Calorimetry & enthalpy worksheet with answers

Free printable Calorimetry & enthalpy worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
waterm = 250 gT1​ = 10 °C → T2​ = 45 °Cq = ?

How much heat q is needed to warm 250 g of water from 10 °C to 45 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 250 gT1 = 10 °CT2 = 45 °Cc = 4.18 J/(g·°C)
q = kJ
2.Easy
waterm = 300 gT1​ = 30 °C → T2​ = 45 °Cq = ?

How much heat q is needed to warm 300 g of water from 30 °C to 45 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 300 gT1 = 30 °CT2 = 45 °Cc = 4.18 J/(g·°C)
q = kJ
3.Medium
Tf​ = ?Zincm = 250 gT = 200 °Cc = 0.388 J/(g·°C)Waterm = 200 gT = 20 °Cc = 4.18 J/(g·°C)

A 250 g block of zinc (c = 0.388 J/(g·°C)) at 200 °C is dropped into 200 g of water (c = 4.18 J/(g·°C)) at 20 °C in an insulated cup. Find the final temperature Tf.

mmetal = 250 gcmetal = 0.388 J/(g·°C)Tmetal = 200 °Cmwater = 200 gTwater = 20 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
Tf​ = ?Ironm = 75 gT = 180 °Cc = 0.449 J/(g·°C)Waterm = 400 gT = 24 °Cc = 4.18 J/(g·°C)

A 75 g block of iron (c = 0.449 J/(g·°C)) at 180 °C is dropped into 400 g of water (c = 4.18 J/(g·°C)) at 24 °C in an insulated cup. Find the final temperature Tf.

mmetal = 75 gcmetal = 0.449 J/(g·°C)Tmetal = 180 °Cmwater = 400 gTwater = 24 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
H10 g C4​H10​2C4​H10​ + 13O₂reactants8CO₂ + 10H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 10 g of C4H10 (M = 58.12 g/mol) burns completely: 2C4H10 + 13O₂ → 8CO₂ + 10H₂O(l). Give q as a positive number.

ΔH°f(C4H10) = −125.6 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ
6.Hard
H50 g C4​H10​2C4​H10​ + 13O₂reactants8CO₂ + 10H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 50 g of C4H10 (M = 58.12 g/mol) burns completely: 2C4H10 + 13O₂ → 8CO₂ + 10H₂O(l). Give q as a positive number.

ΔH°f(C4H10) = −125.6 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ

Answer key

  1. 1. q = 36.58 kJ
  2. 2. q = 18.81 kJ
  3. 3. Tf = 38.71 °C
  4. 4. Tf = 27.08 °C
  5. 5. q = 495.1 kJ
  6. 6. q = 2475 kJ

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