Calorimetry & enthalpy worksheet with answers

Free printable Calorimetry & enthalpy worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
waterm = 1000 gT1​ = 26 °C → T2​ = 85 °Cq = ?

How much heat q is needed to warm 1000 g of water from 26 °C to 85 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 1000 gT1 = 26 °CT2 = 85 °Cc = 4.18 J/(g·°C)
q = kJ
2.Easy
waterm = 1000 gT1​ = 28 °C → T2​ = 70 °Cq = ?

How much heat q is needed to warm 1000 g of water from 28 °C to 70 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 1000 gT1 = 28 °CT2 = 70 °Cc = 4.18 J/(g·°C)
q = kJ
3.Medium
Tf​ = ?Ironm = 150 gT = 120 °Cc = 0.449 J/(g·°C)Waterm = 300 gT = 22 °Cc = 4.18 J/(g·°C)

A 150 g block of iron (c = 0.449 J/(g·°C)) at 120 °C is dropped into 300 g of water (c = 4.18 J/(g·°C)) at 22 °C in an insulated cup. Find the final temperature Tf.

mmetal = 150 gcmetal = 0.449 J/(g·°C)Tmetal = 120 °Cmwater = 300 gTwater = 22 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
Tf​ = ?Aluminiumm = 100 gT = 170 °Cc = 0.897 J/(g·°C)Waterm = 100 gT = 24 °Cc = 4.18 J/(g·°C)

A 100 g block of aluminium (c = 0.897 J/(g·°C)) at 170 °C is dropped into 100 g of water (c = 4.18 J/(g·°C)) at 24 °C in an insulated cup. Find the final temperature Tf.

mmetal = 100 gcmetal = 0.897 J/(g·°C)Tmetal = 170 °Cmwater = 100 gTwater = 24 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
H20 g CH3​OH2CH3​OH + 3O₂reactants2CO₂ + 4H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 20 g of CH3OH (M = 32.04 g/mol) burns completely: 2CH3OH + 3O₂ → 2CO₂ + 4H₂O(l). Give q as a positive number.

ΔH°f(CH3OH) = −238.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ
6.Hard
H50 g CH3​OH2CH3​OH + 3O₂reactants2CO₂ + 4H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 50 g of CH3OH (M = 32.04 g/mol) burns completely: 2CH3OH + 3O₂ → 2CO₂ + 4H₂O(l). Give q as a positive number.

ΔH°f(CH3OH) = −238.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ

Answer key

  1. 1. q = 246.6 kJ
  2. 2. q = 175.6 kJ
  3. 3. Tf = 27 °C
  4. 4. Tf = 49.8 °C
  5. 5. q = 453.4 kJ
  6. 6. q = 1134 kJ

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