Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 1.5 mvmax​ = ?

A 0.8 kg stone is whirled in a horizontal circle of radius 1.5 m on a smooth, level table, held by a string that breaks at a tension of 90 N. Find the highest speed vmax the stone can have.

m = 0.8 kgr = 1.5 mTmax = 90 N
vmax = m/s
2.Easy
r = 100 m13 m/sF = ?

A 1400 kg car drives around a flat curve of radius 100 m at a constant 13 m/s. Find the inward (centripetal) force Fc needed.

m = 1400 kgv = 13 m/sr = 100 m
Fc = N
3.Medium
r = 25 mvmax​ = ?

A car takes a flat curve of radius 25 m. The coefficient of static friction between tyres and road is 0.3. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 25 mμs = 0.3g = 9.81 m/s²
vmax = m/s
4.Medium
θ = 18°to centrev = ?

A curve of radius 240 m is banked at 18°. At what speed v can a car take it with no friction needed at all? Use g = 9.81 m/s².

r = 240 mθ = 18°g = 9.81 m/s²
v = m/s
5.Hard
θ = 12°to centrevmin​ = ?

A curve of radius 120 m is banked at 12°, and the coefficient of static friction between tyres and road is 0.15. Use g = 9.81 m/s². Find the lowest speed vmin at which a car can take the curve without sliding down the bank.

r = 120 mθ = 12°μs = 0.15g = 9.81 m/s²
vmin = m/s
6.Hard
r = 1.4 mv = 5 m/s

A 1.3 kg ball on a string 1.4 m long is swung in a vertical circle. At the lowest point it moves at 5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.3 kgr = 1.4 mv = 5 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. vmax = 12.99 m/s
  2. 2. Fc = 2366 N
  3. 3. vmax = 8.578 m/s
  4. 4. v = 27.66 m/s
  5. 5. vmin = 8.448 m/s
  6. 6. T = 35.97 N

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