How much heat q is needed to warm 750 g of water from 14 °C to 90 °C? The specific heat of water is 4.18 J/(g·°C). Give the answer in kJ.
Calorimetry & enthalpy worksheet with answers
1.Easy
m = 750 gT1 = 14 °CT2 = 90 °Cc = 4.18 J/(g·°C)
q = kJ
2.Easy
5 kJ of heat is added to 750 g of water (c = 4.18 J/(g·°C)). Find the temperature rise ΔT.
q = 5 kJm = 750 gc = 4.18 J/(g·°C)
ΔT = °C
3.Medium
A 100 g block of iron (c = 0.449 J/(g·°C)) at 160 °C is dropped into 200 g of water (c = 4.18 J/(g·°C)) at 20 °C in an insulated cup. Find the final temperature Tf.
mmetal = 100 gcmetal = 0.449 J/(g·°C)Tmetal = 160 °Cmwater = 200 gTwater = 20 °Ccwater = 4.18 J/(g·°C)
Tf = °C
4.Medium
A 150 g block of lead (c = 0.129 J/(g·°C)) at 180 °C is dropped into 400 g of water (c = 4.18 J/(g·°C)) at 21 °C in an insulated cup. Find the final temperature Tf.
mmetal = 150 gcmetal = 0.129 J/(g·°C)Tmetal = 180 °Cmwater = 400 gTwater = 21 °Ccwater = 4.18 J/(g·°C)
Tf = °C
5.Hard
Use the standard enthalpies of formation to find ΔH° for the reaction C6H12O6 + 6O₂ → 6CO₂ + 6H₂O(l).
ΔH°f(C6H12O6) = −1274 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
ΔH° = kJ
6.Hard
Use the standard enthalpies of formation to find ΔH° for the reaction C2H5OH + 3O₂ → 2CO₂ + 3H₂O(l).
ΔH°f(C2H5OH) = −277.7 kJ/molΔH°f(CO₂) = −393.5 kJ/molΔH°f(H₂O, l) = −285.8 kJ/molΔH°f(O₂) = 0
ΔH° = kJ
Answer key
- 1. q = 238.3 kJ
- 2. ΔT = 1.595 °C
- 3. Tf = 27.14 °C
- 4. Tf = 22.82 °C
- 5. ΔH° = −2802 kJ
- 6. ΔH° = −1367 kJ
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