Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 0.4 mvmax​ = ?

A 0.8 kg stone is whirled in a horizontal circle of radius 0.4 m on a smooth, level table, held by a string that breaks at a tension of 200 N. Find the highest speed vmax the stone can have.

m = 0.8 kgr = 0.4 mTmax = 200 N
vmax = m/s
2.Easy
r = 0.6 mvmax​ = ?

A 1.2 kg stone is whirled in a horizontal circle of radius 0.6 m on a smooth, level table, held by a string that breaks at a tension of 120 N. Find the highest speed vmax the stone can have.

m = 1.2 kgr = 0.6 mTmax = 120 N
vmax = m/s
3.Medium
r = 105 mvmax​ = ?

A car takes a flat curve of radius 105 m. The coefficient of static friction between tyres and road is 0.6. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 105 mμs = 0.6g = 9.81 m/s²
vmax = m/s
4.Medium
r = 20 mvmax​ = ?

A car drives over the top of a hump in the road, which is a circular arc of radius 20 m. Use g = 9.81 m/s². Above what speed vmax do the wheels leave the road at the top?

r = 20 mg = 9.81 m/s²
vmax = m/s
5.Hard
r = 0.8 m10 m/svtop​ = ?

A 1.2 kg ball on a light string 0.8 m long is swung in a vertical circle. At the lowest point its speed is 10 m/s. Ignore air resistance and use g = 9.81 m/s². Find the tension Ttop in the string at the highest point.

m = 1.2 kgr = 0.8 mvbottom = 10 m/sg = 9.81 m/s²
Ttop = N
6.Hard
r = 0.8 mv = ?

A ball on a string 0.8 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 0.8 mg = 9.81 m/s²
vmin = m/s

Answer key

  1. 1. vmax = 10 m/s
  2. 2. vmax = 7.746 m/s
  3. 3. vmax = 24.86 m/s
  4. 4. vmax = 14.01 m/s
  5. 5. Ttop = 91.14 N
  6. 6. vmin = 2.801 m/s

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