16 kJ of heat is added to 500 g of water (c = 4.18 J/(g·°C)). Find the temperature rise ΔT.
Calorimetry & enthalpy worksheet with answers
1.Easy
q = 16 kJm = 500 gc = 4.18 J/(g·°C)
ΔT = °C
2.Easy
How much heat q is needed to warm 500 g of water from 24 °C to 80 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.
m = 500 gT1 = 24 °CT2 = 80 °Cc = 4.18 J/(g·°C)
q = kJ
3.Medium
A 100 g block of lead (c = 0.129 J/(g·°C)) at 100 °C is dropped into 250 g of water (c = 4.18 J/(g·°C)) at 25 °C in an insulated cup. Find the final temperature Tf.
mmetal = 100 gcmetal = 0.129 J/(g·°C)Tmetal = 100 °Cmwater = 250 gTwater = 25 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
A 150 g block of aluminium (c = 0.897 J/(g·°C)) at 130 °C is dropped into 300 g of water (c = 4.18 J/(g·°C)) at 23 °C in an insulated cup. Find the final temperature Tf.
mmetal = 150 gcmetal = 0.897 J/(g·°C)Tmetal = 130 °Cmwater = 300 gTwater = 23 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
Use the standard enthalpies of formation to find ΔH° for the reaction 2C4H10 + 13O₂ → 8CO₂ + 10H₂O(l).
ΔH°f(C4H10) = −125.6 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
ΔH° = kJ
6.Hard
Use the standard enthalpies of formation to find ΔH° for the reaction C6H12O6 + 6O₂ → 6CO₂ + 6H₂O(l).
ΔH°f(C6H12O6) = −1274 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
ΔH° = kJ
Answer key
- 1. ΔT = 7.656 °C
- 2. q = 117 kJ
- 3. Tf = 25.91 °C
- 4. Tf = 33.37 °C
- 5. ΔH° = −5755 kJ
- 6. ΔH° = −2802 kJ
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