Chemical equilibrium worksheet with answers

Free printable Chemical equilibrium worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
H2​0.2mol/L+I2​0.05mol/L⇌2HI0.12mol/LKc​ = ?

For the reaction H2 + I2 ⇌ 2HI, the equilibrium concentrations are [H2] = 0.2 mol/L, [I2] = 0.05 mol/L, [HI] = 0.12 mol/L. Find the equilibrium constant Kc.

[H2] = 0.2[I2] = 0.05[HI] = 0.12
Kc =
2.Easy
2SO2​0.3mol/L+O2​0.08mol/L⇌2SO3​0.5mol/LKc​ = ?

For the reaction 2SO2 + O2 ⇌ 2SO3, the equilibrium concentrations are [SO2] = 0.3 mol/L, [O2] = 0.08 mol/L, [SO3] = 0.5 mol/L. Find the equilibrium constant Kc.

[SO2] = 0.3[O2] = 0.08[SO3] = 0.5
Kc =
3.Medium
H2​I2​HII0.10.10C−x−x+2xE0.1 − x0.1 − x2x

0.1 mol/L of H₂ and 0.1 mol/L of I₂ are put in a container and react: H₂ + I₂ ⇌ 2HI, with Kc = 16. Find the equilibrium concentration [H2].

[H₂]₀ = [I₂]₀ = 0.1 mol/LKc = 16
[H2] = mol/L
4.Medium
H2​I2​HII0.80.80C−x−x+2xE0.8 − x0.8 − x2x

0.8 mol/L of H₂ and 0.8 mol/L of I₂ are put in a container and react: H₂ + I₂ ⇌ 2HI, with Kc = 49. Find the equilibrium concentration [H2].

[H₂]₀ = [I₂]₀ = 0.8 mol/LKc = 49
[H2] = mol/L
5.Hard
PCl5​PCl3​Cl2​I0.500C−x+x+xE0.5 − xxx

PCl₅ decomposes: PCl₅ ⇌ PCl₃ + Cl₂, with Kc = 0.08 at the reaction temperature. A container starts with 0.5 mol/L of PCl₅ only. Find the equilibrium concentration [Cl2].

[PCl₅]₀ = 0.5 mol/LKc = 0.08
[Cl2] = mol/L
6.Hard
PCl5​PCl3​Cl2​I1.500C−x+x+xE1.5 − xxx

PCl₅ decomposes: PCl₅ ⇌ PCl₃ + Cl₂, with Kc = 0.05 at the reaction temperature. A container starts with 1.5 mol/L of PCl₅ only. Find the equilibrium concentration [Cl2].

[PCl₅]₀ = 1.5 mol/LKc = 0.05
[Cl2] = mol/L

Answer key

  1. 1. Kc = 1.44
  2. 2. Kc = 34.72
  3. 3. [H2] = 0.03333 mol/L
  4. 4. [H2] = 0.1778 mol/L
  5. 5. [Cl2] = 0.164 mol/L
  6. 6. [Cl2] = 0.25 mol/L

Full step-by-step solutions: practise this topic on examproblems.com.