Calorimetry & enthalpy worksheet with answers

Free printable Calorimetry & enthalpy worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
waterm = 150 gq = 25 kJΔT = ?

25 kJ of heat is added to 150 g of water (c = 4.18 J/(g·°C)). Find the temperature rise ΔT.

q = 25 kJm = 150 gc = 4.18 J/(g·°C)
ΔT = °C
2.Easy
waterm = 150 gT1​ = 28 °C → T2​ = 85 °Cq = ?

How much heat q is needed to warm 150 g of water from 28 °C to 85 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 150 gT1 = 28 °CT2 = 85 °Cc = 4.18 J/(g·°C)
q = kJ
3.Medium
Tf​ = ?Leadm = 100 gT = 90 °Cc = 0.129 J/(g·°C)Waterm = 250 gT = 15 °Cc = 4.18 J/(g·°C)

A 100 g block of lead (c = 0.129 J/(g·°C)) at 90 °C is dropped into 250 g of water (c = 4.18 J/(g·°C)) at 15 °C in an insulated cup. Find the final temperature Tf.

mmetal = 100 gcmetal = 0.129 J/(g·°C)Tmetal = 90 °Cmwater = 250 gTwater = 15 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
Tf​ = ?Leadm = 200 gT = 190 °Cc = 0.129 J/(g·°C)Waterm = 150 gT = 20 °Cc = 4.18 J/(g·°C)

A 200 g block of lead (c = 0.129 J/(g·°C)) at 190 °C is dropped into 150 g of water (c = 4.18 J/(g·°C)) at 20 °C in an insulated cup. Find the final temperature Tf.

mmetal = 200 gcmetal = 0.129 J/(g·°C)Tmetal = 190 °Cmwater = 150 gTwater = 20 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
H100 g C6​H12​O6​C6​H12​O6​ + 6O₂reactants6CO₂ + 6H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 100 g of C6H12O6 (M = 180.16 g/mol) burns completely: C6H12O6 + 6O₂ → 6CO₂ + 6H₂O(l). Give q as a positive number.

ΔH°f(C6H12O6) = −1274 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ
6.Hard
H250 g C2​H6​2C2​H6​ + 7O₂reactants4CO₂ + 6H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 250 g of C2H6 (M = 30.07 g/mol) burns completely: 2C2H6 + 7O₂ → 4CO₂ + 6H₂O(l). Give q as a positive number.

ΔH°f(C2H6) = −84.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ

Answer key

  1. 1. ΔT = 39.87 °C
  2. 2. q = 35.74 kJ
  3. 3. Tf = 15.91 °C
  4. 4. Tf = 26.72 °C
  5. 5. q = 1555 kJ
  6. 6. q = 12967 kJ

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