Calorimetry & enthalpy worksheet with answers

Free printable Calorimetry & enthalpy worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
waterm = 100 gT1​ = 15 °C → T2​ = 75 °Cq = ?

How much heat q is needed to warm 100 g of water from 15 °C to 75 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 100 gT1 = 15 °CT2 = 75 °Cc = 4.18 J/(g·°C)
q = kJ
2.Easy
waterm = 250 gT1​ = 24 °C → T2​ = 40 °Cq = ?

How much heat q is needed to warm 250 g of water from 24 °C to 40 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 250 gT1 = 24 °CT2 = 40 °Cc = 4.18 J/(g·°C)
q = kJ
3.Medium
Tf​ = ?Zincm = 150 gT = 130 °Cc = 0.388 J/(g·°C)Waterm = 250 gT = 16 °Cc = 4.18 J/(g·°C)

A 150 g block of zinc (c = 0.388 J/(g·°C)) at 130 °C is dropped into 250 g of water (c = 4.18 J/(g·°C)) at 16 °C in an insulated cup. Find the final temperature Tf.

mmetal = 150 gcmetal = 0.388 J/(g·°C)Tmetal = 130 °Cmwater = 250 gTwater = 16 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
Tf​ = ?Leadm = 100 gT = 150 °Cc = 0.129 J/(g·°C)Waterm = 200 gT = 19 °Cc = 4.18 J/(g·°C)

A 100 g block of lead (c = 0.129 J/(g·°C)) at 150 °C is dropped into 200 g of water (c = 4.18 J/(g·°C)) at 19 °C in an insulated cup. Find the final temperature Tf.

mmetal = 100 gcmetal = 0.129 J/(g·°C)Tmetal = 150 °Cmwater = 200 gTwater = 19 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
H100 g C4​H10​2C4​H10​ + 13O₂reactants8CO₂ + 10H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 100 g of C4H10 (M = 58.12 g/mol) burns completely: 2C4H10 + 13O₂ → 8CO₂ + 10H₂O(l). Give q as a positive number.

ΔH°f(C4H10) = −125.6 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ
6.Hard
H25 g CH3​OH2CH3​OH + 3O₂reactants2CO₂ + 4H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 25 g of CH3OH (M = 32.04 g/mol) burns completely: 2CH3OH + 3O₂ → 2CO₂ + 4H₂O(l). Give q as a positive number.

ΔH°f(CH3OH) = −238.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ

Answer key

  1. 1. q = 25.08 kJ
  2. 2. q = 16.72 kJ
  3. 3. Tf = 22.01 °C
  4. 4. Tf = 20.99 °C
  5. 5. q = 4951 kJ
  6. 6. q = 566.8 kJ

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