Calorimetry & enthalpy worksheet with answers

Free printable Calorimetry & enthalpy worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
waterm = 1000 gT1​ = 23 °C → T2​ = 40 °Cq = ?

How much heat q is needed to warm 1000 g of water from 23 °C to 40 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 1000 gT1 = 23 °CT2 = 40 °Cc = 4.18 J/(g·°C)
q = kJ
2.Easy
waterm = 300 gT1​ = 24 °C → T2​ = 40 °Cq = ?

How much heat q is needed to warm 300 g of water from 24 °C to 40 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.

m = 300 gT1 = 24 °CT2 = 40 °Cc = 4.18 J/(g·°C)
q = kJ
3.Medium
Tf​ = ?Aluminiumm = 75 gT = 180 °Cc = 0.897 J/(g·°C)Waterm = 100 gT = 22 °Cc = 4.18 J/(g·°C)

A 75 g block of aluminium (c = 0.897 J/(g·°C)) at 180 °C is dropped into 100 g of water (c = 4.18 J/(g·°C)) at 22 °C in an insulated cup. Find the final temperature Tf.

mmetal = 75 gcmetal = 0.897 J/(g·°C)Tmetal = 180 °Cmwater = 100 gTwater = 22 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
Tf​ = ?Zincm = 50 gT = 180 °Cc = 0.388 J/(g·°C)Waterm = 250 gT = 15 °Cc = 4.18 J/(g·°C)

A 50 g block of zinc (c = 0.388 J/(g·°C)) at 180 °C is dropped into 250 g of water (c = 4.18 J/(g·°C)) at 15 °C in an insulated cup. Find the final temperature Tf.

mmetal = 50 gcmetal = 0.388 J/(g·°C)Tmetal = 180 °Cmwater = 250 gTwater = 15 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
H10 g CH3​OH2CH3​OH + 3O₂reactants2CO₂ + 4H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 10 g of CH3OH (M = 32.04 g/mol) burns completely: 2CH3OH + 3O₂ → 2CO₂ + 4H₂O(l). Give q as a positive number.

ΔH°f(CH3OH) = −238.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ
6.Hard
H100 g C4​H10​2C4​H10​ + 13O₂reactants8CO₂ + 10H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 100 g of C4H10 (M = 58.12 g/mol) burns completely: 2C4H10 + 13O₂ → 8CO₂ + 10H₂O(l). Give q as a positive number.

ΔH°f(C4H10) = −125.6 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ

Answer key

  1. 1. q = 71.06 kJ
  2. 2. q = 20.06 kJ
  3. 3. Tf = 43.9 °C
  4. 4. Tf = 18.01 °C
  5. 5. q = 226.7 kJ
  6. 6. q = 4951 kJ

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