Chemical equilibrium worksheet with answers

Free printable Chemical equilibrium worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
CO0.4mol/L+H2​O0.4mol/L⇌CO2​0.1mol/L+H2​0.05mol/LKc​ = ?

For the reaction CO + H2O ⇌ CO2 + H2, the equilibrium concentrations are [CO] = 0.4 mol/L, [H2O] = 0.4 mol/L, [CO2] = 0.1 mol/L, [H2] = 0.05 mol/L. Find the equilibrium constant Kc.

[CO] = 0.4[H2O] = 0.4[CO2] = 0.1[H2] = 0.05
Kc =
2.Easy
H2​0.12mol/L+I2​0.15mol/L⇌2HI0.3mol/LKc​ = ?

For the reaction H2 + I2 ⇌ 2HI, the equilibrium concentrations are [H2] = 0.12 mol/L, [I2] = 0.15 mol/L, [HI] = 0.3 mol/L. Find the equilibrium constant Kc.

[H2] = 0.12[I2] = 0.15[HI] = 0.3
Kc =
3.Medium
H2​I2​HII0.20.20C−x−x+2xE0.2 − x0.2 − x2x

0.2 mol/L of H₂ and 0.2 mol/L of I₂ are put in a container and react: H₂ + I₂ ⇌ 2HI, with Kc = 64. Find the equilibrium concentration [H2].

[H₂]₀ = [I₂]₀ = 0.2 mol/LKc = 64
[H2] = mol/L
4.Medium
H2​I2​HII0.250.250C−x−x+2xE0.25 − x0.25 − x2x

0.25 mol/L of H₂ and 0.25 mol/L of I₂ are put in a container and react: H₂ + I₂ ⇌ 2HI, with Kc = 4. Find the equilibrium concentration [HI].

[H₂]₀ = [I₂]₀ = 0.25 mol/LKc = 4
[HI] = mol/L
5.Hard
PCl5​PCl3​Cl2​I1.500C−x+x+xE1.5 − xxx

PCl₅ decomposes: PCl₅ ⇌ PCl₃ + Cl₂, with Kc = 0.08 at the reaction temperature. A container starts with 1.5 mol/L of PCl₅ only. Find the equilibrium concentration [Cl2].

[PCl₅]₀ = 1.5 mol/LKc = 0.08
[Cl2] = mol/L
6.Hard
PCl5​PCl3​Cl2​I100C−x+x+xE1 − xxx

PCl₅ decomposes: PCl₅ ⇌ PCl₃ + Cl₂, with Kc = 0.2 at the reaction temperature. A container starts with 1 mol/L of PCl₅ only. Find the equilibrium concentration [PCl5].

[PCl₅]₀ = 1 mol/LKc = 0.2
[PCl5] = mol/L

Answer key

  1. 1. Kc = 0.03125
  2. 2. Kc = 5
  3. 3. [H2] = 0.04 mol/L
  4. 4. [HI] = 0.25 mol/L
  5. 5. [Cl2] = 0.3087 mol/L
  6. 6. [PCl5] = 0.6417 mol/L

Full step-by-step solutions: practise this topic on examproblems.com.