Calorimetry & enthalpy worksheet with answers

Free printable Calorimetry & enthalpy worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
waterm = 300 gq = 35 kJΔT = ?

35 kJ of heat is added to 300 g of water (c = 4.18 J/(g·°C)). Find the temperature rise ΔT.

q = 35 kJm = 300 gc = 4.18 J/(g·°C)
ΔT = °C
2.Easy
waterm = 300 gq = 30 kJΔT = ?

30 kJ of heat is added to 300 g of water (c = 4.18 J/(g·°C)). Find the temperature rise ΔT.

q = 30 kJm = 300 gc = 4.18 J/(g·°C)
ΔT = °C
3.Medium
Tf​ = ?Ironm = 50 gT = 80 °Cc = 0.449 J/(g·°C)Waterm = 150 gT = 18 °Cc = 4.18 J/(g·°C)

A 50 g block of iron (c = 0.449 J/(g·°C)) at 80 °C is dropped into 150 g of water (c = 4.18 J/(g·°C)) at 18 °C in an insulated cup. Find the final temperature Tf.

mmetal = 50 gcmetal = 0.449 J/(g·°C)Tmetal = 80 °Cmwater = 150 gTwater = 18 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
Tf​ = ?Ironm = 100 gT = 130 °Cc = 0.449 J/(g·°C)Waterm = 250 gT = 20 °Cc = 4.18 J/(g·°C)

A 100 g block of iron (c = 0.449 J/(g·°C)) at 130 °C is dropped into 250 g of water (c = 4.18 J/(g·°C)) at 20 °C in an insulated cup. Find the final temperature Tf.

mmetal = 100 gcmetal = 0.449 J/(g·°C)Tmetal = 130 °Cmwater = 250 gTwater = 20 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
H50 g C4​H10​2C4​H10​ + 13O₂reactants8CO₂ + 10H₂O(l)productsq = ?

Use the standard enthalpies of formation to find the heat q released when 50 g of C4H10 (M = 58.12 g/mol) burns completely: 2C4H10 + 13O₂ → 8CO₂ + 10H₂O(l). Give q as a positive number.

ΔH°f(C4H10) = −125.6 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
q = kJ
6.Hard
H2CH3​OH + 3O₂reactants2CO₂ + 4H₂O(l)productsΔH° = ?

Use the standard enthalpies of formation to find ΔH° for the reaction 2CH3OH + 3O₂ → 2CO₂ + 4H₂O(l).

ΔH°f(CH3OH) = −238.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
ΔH° = kJ

Answer key

  1. 1. ΔT = 27.91 °C
  2. 2. ΔT = 23.92 °C
  3. 3. Tf = 20.14 °C
  4. 4. Tf = 24.53 °C
  5. 5. q = 2475 kJ
  6. 6. ΔH° = −1453 kJ

Full step-by-step solutions: practise this topic on examproblems.com.