and HCO₃⁻ 11 mmol/L. The primary disorder is metabolic acidosis. How far is it compensated? Click your answer.

pH 7.08PaCO₂ 38 mmHg (5.1 kPa)HCO₃⁻ 11 mmol/L
  1. 1uncompensated
  2. 2partially compensated
  3. 3fully compensated
4.Medium

Practice values: Na⁺ 131 mmol/L, glucose 11 mmol/L and urea 19.8 mmol/L. Calculate the serum osmolality Osm = 2·Na⁺ + glucose + urea to the nearest whole number.

Na⁺ 131 mmol/Lglucose 11 mmol/Lurea 19.8 mmol/L
Osm = mOsm/kg
5.Hard
pH7.357.457.32PaCO₂mmHg354534HCO₃⁻mmol/L222617appropriate compensationadded respiratory acidosisadded respiratory alkalosis

A practice gas shows a metabolic acidosis: pH 7.32, PaCO₂ 34 mmHg (4.5 kPa), HCO₃⁻ 17 mmol/L. Compare the measured PaCO₂ with Winter’s formula. Click your interpretation.

pH 7.32PaCO₂ 34 mmHg (4.5 kPa)HCO₃⁻ 17 mmol/L
  1. 1appropriate compensation
  2. 2added respiratory acidosis
  3. 3added respiratory alkalosis
6.Hard

At sea level, a practice gas taken on 50% oxygen shows PaO₂ 87 mmHg (11.6 kPa) and PaCO₂ 37 mmHg (4.9 kPa). Use PAO₂ = FiO₂·(760 − 47) − PaCO₂/0.8 to find the A–a gradient.

FiO₂ 50%PaO₂ 87 mmHg (11.6 kPa)PaCO₂ 37 mmHg (4.9 kPa)
A–a gradient = mmHg

Answer key

  1. 1. metabolic alkalosis
  2. 2. respiratory alkalosis
  3. 3. uncompensated
  4. 4. Osm = 293 mOsm/kg
  5. 5. appropriate compensation
  6. 6. A–a gradient = 223.3 mmHg

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