Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 0.6 mvmax​ = ?

A 0.7 kg stone is whirled in a horizontal circle of radius 0.6 m on a smooth, level table, held by a string that breaks at a tension of 50 N. Find the highest speed vmax the stone can have.

m = 0.7 kgr = 0.6 mTmax = 50 N
vmax = m/s
2.Easy
r = 1.8 mvmax​ = ?

A 1 kg stone is whirled in a horizontal circle of radius 1.8 m on a smooth, level table, held by a string that breaks at a tension of 70 N. Find the highest speed vmax the stone can have.

m = 1 kgr = 1.8 mTmax = 70 N
vmax = m/s
3.Medium
r = 90 mvmax​ = ?

A car takes a flat curve of radius 90 m. The coefficient of static friction between tyres and road is 0.3. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 90 mμs = 0.3g = 9.81 m/s²
vmax = m/s
4.Medium
r = 55 mvmax​ = ?

A car takes a flat curve of radius 55 m. The coefficient of static friction between tyres and road is 0.7. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 55 mμs = 0.7g = 9.81 m/s²
vmax = m/s
5.Hard
r = 0.7 mv = ?

A ball on a string 0.7 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 0.7 mg = 9.81 m/s²
vmin = m/s
6.Hard
r = 0.9 mv = 6 m/s

A 1.1 kg ball on a string 0.9 m long is swung in a vertical circle. At the lowest point it moves at 6 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.1 kgr = 0.9 mv = 6 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. vmax = 6.547 m/s
  2. 2. vmax = 11.22 m/s
  3. 3. vmax = 16.27 m/s
  4. 4. vmax = 19.43 m/s
  5. 5. vmin = 2.62 m/s
  6. 6. T = 54.79 N

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