Calorimetry & enthalpy worksheet with answers

Free printable Calorimetry & enthalpy worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
waterm = 250 gT1​ = 27 °C → T2​ = 70 °Cq = ?

How much heat q is needed to warm 250 g of water from 27 °C to 70 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 250 gT1 = 27 °CT2 = 70 °Cc = 4.18 J/(g·°C)
q = kJ
2.Easy
waterm = 750 gT1​ = 26 °C → T2​ = 70 °Cq = ?

How much heat q is needed to warm 750 g of water from 26 °C to 70 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 750 gT1 = 26 °CT2 = 70 °Cc = 4.18 J/(g·°C)
q = kJ
3.Medium
Tf​ = ?Ironm = 250 gT = 160 °Cc = 0.449 J/(g·°C)Waterm = 200 gT = 19 °Cc = 4.18 J/(g·°C)

A 250 g block of iron (c = 0.449 J/(g·°C)) at 160 °C is dropped into 200 g of water (c = 4.18 J/(g·°C)) at 19 °C in an insulated cup. Find the final temperature Tf.

mmetal = 250 gcmetal = 0.449 J/(g·°C)Tmetal = 160 °Cmwater = 200 gTwater = 19 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
Tf​ = ?Copperm = 200 gT = 180 °Cc = 0.385 J/(g·°C)Waterm = 300 gT = 21 °Cc = 4.18 J/(g·°C)

A 200 g block of copper (c = 0.385 J/(g·°C)) at 180 °C is dropped into 300 g of water (c = 4.18 J/(g·°C)) at 21 °C in an insulated cup. Find the final temperature Tf.

mmetal = 200 gcmetal = 0.385 J/(g·°C)Tmetal = 180 °Cmwater = 300 gTwater = 21 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
H10 g CH3​OH2CH3​OH + 3O₂reactants2CO₂ + 4H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 10 g of CH3OH (M = 32.04 g/mol) burns completely: 2CH3OH + 3O₂ → 2CO₂ + 4H₂O(l). Give q as a positive number.

ΔH°f(CH3OH) = −238.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ
6.Hard
H100 g C6​H12​O6​C6​H12​O6​ + 6O₂reactants6CO₂ + 6H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 100 g of C6H12O6 (M = 180.16 g/mol) burns completely: C6H12O6 + 6O₂ → 6CO₂ + 6H₂O(l). Give q as a positive number.

ΔH°f(C6H12O6) = −1274 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ

Answer key

  1. 1. q = 44.94 kJ
  2. 2. q = 137.9 kJ
  3. 3. Tf = 35.69 °C
  4. 4. Tf = 30.2 °C
  5. 5. q = 226.7 kJ
  6. 6. q = 1555 kJ

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