Calorimetry & enthalpy worksheet with answers

Free printable Calorimetry & enthalpy worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
waterm = 100 gq = 20 kJΔT = ?

20 kJ of heat is added to 100 g of water (c = 4.18 J/(g·°C)). Find the temperature rise ΔT.

q = 20 kJm = 100 gc = 4.18 J/(g·°C)
ΔT = °C
2.Easy
waterm = 500 gT1​ = 16 °C → T2​ = 45 °Cq = ?

How much heat q is needed to warm 500 g of water from 16 °C to 45 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 500 gT1 = 16 °CT2 = 45 °Cc = 4.18 J/(g·°C)
q = kJ
3.Medium
Tf​ = ?Copperm = 50 gT = 160 °Cc = 0.385 J/(g·°C)Waterm = 100 gT = 15 °Cc = 4.18 J/(g·°C)

A 50 g block of copper (c = 0.385 J/(g·°C)) at 160 °C is dropped into 100 g of water (c = 4.18 J/(g·°C)) at 15 °C in an insulated cup. Find the final temperature Tf.

mmetal = 50 gcmetal = 0.385 J/(g·°C)Tmetal = 160 °Cmwater = 100 gTwater = 15 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
Tf​ = ?Aluminiumm = 100 gT = 180 °Cc = 0.897 J/(g·°C)Waterm = 250 gT = 19 °Cc = 4.18 J/(g·°C)

A 100 g block of aluminium (c = 0.897 J/(g·°C)) at 180 °C is dropped into 250 g of water (c = 4.18 J/(g·°C)) at 19 °C in an insulated cup. Find the final temperature Tf.

mmetal = 100 gcmetal = 0.897 J/(g·°C)Tmetal = 180 °Cmwater = 250 gTwater = 19 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
HC6​H12​O6​ + 6O₂reactants6CO₂ + 6H₂O(l)productsΔH° = ?

Use the standard enthalpies of formation to find ΔH° for the reaction C6H12O6 + 6O₂ → 6CO₂ + 6H₂O(l).

ΔH°f(C6H12O6) = −1274 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
ΔH° = kJ
6.Hard
H50 g CH3​OH2CH3​OH + 3O₂reactants2CO₂ + 4H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 50 g of CH3OH (M = 32.04 g/mol) burns completely: 2CH3OH + 3O₂ → 2CO₂ + 4H₂O(l). Give q as a positive number.

ΔH°f(CH3OH) = −238.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ

Answer key

  1. 1. ΔT = 47.85 °C
  2. 2. q = 60.61 kJ
  3. 3. Tf = 21.38 °C
  4. 4. Tf = 31.73 °C
  5. 5. ΔH° = −2802 kJ
  6. 6. q = 1134 kJ

Full step-by-step solutions: practise this topic on examproblems.com.