Arterial blood gas interpretation worksheet with answers

Free printable Arterial blood gas interpretation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

A practice blood gas shows PaO₂ 64 mmHg (8.5 kPa) while the inspired oxygen is 70%. Calculate the ratio P/F = PaO₂/FiO₂ in mmHg.

PaO₂ 64 mmHg (8.5 kPa)FiO₂ 70%
P/F = mmHg
2.Easy

A practice blood gas shows PaO₂ 56 mmHg (7.5 kPa) while the inspired oxygen is 40%. Calculate the ratio P/F = PaO₂/FiO₂ in mmHg.

PaO₂ 56 mmHg (7.5 kPa)FiO₂ 40%
P/F = mmHg
3.Medium
pH7.357.457.37PaCO₂mmHg354532HCO₃⁻mmol/L222618uncompensatedpartially compensatedfully compensated

A practice arterial blood gas shows pH 7.37, PaCO₂ 32 mmHg (4.3 kPa) and HCO₃⁻ 18 mmol/L. The primary disorder is metabolic acidosis. How far is it compensated? Click your answer.

pH 7.37PaCO₂ 32 mmHg (4.3 kPa)HCO₃⁻ 18 mmol/L
  1. 1uncompensated
  2. 2partially compensated
  3. 3fully compensated
4.Medium
pH7.357.457.36PaCO₂mmHg354560HCO₃⁻mmol/L222633uncompensatedpartially compensatedfully compensated

A practice arterial blood gas shows pH 7.36, PaCO₂ 60 mmHg (8.0 kPa) and HCO₃⁻ 33 mmol/L. The primary disorder is respiratory acidosis. How far is it compensated? Click your answer.

pH 7.36PaCO₂ 60 mmHg (8.0 kPa)HCO₃⁻ 33 mmol/L
  1. 1uncompensated
  2. 2partially compensated
  3. 3fully compensated
5.Hard
pH7.357.457.27PaCO₂mmHg354527HCO₃⁻mmol/L222612added normal-gap acidosispure high-gap acidosisadded metabolic alkalosis

A practice gas shows pH 7.27, PaCO₂ 27 mmHg (3.6 kPa) and HCO₃⁻ 12 mmol/L, with Na⁺ 141 and Cl⁻ 113 mmol/L. Use the anion gap and the delta ratio to click the best interpretation.

pH 7.27PaCO₂ 27 mmHg (3.6 kPa)HCO₃⁻ 12 mmol/LNa⁺ 141 mmol/LCl⁻ 113 mmol/L
  1. 1added normal-gap acidosis
  2. 2pure high-gap acidosis
  3. 3added metabolic alkalosis
6.Hard

Practice values: Na⁺ 141, Cl⁻ 111, HCO₃⁻ 19 mmol/L and albumin 20 g/L. Find the albumin-corrected anion gap AGc = AG + 0.25·(40 − albumin).

Na⁺ 141 mmol/LCl⁻ 111 mmol/LHCO₃⁻ 19 mmol/Lalbumin 20 g/L
AGc = mmol/L

Answer key

  1. 1. P/F = 91.43 mmHg
  2. 2. P/F = 140 mmHg
  3. 3. fully compensated
  4. 4. fully compensated
  5. 5. added normal-gap acidosis
  6. 6. AGc = 16 mmol/L

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